tính C=1/3*5+1/5*7+1/7*9+............+1/(2X+1)(2X+3)=15/93
Những câu hỏi liên quan
1/3 x 5 + 1/5 x 7 + 1/7 x 9+ ... + 1/(2x + 1) x (2x + 3) = 15/93.tinh x
1/3×5 +1/5×7 +.......+1/2x+1×2x+3=15/93
1/3*5+1/5*7+...+1/(2x+1)*(2x+3)=15/93
\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{\left(2x+1\right)\left(2x+3\right)}=\frac{15}{93}\)
\(2\left(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{\left(2x+1\right)\left(2x+3\right)}\right)=2.\frac{15}{93}\)
\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{\left(2x+1\right)\left(2x+3\right)}=\frac{10}{31}\)
\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{2x+1}-\frac{1}{2x+3}=\frac{10}{31}\)
\(\frac{1}{3}-\frac{1}{2x+3}=\frac{10}{31}\)
\(\frac{1}{2x+3}=\frac{1}{93}\)
\(\Rightarrow2x+3=93\)
\(2x=90\)
\(x=\frac{90}{2}=45\)
Vậy \(x=45\)
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Tính:
2/7 + 5/7 8/15 + 6/15 2/9 + 3/9 + 4/9
[ Không cần làm phép tính ]Điền vào ô trống <,>,= :
3/5 + 1/5 ... 1/5 + 3/5
7/9 + 1/9 ... 7/9 + 1/9 + 1/9
3/7 + 2/7 ... 3/7 + 4/7
1/5 + 3/5 ... 2/5 + 3/5
Tính:
2/7 + 5/7=1
8/15 + 6/15 =14/15
2/9 + 3/9 + 4/9=9/9=1
[ Không cần làm phép tính ]Điền vào ô trống <,>,= :
3/5 + 1/5 = 1/5 + 3/5
7/9 + 1/9 < 7/9 + 1/9 + 1/9
3/7 + 2/7 < 3/7 + 4/7
1/5 + 3/5 < 2/5 + 3/5
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Tính:
2/7 + 5/7=1
8/15 + 6/15 =14/15
2/9 + 3/9 + 4/9=9/9=1
[ Không cần làm phép tính ]Điền vào ô trống <,>,= :
3/5 + 1/5 = 1/5 + 3/5
7/9 + 1/9 < 7/9 + 1/9 + 1/9
3/7 + 2/7 < 3/7 + 4/7
1/5 + 3/5 < 2/5 + 3/5
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Tìm x biết
a) x/2008- 1/10-1/15 -....-1/120=5/8
b) 1/3*5+1/5*7 +.....+1/(2x+1)*(2x+3)= 15/93
Tìm x
a)7/x+4/5×9+4/9×13+...+4/41×45=29/93
b)x+2/1×3+2/3×5+...+2/49×51=5/17
c)1/4-1/2×4-1/4×6-...-1/2x(2x+2)=23/176
Tìm x biết \(\frac{1}{3\times5}+\frac{1}{5\times7}+\frac{1}{7\times9}+...+\frac{1}{\left(2x+1\right)\left(2x+3\right)}=\frac{15}{93}\)
\(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+.....+\frac{1}{\left(2x+1\right).\left(2x+3\right)}=\frac{15}{93}\)
\(2.\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+.....+\frac{1}{\left(2x+1\right).\left(2x+3\right)}\right)=2.\frac{15}{93}\)
\(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+.....+\frac{2}{\left(2x+1\right).\left(2x+3\right)}=\frac{10}{31}\)
\(\frac{1}{3}-\frac{1}{2x+3}=\frac{10}{31}\)
\(\frac{1}{2x+3}=\frac{1}{3}-\frac{10}{31}\)
\(\frac{1}{2x+3}=\frac{1}{93}\)
\(\Rightarrow2x+3=93\)
\(\Rightarrow2x=90\)
\(\Rightarrow x=45\)
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Tìm x biet:
a,5/2x+x=32/15
b,x-7/2x=-32/15
c,-7/3x-7/4x+11/3=18/5
d,-5/6-3x=2/3
e,2x-5/9=-2/3
f,1/2-2/3x=7/12
g,7-|2x-3|=4
h,(19x+2.5^2):14=(13-8)^2-4^2
i,3/4x-2/3=2/7.1/6+5/7.1/6
k,(x+1/2).(2/3-2x)=0
l,x/2013-1/10-1/15-1/21-........-1/120=5/8
a)7/x+4/5×9+4/9×13+...+4/41×45=29/93
b)x+2/1×3+2/3×5+...+2/49×51=5/17
c)1/4-1/2×4-1/4×6-...-1/2x(2x+2)=23/176
Tìm x