\(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Rightarrow\frac{\left(72-x\right).5}{15}=\frac{3\left(x-18\right)}{15}\)

\(\Rightarrow\left(72-x\right).5=3\left(x-18\right)\)

\(\Rightarrow360-5x=3x-54\)

\(\Rightarrow-3x-5x=-360-54\)

\(\Rightarrow-8x=-414\)

\(\Rightarrow x=51,75\)

+) Vì \(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Rightarrow5\left(72-x\right)=3\left(x-18\right)\)

     \(5.72-5x=3x-3.18\)

      \(360-5x=3x-54\)

       \(-5x-3x=-54-360\)

       \(-8x=-414\)

              \(x=-414:\left(-8\right)\)

              \(x=51,75\)

      Vậy x = 51,75

\(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Leftrightarrow5\left(7x-2\right)=3\left(x-18\right)\)

\(\Leftrightarrow360-5x=3x-54\)

\(\Leftrightarrow360=3x-54+5x\)

\(\Leftrightarrow360=8x-54\)

\(\Leftrightarrow8x-54=360\) (chuyển vế)

\(\Leftrightarrow8x=360+54\)

\(\Leftrightarrow8x=414\)

\(\Leftrightarrow x=\frac{414}{8}=\frac{207}{4}\)

\(\Rightarrow x=\frac{207}{4}\)

<=> (x-18/74 - 1)+(x-20/72 - 1)+(x-22/70 - 1) = 0

<=> x-92/74 + x-92/72 + x-92/70 = 0

<=> (x-92).(1/74+1/72+1/70) = 0

<=> x-92 = 0 ( vì 1/74 + 1/72 + 1/70 > 0 )

<=> x=92

Vậy S = {92}

Tk mk nha

Ta có :

\(\frac{x-18}{74}+\frac{x-20}{72}+\frac{x-22}{70}=3\)

\(\Leftrightarrow\)\(\left(\frac{x-18}{74}-1\right)+\left(\frac{x-20}{72}-1\right)+\left(\frac{x-22}{70}-1\right)=3-3\)

\(\Leftrightarrow\)\(\frac{x-92}{74}+\frac{x-92}{72}+\frac{x-92}{70}=0\)

\(\Leftrightarrow\)\(\left(x-92\right)\left(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\right)=0\)

Vì \(\left(\frac{1}{74}+\frac{1}{72}+\frac{1}{70}\right)\ne0\)

\(\Rightarrow\)\(x-92=0\)

\(\Rightarrow\)\(x=92\)

Vậy \(x=92\)

Chúc bạn học tốt 

\(\frac{-5}{x}=\frac{-y}{8}=\frac{18}{72}\)

\(\Leftrightarrow\frac{-5}{x}=\frac{-y}{8}=\frac{1}{4}\)

\(\Leftrightarrow\orbr{\begin{cases}-\frac{5}{x}=\frac{1}{4}\\-\frac{y}{8}=\frac{1}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-5.4:1\\-y=8.1:4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-20\\-y=2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-20\\y=-2\end{cases}}}\)

vậy x=-20 và y=-2

\(-\frac{1}{3}-x=\frac{1}{2}-\frac{1}{-4}\)

\(-\frac{1}{3}-x=\frac{1}{2}-\frac{-1}{4}\)

\(-\frac{1}{3}-x=\frac{2}{4}-\frac{-1}{4}\)

\(-\frac{1}{3}-x=\frac{3}{4}\)

\(x=-\frac{1}{3}-\frac{3}{4}\)

\(x=-\frac{4}{12}-\frac{9}{12}\)

\(x=-\frac{13}{12}\)

\(x=-\frac{18}{24}+\frac{15}{21}\)

\(x=-\frac{3}{4}+\frac{5}{7}\)

\(x=-\frac{21}{28}+\frac{20}{28}\)

\(x=-\frac{1}{28}\)

Ta có: \(\dfrac{-5}{x}=\dfrac{-y}{8}=\dfrac{-18}{72}\)

\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{-5}{x}=-\dfrac{18}{72}=\dfrac{-1}{4}\\\dfrac{-y}{8}=\dfrac{-18}{72}=\dfrac{-1}{4}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=20\\y=2\end{matrix}\right.\)

Vậy: (x,y)=(20;2)

\(\dfrac{-5}{x}=\dfrac{-y}{8}=\dfrac{-18}{72}\) 

+)\(\dfrac{-5}{x}=\dfrac{-18}{72}\) 

\(\Rightarrow x=\dfrac{-5.72}{-18}=20\) 

+)\(\dfrac{-y}{8}=\dfrac{-18}{72}\) 

\(\Rightarrow-y=\dfrac{-18.8}{72}=-2\) 

\(\Rightarrow y=2\)

Xét \(\frac{-5}{x}=\frac{-18}{72}\)

\(\Rightarrow\)(-5) . 72 = x . (-18)

\(\Rightarrow\)-360 = x . (-18)

\(\Rightarrow\)x = (-360) : (-18) = 20

Xét \(\frac{y}{16}=\frac{-18}{72}\)

\(\Rightarrow\)72y = 16 . (-18)

\(\Rightarrow\)72y = -288

\(\Rightarrow\)y = (-288) : 72 = -4

Vậy x = 20 ; y = -4

Ta có : 

   \(\frac{-5}{x}=\frac{-18}{72}\Rightarrow\frac{-5}{x}=\frac{-1}{4}\)  

                            \(\Rightarrow-5.4=x.-1\) 

                            \(\Rightarrow-20=-x\)

                            \(\Rightarrow x=20\)

Thay x = 20 vào  \(\frac{-5}{x}\)ta được : 

\(\frac{-5}{20}=\frac{y}{16}\)\(\Rightarrow\frac{-1}{4}=\frac{y}{16}\Rightarrow-1.16=y.4\)

                                                   \(\Rightarrow-16=y.4\)  

                                                    \(\Rightarrow y=-4\)  

Vậy x = 20 , y = -4

Tk mk nha !!! 

\(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Rightarrow5\left(72-x\right)=3\left(x-18\right)\)

\(\Rightarrow360-5x=3x-54\)

\(\Rightarrow-5x-3x=-54-360\)

\(\Rightarrow-8x=-414\)

\(\Rightarrow x=207\)

\(\frac{72-x}{x-18}=\frac{x}{5}\)

=> 5(72 - x) = x(x - 18)

=> 360 - 5x = x² - 18x 

=> x² - 13x = 360

=> x² - 6,5x - 6,5x + 42,25 = 360 + 42,25

=> x(x - 6,5) - 6,5(x - 6,5) = 402,25

=> (x - 6,5)² = 402,25 

=> \(\orbr{\begin{cases}x=\sqrt{402,25}+6,5\\x=-\sqrt{402,25}+6,5\end{cases}}\)

Lớp 7 chưa học điều kiện, em nghĩ vậy nếu như lớp 8 sẽ thế này ạ 

ĐK : \(x\ne18\)

\(\frac{72-x}{x-18}=\frac{x}{5}\Leftrightarrow360-5x=x^2-18x\)

\(\Leftrightarrow360-23x-x^2=0\)( vô nghiệm ) 

Ta có : 

         -5/x = -18/72 

=> -5 . 72 = -18 . x 

=> -360    = -18 . x 

=>    x      = -360 :- 18

=>    x      = 20  

Thay x = 20 ta được : 

       -5/20 = y/16 

=> -5 . 16 = 20 . y  

=>    -80   = 20 . y 

=>      y    = -80 : 20

=>      y    = -4

Vậy x = 20 , y = -4

Chúc bạn học giỏi nha !!! 
Dấu " / " là chia 

TK mình nha !!! ^_^ 

x = 45/2                            y = -32/9

x=20

y=-4

Hok tốt

^_^

b, \(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Rightarrow\left(72-x\right).5=\left(x-18\right).3\)

\(\Rightarrow72.5-5x=3x-18.3\)

\(\Rightarrow360-5x=3x-54\)

\(\Rightarrow360+54=3x+5x\)

\(\Rightarrow414=8x\)

\(\Rightarrow x=414:8\)

\(\Rightarrow x=51,75\)

Vậy \(x=51,75\)

a, \(3\frac{4}{5}:2x=0,25:2\frac{2}{3}\)

\(\frac{19}{5}:2x=\frac{1}{4}:\frac{8}{3}\)

\(\frac{19}{5}:2x=\frac{3}{32}\)

\(2x=\frac{19}{5}:\frac{3}{32}\)

\(2x=\frac{608}{15}\)

\(x=\frac{304}{15}\)

Thay x vào biểu thức thì nó không có bằng nhau. Bạn xem lại đề nha.

b) \(\frac{72-x}{3}=\frac{x-18}{5}\)

\(\Rightarrow\left(72-x\right).5=\left(x-18\right).3\)

\(\Rightarrow360-5x=3x-54\)

\(\Rightarrow360+54=3x+5x\)

\(\Rightarrow414=8x\)

\(\Rightarrow x=414:8\)

\(\Rightarrow x=\frac{207}{4}\)

Vậy \(x=\frac{207}{4}.\)

Chúc bạn học tốt!