a) 20042 - 16

= 20042 - 42

= (2004 - 4)(2004 + 4)

= 2000.2008

= 4016000

b) 10,2.9,8 - 9,8.0,2 + 10,2.0,2

= 9,8(10,2 - 0,2) + 2,04

= 9,8.10 + 2,04

= 98 + 2,04

= 100,04

a) Đề có trục trặc

\(20042-16=20026\)

b) \(10,2.9,8-9,8.0,2+10,2.10,2-10,2.0,2\)

\(=9,8\left(10,2-0,2\right)+10,2\left(10,2-0,2\right)\)

\(=9,8.10+10,2.10=10\left(9,8+10,2\right)=10.20=200\)

a) 2004² - 16

= 2004² - 4²

= (2004 - 4)(2004 + 4)

= 2000.2008

= 4016000

b) 892² + 892.216 + 108²

= 892² + 2.892.108 + 108²

= (892 + 108)²

= 1000²

= 1000000

c) 10,2.9,8 - 9,8.0,2 + 10,2.0,2

= 9,8(10,2 - 0,2) + 2,04

= 9,8.10 + 2,04

= 98 + 2,04

= 100,04

d) 36² + 26² - 52.36

= 36² - 2.36.26 + 26²

= (36 - 26)²

= 10²

= 100

\(A=2004^2-16=\left(2004-4\right)\left(2004+4\right)=2000\cdot2008=4016000\)

\(B=892^2+892\cdot216+108^2=892^2+2\cdot892\cdot108+108^2=\left(892+108\right)^2=1000^2=1000000\)

\(C=10,2\cdot9,8-9,8\cdot0,2+10,2^2-10,2\cdot0,2\)

\(=9,8\left(10,2-0,2\right)+10,2\left(10,2-0,2\right)\)

\(=10\cdot\left(9,8+10,2\right)=10\cdot20=200\)

\(D=36^2+26^2-52\cdot36=\left(36-26\right)^2=10^2=100\)

\(E=105^2-25=\left(105-5\right)\left(105+5\right)=100\cdot110=11000\)

\(F=73^2-27^2=\left(73-27\right)\left(73+27\right)=46\cdot100=4600\)

A. 2004²-16=2004²-4²=(2004-4)(2004+4)=2000.2008=2016000
B. 892²+892.216+108²= 892²+2.892.108+108²=(892+108)²=1000²=1000000
C.Khó nhìn quá
D.36²+26²-52.36=36²-2.36.26+26²=(36-16)²=20²=400
E.105²-25=(105-5)(105+5)=100.110=11000
F. 73²-27²=(73-27)(73+27)=46.100=4600

a: \(=\left(892+108\right)^2=1000^2=1000000\)

b: \(=\left(36-26\right)^2=10^2=100\)

c: \(=9.8\cdot10+10.2\cdot10=20\cdot10=200\)

Lời giải:

\(892^2+892.216+108^2=892^2+2.892.108+108^2\)

\(=(892+108)^2=1000^2=1000000\)

-------

\(10,2.9,8-9.8.0,2+10,2^2-10,2.0,2\)

\(=9,8(10,2-0,2)+10,2(10,2-0,2)\)

\(=9,8.10+10,2.10=10(9,8+10,2)=10.20=200\)

--------

\(36^2+26^2-52.36=36^2-2.36.26+26^2\)

\(=(36-26)^2=10^2=100\)

\(=9,8\cdot10+10,22-2,04=106,18\)

\(=9,8\cdot10+10,22-2,04\)

=0,98+10,22-2,04

=9,16