a, đk : x khác -1 ; x khác 2 

\(\Rightarrow4x-8=3x+3\Leftrightarrow x=11\left(tm\right)\)

b, đk : x khác 2 ; -2 

\(\Rightarrow\left(x+2\right)^2-8x=0\Leftrightarrow\left(x-2\right)^2=0\Leftrightarrow x=2\left(ktm\right)\)

-> vậy pt vô nghiệm 

c, đk : x khác 3  ; 0 

\(\Rightarrow x-5\left(x-3\right)=3x+7\Leftrightarrow-4x+15=3x+7\Leftrightarrow-7x=-8\Leftrightarrow x=\dfrac{8}{7}\left(tm\right)\)

a)Với \(x\ne-1;x\ne2\)

\(\dfrac{4}{x+1}=\dfrac{3}{x-2}\)

<=>4(x-2)=3(x+1)

<=>4x-8=3x+3

<=>x=11(TM)

b)Với\(x\ne\pm2\)

\(\dfrac{x+2}{2x-4}-\dfrac{4x}{x^2-4}=0\)

<=>\(\dfrac{x+2}{2\left(x-2\right)}-\dfrac{4x}{\left(x+2\right)\left(x-2\right)}=0\)

<=>\(\dfrac{\left(x+2\right)^2-8x}{2\left(x+2\right)\left(x-2\right)}=0\)

<=>\(x^2+4x+4-8x=0\left(Vĩx\ne\pm2\right)\)

<=>\(x^2-4x+4=0\)

<=>\(\left(x-2\right)^2=0\)

<=>x-2=0

<=>x=2(Không thỏa mãn)

c)Với \(x\ne3,x\ne0\)

\(\dfrac{1}{x-3}-\dfrac{5}{x}=\dfrac{3x+7}{x\left(x-3\right)}\)

<=>\(\dfrac{x-5\left(x-3\right)}{x\left(x-3\right)}=\dfrac{3x+7}{x\left(x-3\right)}\)

<=>x-5x+15=3x+7(Vì \(x\ne0,x\ne3\))

<=>7x=8

<=>x=\(\dfrac{8}{7}\left(TM\right)\)

a) (3x + 5)² = 289

Vì \(\sqrt{289}\)= 17

=> 3x + 5 = 17

3x = 17 - 5

3x = 12

x = 12 : 3

x = 4

b) x + (x²)³ = x⁵

x + x⁶ = x⁵

x = x⁵ - x⁶

x = x^-1 = \(\frac{1}{x}\).

2:

a: =>x-1=0 hoặc 3x+1=0

=>x=1 hoặc x=-1/3

b: =>x-5=0 hoặc 7-x=0

=>x=5 hoặc x=7

c: =>\(\left[{}\begin{matrix}x-1=0\\x+5=0\\3x-8=0\end{matrix}\right.\Leftrightarrow x\in\left\{1;-5;\dfrac{8}{3}\right\}\)

d: =>x=0 hoặc x^2-1=0

=>\(x\in\left\{0;1;-1\right\}\)

Bạn tách ra từng câu thoi nhe .

2 mũ x nhân 7=224        (3x+5) mũ 2=289                   phần c mình chịu T-T

2 mũ x=224:7                 (3x+5) mũ 2=17 mũ 2

2 mũ x=32                       3x+5=17

2 mũ 5=32                      3x=17-2

=>x=5                               3x=15

                                         x=15:3

                                         x=5

a )  2^x.7=224

     2^x=224:7

     2^x=32=2⁵

       ^{vậy x= 5}

b)(3X+5)²=289

    (3X+5)²=17²

      ^{=> 3X+5=17}

           ^3X=17-5

           ^3X=12

            ^X=12:3=4

C)3^2x+1.11=2673

     3^2x+1=2673:11

    3^2x+1=243

   3^2x+1=3⁵

  =>2x+1=5

      2x=5-1

    2x= 4

  x=4:2

x=2

Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu

a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14) 

=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84

=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84) 

=> 156 -  56x = 24x - 324 

=>  24x + 56x = 324 + 156 

=> 80x = 480 

=> x = 480 : 80 =  6 

Vậy x = 6 

b, 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1 

=> 15x + 25 - 8x + 12 = 5x + 6x + 36 + 1 

=> (15x - 8x) + (25 + 12) = 11x + 37 

=> 7x + 37 = 11x + 37 

=> 11x - 7x = 0 

=>  x = 0 

5.(x+7)=3.(2-x)

=>5x+35=6-3x

=>5x+3x=6+41

=>8x=47

=>x=47:8=47/8

\(12\left(x-3\right)=5\left(x-1\right)+4\)

\(\Rightarrow12x-36=5x-5+4\)

\(\Rightarrow12x-5x=-5+4+36\)

\(\Rightarrow7x=35\)

\(\Rightarrow x=5\)

\(-6\left(x-7\right)+2\left(x+10\right)=x-18\)

\(-6x+42+2x+20=x-18\)

\(-6x+2x-x=-18-20-42\)

\(-5x=-80\)

\(x=16\)

\(7\left(2x-1\right)-12\left(x-5\right)=3\)

\(\Rightarrow14x-7-12x+60=3\)

\(\Rightarrow14x-12x=3-60+7\)

\(\Rightarrow2x=-50\)

\(\Rightarrow x=-25\)

\(\left|2x-1\right|=17\)

\(\Leftrightarrow\orbr{\begin{cases}2x-1=17\\2x-1=-17\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=9\\x=-8\end{cases}}\)

\(\left|8-3x\right|=14\)

\(\Leftrightarrow\orbr{\begin{cases}8-3x=14\\8-3x=-14\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=\frac{22}{3}\end{cases}}\)

2:

a: =>x^2+3x-4x-12-(x^2-5x+x-5)=8

=>x^2-x-12-x^2+4x+5=8

=>3x-7=8

=>3x=15

=>x=5

b: =>3x^2+3x-2x-2-3x^2-21x=13

=>-20x=15

=>x=-3/4

c: =>x^2-25-x^2-2x=9

=>-2x=25+9=34

=>x=-17

d: =>x^3-1-x^3+3x=1

=>3x-1=1

=>3x=2

=>x=2/3