Cho góc nhọn \(\alpha\).Rút gọn biểu thức: \(\sin^6\alpha+c\text{os}^6\alpha+3sin^2\alpha-c\text{os}^2\alpha\)
Những câu hỏi liên quan
Cho góc nhọn \(\alpha\). Rút gọn biểu thức sau :
A = \(sin^6\alpha+c\text{os}^6\alpha+3sin^2-c\text{os}^2\)
\(=\left(sin^2\alpha\right)^3+\left(cos^2\alpha\right)^3+3sin^2\alpha-cos^2\alpha\)
\(=\left(sin^2\alpha+cos^2\alpha\right)\left(sin^4\alpha-sin^2\alpha.cos^2\alpha+cos^4\alpha\right)+3sin^2\alpha-cos^2\alpha\)
\(=sin^4\alpha-sin^2\alpha.cos^2\alpha+cos^4\alpha+3sin^2\alpha-cos^2\alpha\)
\(=sin^4\alpha+cos^4\alpha-sin^2\alpha.cos^2\alpha+3sin^2\alpha-cos^2\alpha\)
\(=\left(sin^2\alpha\right)^2+\left(cos^2\right)^2-sin^2\alpha.cos^2\alpha+3sin^2\alpha-cos^2\)
\(=1-2sin^2\alpha.cos^2\alpha-sin^2\alpha.cos^2\alpha+3sin^2\alpha-cos^2\alpha\)
\(=1-3sin^2\alpha.cos^2\alpha+3sin^2\alpha.cos^2\alpha-cos^2\alpha\)
\(=1-3sin^2\alpha.\left(1-sin^2\alpha\right)+3sin^2\alpha-\left(1-sin^2\alpha\right)\)
\(=1-3sin^2\alpha-sin^2\alpha+3sin^2\alpha-\left(1-sin^2\alpha\right)\)
\(1-3sin^2\alpha-sin^2\alpha+3sin^2\alpha-1+sin^2\alpha\)
\(=0\)
Đúng 0
Bình luận (0)
\(sin^3\alpha+c\text{os}^3\alpha+\left(sin\alpha+c\text{os}\alpha\right).sin\alpha.c\text{os}\alpha-c\text{os}\alpha.\)
=(sin a+cos a)(sin^2.a-sina.cosa+cos^2a)+(sina+cosa)sina.cosa-cos a
=(sin a+cos a)(1-sina.cosa+sina.cosa)-cosa
=sina+cosa-cosa
=sina
Đúng 0
Bình luận (0)
Cho \(\alpha\) là góc nhọn. Rút gọn biểu thức:
\(A=sin^6\alpha+cos^6\alpha+3sin^2\alpha-cos^2\alpha\)
cảm ơn các bạn trước nhé
\(A=sin^6\alpha+cos^6\alpha+3sin^2\alpha-cos^2\alpha\)
\(=\left(sin^2\alpha\right)^3+\left(cos^2\alpha\right)^3+3sin^2\alpha-cos^2\alpha\)
\(=\left(sin^2\alpha+cos^2\alpha\right)\left(sin^4\alpha+cos^4\alpha-sin^2\alpha.cos^2\alpha\right)+3sin^2\alpha-cos^2\alpha\)
\(=sin^4\alpha+cos^4\alpha-sin^2\alpha.cos^2\alpha+3sin^2\alpha-cos^2\alpha\)
\(=\left(sin^2\alpha+cos^2\alpha\right)^2-2sin^2\alpha.cos^2\alpha-sin^2\alpha.cos^2\alpha+3sin^2\alpha-cos^2\alpha\)
\(1-3sin^2\alpha.cos^2\alpha+3sin^2\alpha-cos^2\alpha=3sin^2\alpha\left(1-cos^2\alpha\right)+\left(1-cos^2\alpha\right)\)
\(=\left(3sin^2\alpha+1\right).sin^2\alpha=0\)
Đúng 0
Bình luận (0)
Cho α là góc nhọn : rút gọn biểu thức:
\(sin^6\alpha+cos^6\alpha+3sin^2\alpha-cos^2\alpha\)
\(\sin^6a+\cos^6a+3\sin^2a-\cos^2a\\ =\sin^6a+3\sin^2\cos^2\left(\sin^2a+\cos^2a\right)+\cos^6a-3\sin^2a\cos^2a\left(\sin^2a+\cos^2a\right)+3\sin^2a-\cos^2a\\ =\left(\sin^2a+\cos^2a\right)^3-3\sin^2a.\cos^2a.1+3\sin^2a-cos^2a\\ =1^3-\cos^2a+3\sin^2a-3\sin^2\cos^2\\ =\left(1-\cos^2a\right)\left(3\sin^2a+1\right)\)
Đúng 0
Bình luận (0)
cho \(\alpha\)là góc nhọn. Rút gọn biểu thức \(A=sin^6\alpha+3sin^2\alpha-cos^2\alpha^{ }\)
cho \(\tan\alpha+\cos\alpha=3\). Tính \(A=\sin\alpha\times\cos\alpha\)
(\(\alpha\)là alpha nha m.n)
giải hộ mk vs ạ !! gấp lắm
Cho \(\alpha\) là góc nhọn. Rút gọn biểu thức:
A=\(\sin^6\alpha+\cos^6\alpha+3\sin^2\alpha-\cos^2\alpha\)
GIÚP MÌNH VS M.N~!!!!!!!!!!!!
Đặt \(\sin^2\alpha=x\Rightarrow\cos^2\alpha=1-\sin^2\alpha\)
\(A=x^3+\left(1-x\right)^3+3x-\left(1-x\right)=x^3+1-3x+3x^2-x^3+3x-1+x=3x^2+x\)
Vậy \(A=3\sin^4\alpha+\sin^2\alpha\). NHỚ NHA!
Đúng 0
Bình luận (0)
cho α là góc nhọn rút gon biểu thức
A= sin6α + cos6α + 3sin2α - cos2α
=(sin2α)3 + (cos2α)3 + 3sin2α - cos2α
= (sin2α + cos2α)(sin4α - sin2α.cos2α + cos4α) + 3sin2α - cos2α
= 1.(sin4α - sin2α.cos2α + cos4α) + 3sin2α - cos2α
= (1- cos2α) - (1- cos2α).cos2α + cos4α + 3(1- cos2α) - cos2α
[ có 1- cos2α là vì sin2α + cos2α = 1 => sin2α = 1- cos2α nên thay sin2α thành 1- cos2α ]
= 1 - 2cos2α + cos4α - cos2α + cos4α + cos4α + 3 - 3cos2α - cos2α
= 4 - 7cos2α + 3cos4α [rút vậy chắc gọn rồi ha =w=]
Đúng 0
Bình luận (0)
Cho tam giác ABC có C<45 độ AB=c ; Bc = a ; AC=b. đường cao AH=h. Trung tuyến AM=m
CMR
a) \(c\text{os}2\alpha=c\text{os}^2\alpha-sin^2\alpha\)
b) \(tan2\alpha=\frac{2tan\alpha}{1tan^2\alpha}\)
Cho tam giác ABC có C<45 độ AB=c ; Bc = a ; AC=b. đường cao AH=h. Trung tuyến AM=m
CMR
a) \(c\text{os}2\alpha=c\text{os}^2\alpha-sin^2\alpha\)
b) \(tan2\alpha=\frac{2tan\alpha}{1tan^2\alpha}\)