x+4/3000 + x+3/3001 = x+2/3002 + x+1/3003

=> (x+4/3000 + x+3/3001) - (x+2/3002 + x+1/3003) = 0

=> (x+4/3000 + 1 + x+3/3001 + 1) - (x+2/3002 + 1 + x+1/3003 + 1) = 0

=> (x+3004/3000 + x+3004/3001) - (x+3004/3002 + x+3004/3003) = 0

=> (x+3004) x (1/3000 + 1/3001) - (x+3004) x (1/3002 + 1/3003) = 0

=> (x+3004) x [(1/3000 + 1/3001) - [(1/3002 + 1/3003)] = 0

=> x+3004 = 0 hoặc (1/3000 + 1/3001) - (1/3002 + 1/3003) = 0

Mà 1/3000 + 1/3001 > 1/3002 + 1/3003 => (1/3000 + 1/3001) - (1/3002 + 1/3003) khác 0

=> x+3004 = 0

=> x = 0-3004 = -3004

Vậy x = -3004

(x + 3).(x + 1/2) < 0

=> trong 2 số x + 3 và x + 1/2 có 1 số < 0 và 1 số > 0

Mà x + 3 > x + 1/2

=> x + 3 > 0 và x + 1/2 < 0

=> x > -3 và x < -1/2

=> x > -6/2 và x < -1/2

=> x thuộc { -5/2 ; -4/2 ;-3/2}

Vậy x thuộc { -5/2 ; -4/2 ; -3/2}

bai toan nay kho

Đặt A=1-2+3-4+............+3001-3002

A=(1-2)+(3-4)+..............+(3001-3002)

A=(-1)+(-1)+................+(-1){Có 1501 số(-1)}

A=(-1).1501

A=-1501

\(A=2219.2221.2226-2218.2223.2225\)

\(A=2219.(2223-2).2226-2218.2223.2225\)

\(A=2219.2223.2226-2.2219.2226-2218.2223.2225\)

\(A=2223.(2219.2216-2218.2225)-2.2219.2216\)

\(A=2223.\left\{(2218+1).(2215+1)-2218.2225\right\}-2.2219.2216\)

\(A=2223.(2218+2225+1)-2219.2226-2219.2226\)

\(A=2223.2219+2223.2225-2219.2226-2219.2226\)

\(A=(2223.2219-2219.2226)+2223.2225-2219.2225-2219\)

\(A=2219.(-3)+2225.4-2219\)

\(A=2219.(-4)+2225.4\)

\(A=4.(2225-2219)\)

\(A=4.6\)

\(A=24\)

\(B=3004.2999.2997-3003.2996.3001\)

\(B=3004.2999.(3001-4)-3003.2996.3001\)

\(B=(3003+1).2999.3001-3004.2999.4-3003.2996.3001\)

\(B=3003.(2996+3).3001+2999.3001-3004.2999.4-3003.2996.3001\)

\(B=3003.2996.3001+3.3003.3001-3.3004.2999+2999.3001-3004.2999-3003.2996.3001\)

\(B=3.(3003.3001-3004.2999)+2999.(3001-3004)\)

\(B=3.\left\{\left(3004-1\right).\left(2999+2\right)-3004.2999\right\}-3.2999\)

\(B=3.\left(3004.2999+2.3004-2999-2-3004.2999\right)-3.2999\)

\(B=3.(2.3003-2999)-3.2999\)

\(B=6.3003-6.2999\)

\(B=6.(3003-2999)\)

\(B=6.4\)

\(B=24\)

Mà \(A=24\) , \(B=24\)

\(\Rightarrow A=B\)

A=2219*(2223-2)*2226 - 2218*2223*2225

=2219*2223*2226 - 2*2219*2226 - 2218*2223*2225

=2223*(2219*2226 - 2218*2225) - 2*2219*2226

=2223*[(2218+1)*(2225+1) - 2218*2225] - 2*2219*2226

=2223*(2218+2215+1) - 2*2219*2226

=2223*2219+2223*2225 - 2219*2226 - 2219*2226

=(2223*2219 - 2219*2226) +2223*2225 - 2219*2225 - 2219

=2219*(-3) + 2225*4 - 2219

=2219*(-4) + 2225*4 = 4*(2225-2219) = 4*6 = 24

B=3004*2999*(3001-4) - 3003*2996*3001

=(3003+1)*2999*3001 - 3004*2999*4 - 3003*2996*3001

=3003*(2996+3)*3001 +2999*3001 - 3004*2999*4 - 3003*2996*3001

=3003*2996*3001+3*3003*3001 +2999*3001 - 3*3004*2999 - 3004*2999 - 3003*2996*3001

=3*(3003*3001 - 3004*2999) + 2999*(3001-3004)

=3*[(3004-1)*(2999+2) - 3004*2999] - 3*2999

=3*(3004*2999+2*3004 - 2999 - 2 - 3004*2999) - 3*2999

=3*(2*3003-2999) - 3*2999

=6*3003 - 6*2999 = 6*(3003-2999) = 6*4 = 24

===> A=B (=24)

y ở đâu vậy?

aaaaaa = a . 111111 = a . 3003 . 37 chia hết cho 3003

=> aaaaaa chia hết cho 3003 (đpcm)

\(a)\left(2^2\right)^x=2^5\)

\(\Leftrightarrow2^{2x}=2^5\)

\(\Leftrightarrow2x=5\)

\(\Leftrightarrow x=2,5\)

\(b)\left(3^x\right)^2=81\)

\(\Leftrightarrow3^{2x}=3^4\)

\(\Leftrightarrow2x=4\)

\(\Leftrightarrow x=2\)

\(c)8^{x+1}=2^{3003}\)

\(\Leftrightarrow\left(2^3\right)^{x+1}=2^{3003}\)

\(\Leftrightarrow2^{3\left(x+1\right)}=2^{3003}\)

\(\Leftrightarrow3\left(x+1\right)=3003\)

\(\Leftrightarrow x+1=1001\)

\(\Leftrightarrow x=1000\)

\(d)8^{x+1}=4^{1002}\)

\(\Leftrightarrow\left(2^3\right)^{x+1}=\left(2^2\right)^{1002}\)

\(\Leftrightarrow2^{3\left(x+1\right)}=2^{2004}\)

\(\Leftrightarrow3\left(x+1\right)=2004\)

\(\Leftrightarrow x+1=668\)

\(\Leftrightarrow x=667\)