135 - 5 ( x + 4 ) = 35

        5 ( x + 4 ) = 135 - 35

        5 ( x + 4 ) = 100

           ( x + 4 ) = 100 : 5

           ( x + 4 ) = 20

             x         = 20 - 4

             x         = 16

135 - 5( x + 4 ) = 35

135 - 5x - 20 = 35

-5x = 35 + 20 - 135

-5x = 150

-x = 150 : 5

x = -30

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135-5(x+4)=35

       5(x+4)=135-35

       5(x+4)=100

          x+4=100:5

           x+4=20

               x=20-4

               x=16

135- 5(x+4)= 35

        5(x+4)=135- 35

        5(x+4)=100

           x+4=100: 5

           x+4=20

               x=20-4

               x=16

a) \(5x-65=5.3^2 \\ 5x-65=45\\5x=45+65\\5x=110\\x=22\)

b) \(200-(2x+6)=4^3\\2x+6=200-4^3\\2x+6=136\\2x=130\\x=65\)

c) \(2(x-51)=2.2^3+20\\2(x-51)=16+20\\2(x-51)=36\\x-51=18\\x=51+18=69\)

d) \(135-5(x+4)=35\\5(x+4)=135-45\\5(x-4)=90\\x-4=18\\x=18+4=22\)

e) \((2x-4)(15-3x)=0\\2(x-2).3(5-x)=0\\(x-2)(5-x)=0\\ \left[ \begin{array}{l}x-2=0\\5-x=0\end{array} \right. \\ \left[ \begin{array}{l}x=2\\x=5\end{array} \right.\)

f) \(2^{x+1} . 2^{2014}=2^{2016} \\ (2^{x+1} . 2^{2014}):2^{2014}=2^{2016} :2^{2014} \\ 2^{x=1}=2^{2016-2014} \\2^{x+1}=2^2\\x+1=2\\x=1\)

g) \(15+(x-1)^3=43\\(x-1)^3=15-42\\(x-1)^3=-27\\(x-1)^3=(-3)^3\\x-1=-3\\x=-2\)

h) \(15-x=17+(-9)\\15-x=17-9\\15-x=8\\x=15-8\\x=7\)

i) \(|x-5|=|-7|+|-4|\\|x-5|=7+4\\|x-5|=11\\ \left[ \begin{array}{l}x-5=11\\x-5=-11\end{array} \right. \\ \left[ \begin{array}{l}x=16\\x=-6\end{array} \right.\)

k) \(|x-3|-12=-9+|-7|\\|x-3|-12=-9+7\\|x-3|-12=-2\\|x-3|=10 \\ \left[ \begin{array}{l}x-3=10\\x-3=-10\end{array} \right. \\ \left[ \begin{array}{l}x=13\\x=-7\end{array} \right.\)

Lời giải:

1. $(x+2)-2=0$

$x+2=2$

$x=0$

2.

$(x+3)+1=7$

$x+3=7-1=6$

$x=6-3=3$

3.

$(3x-4)+4=12$

$3x-4+4=12$

$3x=12$

$x=12:3=4$

4.

$(5x+4)-1=13$

$5x+4=13+1=14$

$5x=14-4=10$

$x=10:5=2$

5.

$(4x-8)-3=5$

$4x-8=5+3=8$

$4x=8+8=16$

$x=16:4=4$

6.

$3+(x-5)=7$

$x-5=7-3=4$

$x=4+5=9$

7.

$8-(2x-4)=2$

$2x-4=8-2=6$

$2x=6+4=10$

$x=10:2=5$

8.

$7+(5x+2)=14$

$5x+2=14-7=7$

$5x=7-2=5$

$x=5:5=1$

9.

$5-(3x-11)=1$

$3x-11=5-1=4$

$3x=11+4=15$

$x=15:3=5$

10.

$16-(8x+2)=6$

$8x+2=16-6=10$

$8x=10-2=8$

$x=8:8=1$

a) 135 - 5(x + 4) = 35 

<=> 135 - 5x - 20 = 35

<=> 115 - 5x = 35

<=> 5x = 115 - 35 

<=> 5x = 80 

<=> x = 16

b) 25 + 3 (x - 8) = 106

=>        3 ( x - 8) = 106 - 25

=>        3 ( x - 8) = 81

=>           ( x - 8) = 81: 3

=>             x - 8  = 27

=>             x       = 27 + 8

=>             x       = .......

a)  135-5(x+4)=35

5(x+4)=135-35

5(x+4)=100

x+4=100:5

x+4=20

x=20-4

x=16

b)25+3(x-8)=106

  3(x-8)=106-25

3(x-8)=81

x-8=81:3

x-8=27

x=27+8

x=35

a) Thiếu điều kiện nha em mời em sửa lại

140 : ( x - 8 ) = 7 

          x - 8   = 140 : 7 = 20

               x   = 20 + 8 

               x   = 28

* 140 : (X-8)=7

X-8=140:7

X-8=20

x=20+8

x=28

Vậy X =28

* 4(X+41)=400

X+41=400:4

X+41=100

X=100-41

X=59

Vậy x=59

*135-5(X+4)135

5(X+4)=135-35

5(X+4)=100

X+4=100:5

X+4=20

X=20-4

X=16

Vậy X = 16

c) 135 - | 9 - x | = 3

             | 9 - x | = 135 - 3

             | 9 - x | = 132

        =>  9 - x = 132 

                   x = 9 - 132

                   x = 123

      hoặc 9 - x  = - 132

                    x = 9 - ( - 132 )

                    x = 9 + 132

                    x = 141

Vậy ..................

c) 135 - | 9 - x | = 35

\(2\left(x-1\right)+3\left(x-2\right)=x-4\)

\(2x-2+3x-6=x-4\)

\(5x-8=x-4\)

\(5x-8-x+4=0\)

\(4x-4=0\)

\(4x=4\)

\(x=1\)

\(3\left(4-x\right)-2\left(x-1\right)=x+20\)

\(12-x-2x+2=x+20\)

\(14-3x=x+20\)

\(14-3x-x-20=0\)

\(-6-4x=0\)

\(4x=-6\)

\(x=-\frac{3}{2}\)

\(\left|2x+3\right|=5\)

\(\Rightarrow\orbr{\begin{cases}2x=2\\2x=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-4\end{cases}}}\)

a) \(\left|x-2\right|-12=-1\)

\(\Leftrightarrow\left|x-2\right|=11\)

TH1 : \(x-2=11\)

\(\Leftrightarrow x=13\)

TH2 : \(x-2=-11\)

\(\Leftrightarrow x=-9\)

Vậy \(x\in\left\{13;-9\right\}\)

b) \(135-\left|9-x\right|=35\)

\(\Leftrightarrow\left|9-x\right|=100\)

TH1 : \(9-x=100\)

\(\Leftrightarrow x=-91\)

TH2 :\(9-x=-100\)

\(\Leftrightarrow x=109\)

Vậy \(x\in\left\{-81;109\right\}\)

c) \(\left|2x+3\right|=4\)

TH1 : \(2x+3=4\)

\(\Leftrightarrow2x=1\)

\(\Leftrightarrow x=\frac{1}{2}\)

TH2 : \(2x+3=-4\)

\(\Leftrightarrow2x=-7\)

\(\Leftrightarrow x=-\frac{7}{2}\)

Vậy \(x\in\left\{\frac{1}{2};-\frac{7}{2}\right\}\)