\(16\frac{2}{7}:\left(-\frac{3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)

\(=\frac{114}{7}:\left(-\frac{3}{5}\right)+\frac{198}{7}:\frac{3}{5}\)

\(=-\frac{190}{7}+\frac{330}{7}\)

\(=20\)

\(A=\frac{15}{34}+\frac{7}{21}+\frac{9}{34}-1\frac{15}{17}+\frac{2}{3}\)

   \(=\frac{12}{17}+\frac{1}{3}-\frac{32}{17}+\frac{2}{3}\)

   \(=-\frac{20}{17}+\frac{1}{3}+\frac{2}{3}\)

   \(=-\frac{20}{17}+1\)

   \(=-\frac{3}{17}\)

\(B=16\frac{2}{7}:\left(-\frac{3}{5}\right)-28\frac{2}{7}:\left(-\frac{3}{5}\right)\)

   \(=\left(\frac{114}{7}-\frac{198}{7}\right):\left(-\frac{3}{5}\right)\)

   \(=\left(-12\right):\left(-\frac{3}{5}\right)\)

   \(=20\)

A\(=\frac{15}{34}+\frac{7}{21}+\frac{9}{34}-1\frac{15}{17}+\frac{2}{3}\)

\(=\left(\frac{15}{34}+\frac{9}{34}\right)+\left(\frac{7}{21}+\frac{2}{3}\right)-1\frac{15}{17}\)

\(=\left(\frac{14}{17}-\frac{15}{17}\right)+1-1\)

\(=-\frac{1}{17}\)

\(B=16\frac{2}{7}:\left(-\frac{3}{5}\right)-28\frac{2}{7}:\left(-\frac{3}{5}\right)\)

\(B=-\frac{3}{5}.\left(16\frac{2}{7}-28\frac{2}{7}\right)\)

\(B=-\frac{3}{5}.\left(-12\right)\)

\(B=\frac{36}{5}\)

Hoctot

A=\(\frac{15}{34}\)+ \(\frac{7}{21}\)+  \(\frac{9}{34}\)- 1\(\frac{15}{17}\)+ \(\frac{2}{3}\)

   = ( \(\frac{15}{34}\)+ \(\frac{9}{34}\)) + ( \(\frac{7}{21}\)+ \(\frac{2}{3}\)) - \(\frac{32}{17}\)

  =  \(\frac{24}{34}\)+ ( \(\frac{7}{21}\)+ \(\frac{14}{21}\)) - \(\frac{32}{17}\)

  =\(\frac{12}{17}\)+ \(\frac{21}{21}\)- \(\frac{32}{17}\)

  = ( \(\frac{12}{17}\) - \(\frac{32}{17}\)) +1

  =\(\frac{-20}{17}\)+ \(\frac{17}{17}\)

  = \(\frac{-3}{17}\)

\(=\left(16\frac{2}{7}-28\frac{2}{7}\right):\left(-\frac{3}{5}\right)\)
\(=-12\div\left(-\frac{3}{5}\right)=20\)

\(16\frac{2}{7}:\left(\frac{-3}{5}\right)-28\frac{2}{7}:\left(\frac{-3}{5}\right)\)

\(=16\frac{2}{7}.\left(\frac{-5}{3}\right)-28\frac{2}{7}.\left(\frac{-5}{3}\right)\)

\(=\left(16\frac{2}{7}-28\frac{2}{7}\right).\left(\frac{-5}{3}\right)\)

\(=\left(-12\right).\left(\frac{-5}{3}\right)\)\(=20\)

K mình nha

Kết quả là 20 nhé !

16\(\frac{2}{7}\):\(\left(\frac{-3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)

=\(\frac{114}{7}.\frac{-5}{3}+\frac{198}{7}.\frac{5}{3}\)

=\(\frac{-190}{7}+\frac{330}{7}\)

=\(\frac{140}{7}\)

=20

Chúc bn học tốt!

\(^{ }_{ }\)

Thực hiện phép tính

\(16\frac{2}{7}\div\left(\frac{-3}{5}\right)+28\frac{2}{7}\div\frac{3}{5}=\frac{114}{7}.\frac{-5}{3}+\frac{198}{7}.\frac{5}{3}=\frac{-190}{7}+\frac{330}{7}=\frac{140}{7}=20\)

CHÚC BẠN HỌC TỐT

\(B=16\frac{2}{7}:\left(\frac{-3}{5}\right)-28\frac{2}{7}:\left(\frac{-3}{5}\right)\)

\(B=\frac{114}{7}\cdot\frac{-5}{3}-\frac{198}{7}\cdot\frac{-5}{3}\)

\(B=\left(\frac{114}{7}-\frac{198}{7}\right)\cdot\frac{-5}{3}\)

\(B=\frac{-84}{7}\cdot\frac{-5}{3}\)

\(B=\frac{420}{21}\)

\(B=20\)

\(=\frac{16}{5}.\frac{15}{16}-\left(\frac{3}{4}+\frac{2}{7}\right):\left(\frac{-29}{28}\right)\)

\(=3-\left(\frac{21}{28}+\frac{8}{28}\right):\left(\frac{-29}{28}\right)\)

\(=3-\left(\frac{29}{28}\right).\left(\frac{-28}{29}\right)\)

\(=3-\left(-1\right)\)

\(=4\)

b)   \(=\left(\frac{1}{4}+\frac{25}{2}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right)\)

       \(=\left(\frac{4}{16}+\frac{200}{16}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3.3}{2.3.4}-\frac{2}{2.3.4}\right)\right)\)

     \(=\left(\frac{199}{16}\right):\left(12-\frac{7}{12}:\left(\frac{9}{24}-\frac{2}{24}\right)\right)\)

      \(=\frac{199}{16}:\left(12-\frac{7}{12}.\frac{24}{7}\right)\)

    \(=\frac{199}{16}:\left(12-2\right)\)

\(=\frac{199}{16}:10\)

\(=\frac{199}{160}\)

c)   \(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)

\(\left(\frac{-33}{55}+\frac{25}{55}\right):\frac{-3}{7}+\left(\frac{4}{5}\right):\frac{-3}{7}\)

\(\left(\frac{-8}{55}\right).\frac{-7}{3}+\frac{4}{5}.\frac{-7}{3}\)

\(\frac{-7}{3}\left(\frac{-8}{55}+\frac{4}{5}\right)\)

\(\frac{-7}{3}.\frac{36}{55}=\frac{-84}{55}\)

giờ mk phải đi ngủ r mai mk làm cho 

nhớ làm giúp mình nhá mai mình phải đi học r :<

a: \(A=\left(\dfrac{15}{34}+\dfrac{9}{34}-1-\dfrac{15}{17}\right)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)

\(=\left(\dfrac{12}{17}-1-\dfrac{15}{17}\right)+1\)

\(=\dfrac{-20}{17}+1=\dfrac{-3}{17}\)

b: \(B=\dfrac{-5}{3}\cdot16\dfrac{2}{7}-\dfrac{-5}{3}\cdot28\dfrac{2}{7}\)

\(=\dfrac{-5}{3}\left(16+\dfrac{2}{7}-28-\dfrac{2}{7}\right)=\dfrac{-5}{3}\cdot\left(-12\right)=20\)

c: \(C=25\cdot\dfrac{-1}{27}+\dfrac{1}{5}-2\cdot\dfrac{1}{4}-\dfrac{1}{2}\)

\(=\dfrac{-25}{27}+\dfrac{1}{5}-1\)

\(=\dfrac{-125+27-135}{135}=\dfrac{-233}{135}\)