\(-\dfrac{6\sqrt{2}-\sqrt{\left(9-8\sqrt{2}\right)\cdot2}}{2}\)

\(\sqrt{2.36}+\sqrt{2.\dfrac{9}{4}}-\sqrt{2.16}-\sqrt{2.81}=6\sqrt{2}+\dfrac{3}{2}\sqrt{2}-4\sqrt{2}-9\sqrt{2}=\dfrac{-11}{2}\sqrt{2}\)

\(\sqrt{4\dfrac{1}{2}}+\sqrt{32}-\sqrt{72}+\sqrt{162}\\ =\sqrt{\dfrac{4\cdot2+1}{2}}+\sqrt{4^2\cdot2}-\sqrt{6^2\cdot2}+\sqrt{9^2\cdot2}\\ =\sqrt{\dfrac{9}{2}}+4\sqrt{2}-6\sqrt{2}+9\sqrt{2}\\ =\dfrac{3}{\sqrt{2}}+7\sqrt{2}\\ =\dfrac{3}{\sqrt{2}}+\dfrac{7\sqrt{2}\cdot\sqrt{2}}{\sqrt{2}}\\ =\dfrac{17}{\sqrt{2}}\)

\(=\sqrt{\dfrac{9}{2}}+4\sqrt{2}-6\sqrt{2}+9\sqrt{2}\)

\(=\dfrac{3}{2}\sqrt{2}+7\sqrt{2}=\dfrac{17}{2}\sqrt{2}\)

\(\sqrt{4\dfrac{1}{2}}+\sqrt{32}-\sqrt{72}+\sqrt{162}\)

\(=\sqrt{\dfrac{9}{2}}+\sqrt{4^2.2}-\sqrt{6^2.2}+\sqrt{9^2.2}\)

\(=\dfrac{3}{\sqrt{2}}+4\sqrt{2}-6\sqrt{2}+9\sqrt{2}\)

\(=\dfrac{3\sqrt{2}}{2}+7\sqrt{2}=\dfrac{3\sqrt{2}+14\sqrt{2}}{2}=\dfrac{17\sqrt{2}}{2}\)

\sqrt{72}\+ \sqrt{4+1/2}\ - \sqrt{32}\ -\sqrt{162}\

6: Ta có: \(\left(3\sqrt{2}-\sqrt{3}\right)\left(3\sqrt{2}+\sqrt{3}\right)\)

=18-3

=15

7: Ta có: \(\sqrt{72}+\sqrt{4\dfrac{1}{2}}-\sqrt{32}-\sqrt{162}\)

\(=6\sqrt{2}+\dfrac{3}{2}\sqrt{2}-4\sqrt{2}-9\sqrt{2}\)

\(=-\dfrac{11}{2}\sqrt{2}\)

\(\sqrt{2\cdot36}+\sqrt{2\cdot\dfrac{9}{4}}-\sqrt{2\cdot16}-\sqrt{2\cdot81}=6\sqrt{2}+\dfrac{3}{2}\sqrt{2}-4\sqrt{2}-9\sqrt{2}=\dfrac{-11}{2}\sqrt{2}\)

a: \(A=\left(1-\sqrt{7}\right)\cdot\left(1+\sqrt{7}\right)=1-7=-6\)

b: \(B=3\sqrt{3}+8\sqrt{3}-15\sqrt{3}=-4\sqrt{3}\)

c: \(C=4\sqrt{2}-5\sqrt{2}+3\sqrt{2}=2\sqrt{2}\)

a, A = \(3\sqrt{3}+4\sqrt{12}-5\sqrt{27}\)

= \(3\sqrt{3}+8\sqrt{3}-15\sqrt{3}\)

= \(-4\sqrt{3}\)

b, B = \(\sqrt{32}-\sqrt{50}+\sqrt{18}\)

= \(4\sqrt{2}-5\sqrt{2}+3\sqrt{2}\)

= \(2\sqrt{2}\)

A. 1155 nha bạn