Sửa đề: \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

Sửa đề: \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

\(4x^2-4xy+y-25a^2+10a-136\)

\(\text{Phân tích thành nhân tử}\)

\(-\left(4xy-y-4x^2+25a^2-10a+136\right)\)

k nhé !

\(1.25a^2+10a+1\)

\(=\left(5a\right)^2+2.5a.1+1^2\)

\(=\left(5a+1\right)^2\)

\(2.2x^8-12x^4+18\)

\(=2\left(x^8-6x^4+9\right)\)

\(=2\left[\left(x^4\right)^2-2.x^4.3+3^2\right]\)

\(=2\left(x^4-3\right)^2\)

\(=2\left(x^2-\sqrt{3}\right)^2\left(x^2+\sqrt{3}\right)^2\)

\(3.4x+4xy^6+xy^{12}\)

\(=x\left(y^{12}+4y^6+4\right)\)

\(=x\left[\left(y^6\right)^2+2.y^6.2+2^2\right]\)

\(=x\left(y^6+2\right)^2\)

Câu 1

\(25a^2+10a+1\)

\(=\left(5a\right)^2+2\cdot5\cdot a+1\)

\(=\left(5a+1\right)^2\)

A) \(25a^2+10a+1\)

\(=\left(5a\right)^2+2.5a.1+1^2\)

\(=\left(5a+1\right)^2\)

B) \(2x^8-12x^4+18\)

\(=2.\left(x^8-6x^4+9\right)\)

\(=2.\left[\left(x^4\right)^2-2.x^4.3+3^2\right]\)

\(=2.\left(x^4+3\right)^2\)

C) \(4x+4xy^6+xy^{12}\)

\(=\left(2\sqrt{x}\right)^2+2.\left(2\sqrt{x}\right).y^6+\left(xy^6\right)^2\)

\(=\left[\left(2\sqrt{x}\right)+xy^6\right]^2\)

P/s : Câu cuối không chắc chắn :))

Sai đề

Sửa đề: \(4x^2-4xy+y^2-25a^2+10a-1\)

\(=\left(2x-y\right)^2-\left(5a-1\right)^2\)

\(=\left(2x-y-5a+1\right)\left(2x-y+5a-1\right)\)

\(=y\left(4x^2-4xy+y^2-49\right)\)

\(=y\left[\left(2x-y\right)^2-49\right]\)

\(=y\left(2x-y-7\right)\left(2x-y+7\right)\)

a)4x^2 + y^2 - 4xy - 9t^2 = (2x)^2 - 4xy + y^2 - 9t^2

= (2x - y)^2 - (3t )^2

= ( 2x -y -3t ) ( 2x - y+ 3t)

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Đề sai nhé .Sửu lại

\(x^2-4x^2y^2+4+4x\)

\(=\left(x^2+4x+4\right)-4x^2y^2\)

\(=\left(x+2\right)^2-\left(2xy\right)^2\)

\(=\left(x+2+2xy\right)\left(x+2-2xy\right)\)