\(\left(125^3.7^4-5^9.49^2\right):2005^{2006}\)

\(=\left[\left(5^3\right)^3.7^4-5^9.\left(7^2\right)^2\right]:2005^{2006}\)

\(=\left(5^9.7^4-5^9.7^4\right):2005^{2006}\)

\(=0:2005^{2006}\)

\(=0\)

(125³ . 7⁴ - 5⁹ .49²) : 2005²⁰⁰⁶

= (5^9 * 7^4 - 5^9 * 7^4) :2005^2006

= 0 : 2005^2006

= 0

---

\(\left(125^3.7^4-5^9+49^2\right):2005^{2006}\)

\(=\left(5^9.7^4-5^9.7^4\right):2005^{2006}\)

\(=0:2005^{2006}\)

\(=0\)

\(125^3.7^4-5^9.49^2:2005^{2006}\)

= \(\left(5^3\right)^3.7^4-5^9.\left(7^2\right)^2:2005^{2006}\)

= \(5^9.7^4-5^9.7^4:2005^{2006}\)

(MK nghĩ phải có dấu ngoặc)

\(\left(25^3.7^4-5^9.49^2\right):2005^{2006}\) mới đúng

HỌC TỐT

......................?

mik ko biết

mong bn thông cảm !$$%

Ai nhanh mình k

a, 5/3*4/7*3/5*7/8

= (5/3*3/5)*(4/7*7/8)

= 1*1/2

=1/2

b, 2006*125+1000/126*2005-880

= (2005+1)*125+1000/126*2005-880

=2005*125+125+1000/126*2005-880

=2005*(125+1000/126)-880+125

=2005*8375/63-880+125

=266537,6984-880+125

=265657,6984+125

=265782,6984

a, \(\frac{4}{7}x\frac{5}{7}+\frac{3}{7}x\frac{5}{6}\)

= ( \(\frac{4}{7}+\frac{3}{7}\)) x \(\frac{5}{7}x\frac{5}{6}\)

= 1 x \(\frac{5}{7}x\frac{5}{6}\)

= \(\frac{5}{7}x\frac{5}{6}\)

= \(\frac{25}{42}\)

Tương tự mấy câu sau cũng làm như thế này

a)=(3/8+10/16)+(7/12+10/24)

=1+1=2

c)=(4/6+14/6)+(7/13+19/13)+(17/9+1/9)

=3+2+2=7