a) \(2.\left|5x-3\right|-2x=14\)

\(2\left|5x-3\right|=14+2x\)

\(\left|5x-3\right|=\frac{14+2x}{2}\)

\(\Rightarrow\orbr{\begin{cases}5x-3=\frac{-14-2x}{2}\\5x-3=\frac{14+2x}{2}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}\left(5x-3\right).2=-14-2x\\\left(5x-3\right).2=14+2x\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}10x-6+2x=-14\\10x-6-2x=14\end{cases}\Rightarrow\orbr{\begin{cases}12x=-14+6\\8x=14+6\end{cases}}}\Rightarrow\orbr{\begin{cases}12x=-8\\8x=20\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{-2}{3}\\x=2,5\end{cases}}\)

vậy \(\orbr{\begin{cases}x=\frac{-2}{3}\\x=2,5\end{cases}}\)

Những câu sau tương tự nhé. 

làm giúp đi

\(\left(4-2x\right)\left(5x-10\right)=0\\ \Leftrightarrow2\left(2-x\right)5\left(x-2\right)=0\\ \Leftrightarrow-10\left(x-2\right)^2=0\Leftrightarrow x-2=0\Leftrightarrow x=2\)

\(\left(4-2x\right)\left(5x-10\right)=0\)

\(\Leftrightarrow x=2\)

\(5x=10\sqrt{x}\)

\(\Leftrightarrow5x=10\cdot x^{\frac{1}{2}}\)

\(\Leftrightarrow x=2\cdot x^{\frac{1}{2}}\)

\(\Leftrightarrow x^{\frac{1}{2}}=2\)

\(\Leftrightarrow\sqrt{x}=2\)

\(\Leftrightarrow\sqrt{x^2}=2^2\)

\(\Leftrightarrow x=4\)

Vậy x=4.

\(5x=10\sqrt{x}\)

\(\Rightarrow5\left(\sqrt{x}\right)^2=5.2\sqrt{x}\)

\(\Rightarrow\left(\sqrt{x}\right)^2=2\sqrt{x}\)

\(\Rightarrow\left(\sqrt{x}\right)^2-2\sqrt{x}=0\)

\(\Rightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}\sqrt{x}=0\\\sqrt{x}-2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\\sqrt{x}=2\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=4\end{cases}}}\)

Vậy \(\orbr{\begin{cases}x=0\\x=4\end{cases}}\)

\(5x\left(3x^2y-2xy^2+1\right)-3xy\left(5x^2-3xy\right)+x^2y^2-10=0\)

\(\Leftrightarrow15x^3y-10x^2y^2+5x-15x^3y+9x^2y^2+x^2y^2-10=0\)

\(\Leftrightarrow5x=10\Leftrightarrow x=2\)

+TH1:\(x\le-7\)

Ta có: \(-x-1-x+2-x-7=5x-10\Rightarrow x=\dfrac{1}{2}\) (loại)

+TH2: \(-7\le x\le-1\)

Ta có: \(-x-1-x+2+x+7=5x-10\Rightarrow x=3\)(loại)

+TH3: \(-1\le x\le2\)

Ta có: \(x+1-x+2+x+7=5x-10\Rightarrow x=5\)(loại)

+TH4: \(x>2\)

Ta có: \(x+1+x-2+x+7=5x-10\Rightarrow x=8\)(tm)

Vậy x=8

y=5x,y=10

=>5x=10

x=10:5

x=2

y = 5x 

y = 10

<=> 5x = 10

<=> x = 2

5x=10 nen x=2

      5x + 15 = 10 

<=> 5(x+3) = 5.2

<=> x+3 =2

<=> x = 2-3 

<=> x = -1

Vậy x = -1 thì thỏa 5x + 15 = 10 

\(5x+15=10\)

\(\Rightarrow5.\left(x+3\right)=5.2\)

\(\Rightarrow x+3=2\)

\(\Rightarrow x=2-3\)

\(\Rightarrow x=-1\)

Vậy \(x=-1\)

Chúc bạn học tốt !!! 

5x + 15 = 10

        5x = 10 - 15 = -5

         x = -5 : 5

         x = -1

\(6x-4+5x-3+4-10=9\)

\(6x+5x+4x=9+4+3+10\)

\(15x=26\)

\(x=\dfrac{26}{15}\)

\(6x-4+5x-3+4x-10-9=0\)

\(15x-26=0\)

\(x=\dfrac{26}{15}\)

5x+3.(10-x)+x=45

5x+30-3x+x=45

3x+30=45

3x    =15

x  =   5

X=5 ai thích thì k hộ mik nha!

\(5x+30-3x+x=45\Rightarrow3x+30=45\Rightarrow x=5\)