Đề mik chẳng hiểu tý gì luôn

\(\dfrac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)

\(=\dfrac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)}\)

\(=\dfrac{4}{5}\)

utroi vt j z

a,

\(\dfrac{4^6\cdot9^5+6^9\cdot120}{-8^4\cdot3^{12}-6^{11}}=\dfrac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{-2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{-2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}\left(1+5\right)}{-2^{11}\cdot3^{11}\left(2\cdot3-1\right)}=\dfrac{2^{13}\cdot3^{11}}{-2^{11}\cdot3^{11}\left(2\cdot3+1\right)}=\dfrac{2^2}{7}=\dfrac{4}{7}\)

b,

\(\dfrac{1}{1-\dfrac{1}{1-2-1}}+\dfrac{1}{1+\dfrac{1}{1+2-1}}=\dfrac{1}{1-\dfrac{1}{-2}}+\dfrac{1}{1+\dfrac{1}{2}}=\dfrac{1}{1+\dfrac{1}{2}}+\dfrac{1}{1+\dfrac{1}{2}}=\dfrac{2}{\dfrac{3}{2}}=\dfrac{4}{3}\)

Cảm ơn bạn nha

s bạn lại cảm ơn mik?

Nhiwf bạn nên mình làm được bài này ! Hihi 

M=4⁸:9⁸+6⁹x120/8⁴x3¹²-6¹¹

M=(2²)⁸:(3²)⁸+6⁹x2³x3x5/(2³)⁴x3¹²-6¹¹

M=2¹⁶:3¹⁶+6⁹x2³x3x5/2¹²x3¹²-6¹¹

M=(2¹⁹:3¹⁷+6⁹⁾x5 / 2¹²x3¹²-6¹¹

M=2⁷:3⁵x5/6²

M=128/243x5:36

M=640/243:36

M=160/2187

\(4^0\cdot9^3-6^9\cdot\dfrac{120}{8^4\cdot3^{12}+6^{11}}\) hay \(4^0\cdot9^3-6^9\cdot\dfrac{120}{8^4}\cdot3^{12}+6^{11}\)?