tra mạng đi Min Cute

\(\frac{x+1}{2}=\frac{x-2}{3}\)

\(\Rightarrow\left(x+1\right).3=\left(x-2\right).2\)

\(3x+3=2x-4\)

\(\Rightarrow3x-2x=-4-3\)

\(x=-7\)

KL: x= -7

Học tốt nhé bn !!

\(\frac{x+1}{2}=\frac{x-2}{3}\)

=> (x+1).3 = 2(x-2)

=> 3x + 3 = 2x - 2

=> 3 + 2 = 2x - 3x

=> 5 = -x

=> x = -5

\(\frac{x+1}{2}=\frac{x-2}{3}\)

\(\Rightarrow\left(x+1\right)3=2\left(x-2\right)\)

\(\Rightarrow3x+3=2x-4\)

\(\Rightarrow3x-2x=-4-3\)

\(\Rightarrow x=-7\)

vậy \(x=-7\)

mai mình đi học cô kiểm tra nên ai đó giúp mk vs

a) \(\frac{3x-6}{x+4}=\frac{2\left(x+5\right)+\left(x-3\right)}{x-2}\)

\(\frac{3\left(x-2\right)}{x+4}=\frac{2\left(x+5\right)+x-3}{x-2}\)

\(\frac{3\left(x-4\right)}{x+4}=\frac{3x+7}{x-2}\)

\(3\left(x-2\right)\left(x-2\right)=\left(3x+7\right)\left(x+4\right)\)

\(3\left(x-2\right)^2=\left(3x+7\right)\left(x+4\right)\)

\(3x^2-12x+12=3x^2+12x+7x+28\)

\(3x^2-12x+12=3x^2+19x+28\)

\(-12x+12=19x+28\)

\(12=19x+28+12x\)

\(19x+28+12x=12\) (chuyển vế)

\(31x+28=12\)

\(31x=12-28\)

\(31x=-16\)

\(x=-\frac{16}{31}\)

\(\Rightarrow x=-\frac{16}{31}\)

1

I 2x-3 I = I x+1 I

2x-3 = x+1

x+1 - 2x+3=0

x (1-2) +1+3=0

-1x +4 =0

-1x      = 0-4

-1x      =-4

x          = -4 : -1

x         =4

Trả lời:

    \(\left|2x-3\right|=\left|x+1\right|\)

\(\Rightarrow2x-3=x+1\) hoặc   \(2x-3=-\left(x+1\right)\)

TH1:   \(2x-3=x+1\)

           \(2x-x=1+3\)

            \(x=4\)

TH2: \(2x-3=-\left(x+1\right)\)

         \(2x-3=-x-1\)

          \(2x+x=-1+3\)

          \(3x=2\)

          \(x=\frac{2}{3}\)

          Vậy \(x=4;x=\frac{2}{3}\)

\(\left|\frac{1}{3}-x\right|-\left|-\frac{2}{3}\right|=\left|\frac{3}{4}\right|\)

\(\Leftrightarrow\frac{1}{3}-x-\frac{2}{3}=\frac{3}{4}\)

\(\Leftrightarrow\frac{1}{3}-x=\frac{3}{4}+\frac{2}{3}\)

\(\Leftrightarrow\frac{1}{3}-x=\frac{17}{12}\)

\(\Leftrightarrow x=\frac{1}{3}-\frac{17}{12}=\frac{4}{12}-\frac{17}{12}=\frac{-13}{12}\)