C1:

A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-\left(2\frac{5}{7}+2\frac{1}{3}\right)\)

A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-2\frac{5}{7}-2\frac{1}{3}\)

A = \(3\frac{5}{7}-2\frac{5}{7}+4\frac{2}{3}-2\frac{1}{3}\)

A = \(1+2\frac{1}{3}\)

A = \(1+\frac{7}{3}\)

A = \(\frac{10}{3}\)

C2:

A = \(3\frac{5}{7}+4\frac{2}{3}\)\(-\left(2\frac{5}{7}+2\frac{1}{3}\right)\)

A = \(\frac{26}{7}+\frac{14}{3}-\frac{19}{7}-\frac{7}{3}\)

A = \(1+\frac{14}{3}-\frac{7}{3}=\frac{10}{3}\)

C1: Ta có: \(B=8\frac{1}{9}-3\frac{2}{7}+6\frac{8}{7}-3\frac{5}{7}\)

\(=8+\frac{1}{9}-\left(3+\frac{2}{7}\right)+6+\frac{8}{7}-\left(3+\frac{5}{7}\right)\)

\(=8+\frac{1}{9}-3-\frac{2}{7}+6+1+\frac{1}{7}-3-\frac{5}{7}\)

= \(\left(8-3+6+1-3\right)+\left(\frac{1}{9}-\frac{2}{7}+\frac{1}{7}-\frac{5}{7}\right)\)

\(=9+\left(\frac{-47}{63}\right)\)

 \(=\frac{520}{63}\)

C2: Đổi hỗn số ra phân số rồi tính ( cj nghĩ thế )

Bài 3 là hỗn số hả em?

Bài 1: 

a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)

\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)

\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)

hay \(x=-\dfrac{1}{3}\)

Vậy: \(x=-\dfrac{1}{3}\)

b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)

\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)

hay \(x=\dfrac{50}{9}\)

Vậy: \(x=\dfrac{50}{9}\)

c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)

\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)

\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)

hay \(x=\dfrac{22}{15}\)

Vậy: \(x=\dfrac{22}{15}\)

d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)

\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)

\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)

hay \(x=\dfrac{15}{19}\)

Vậy:\(x=\dfrac{15}{19}\)

Bài 1:

a) \(2\frac{1}{4}+1\frac{1}{2}-1\frac{4}{5}\)

=\(\frac{9}{4}\)+\(\frac{3}{2}\)-\(\frac{9}{5}\)

=\(\frac{45}{20}+\frac{30}{20}-\frac{36}{20}\)

=\(\frac{39}{20}\)

b) \(2\frac{2}{3}\times3\frac{1}{4}:2\frac{3}{4}\)

\(\frac{8}{3}\times\frac{13}{4}:\frac{11}{4}\)

=\(\frac{8}{3}\times\frac{13}{4}\times\frac{4}{11}\)

=\(\frac{104}{33}\)

Bài 2:

a) \(\frac{7}{9}+\frac{4}{5}+\frac{11}{9}+\frac{6}{5}\)

=\(\left(\frac{7}{9}+\frac{11}{9}\right)+\left(\frac{4}{5}+\frac{6}{5}\right)\)

=2+2

=4

b) \(\frac{21}{36}\times\frac{39}{14}\times\frac{54}{13}\)

=\(\frac{21\times39\times54}{36\times14\times13}\)

=\(\frac{675}{100}\)

dung ko ban

bn ơi bài quá dễ

^{1/2 + 2/3 - 3/4 * 4/5 * 5/6 * 6/7 * 7/8 * 8/9 *...* 29/30 : 6/10}

^{= 1/2 + 2/3 - 1/10 : 6/10}

^{= 1/2 + 2/3 - 1/6}

^{= 1}

ủng hộ mình lên 280 điểm với các bạn

bai toan nay kho

\(S=\dfrac{3}{4}-\dfrac{1}{4}-\left(\dfrac{7}{3}-\dfrac{9}{2}\right)-\dfrac{5}{6}\)

\(=\left(\dfrac{3}{4}-\dfrac{1}{4}+\dfrac{18}{4}\right)-\left(\dfrac{14}{6}+\dfrac{5}{6}\right)\)

\(=\dfrac{20}{4}-\dfrac{19}{6}=\dfrac{11}{6}\)

\(S=\dfrac{3}{4}-0,25-\left[\dfrac{7}{3}+\left(\dfrac{-9}{2}\right)\right]-\dfrac{5}{6}\)

   \(=\dfrac{3}{4}-0,25 +\dfrac{13}{6}-\dfrac{5}{6}\)

   \(=\dfrac{11}{6}\)