Để nhân các phân số này, ta chỉ cần nhân tử số với nhau và mẫu số với nhau:

\[
\frac{1}{3} \times \frac{2}{5} \times \frac{3}{7} \times \frac{4}{9} \times \frac{5}{11} \times \frac{6}{15} \times \frac{7}{15} \times \frac{8}{15} \times \frac{9}{19} \times \frac{10}{21} \times \frac{11}{32} \times \frac{12}{25} \times \left( \frac{126}{252} - 4 \right)
\]

Sau đó, ta thực hiện các phép tính:

1. Nhân tử số:
\[1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9 \times 10 \times 11 \times 12 \times 126 = 997920\]

2. Nhân mẫu số:
\[3 \times 5 \times 7 \times 9 \times 11 \times 15 \times 15 \times 15 \times 19 \times 21 \times 32 \times 25 \times 252 = 7621237680\]

Kết quả là:
\[\frac{997920}{7621237680}\]

Bây giờ, ta có thể rút gọn phân số này bằng cách chia tử số và mẫu số cho 160:

\[ \frac{997920}{7621237680} = \frac{997920 ÷ 160}{7621237680 ÷ 160} = \frac{6237}{47695230} \]

\(\frac{6\div\frac{3}{5}-1\frac{1}{6}\times\frac{6}{7}}{4\frac{1}{5}\times\frac{10}{11}+5\frac{2}{11}}=\frac{6\div\frac{3}{5}-\frac{1\times6+1}{6}\times\frac{6}{7}}{\frac{4\times5+1}{5}\times\frac{10}{11}+\frac{5\times11+2}{11}}\)

\(=\frac{6\div\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}}{\frac{21}{5}\times\frac{10}{11}+\frac{57}{11}}=\frac{\left(6\div\frac{3}{5}\right)-\left(\frac{7}{6}\times\frac{6}{7}\right)}{\left(\frac{21}{5}\times\frac{10}{11}\right)+\frac{57}{11}}\)

\(=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}=\frac{9}{\frac{99}{11}}=\frac{9}{9}=1\)

_{^{NUGRUGJG T 0U3O UKWI FU JR HKLYG     QIQUTMVMNUCNREFDK4NMBNNCBRT 32C489898989  ROUH}} 

Bài làm

     \(\frac{10-1\frac{1}{6}\times\frac{6}{7}}{21:\frac{11}{2}+5\frac{2}{12}}\)

\(=\frac{10-\frac{7}{6}\times\frac{6}{7}}{21\times\frac{2}{11}+\frac{62}{12}}\)

\(=\frac{10-1}{\frac{42}{11}+\frac{62}{12}}\)

\(=9:(\frac{42}{11}+\frac{62}{12})\)

\(=9:\left(\frac{504}{132}+\frac{682}{132}\right)\)

\(=9:\frac{1186}{132}\)

\(=9:\frac{593}{66}\)

\(=9\times\frac{66}{593}\)

\(=\frac{594}{593}\)

# Hông bt có đúng k nx. #
 

594/593

\(\frac{6:\frac{3}{5}-1\frac{1}{6}\times\frac{6}{7}}{4\frac{1}{5}\times\frac{10}{11}+5\frac{2}{11}}\)

\(=\frac{\frac{6}{1}:\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}}{\frac{21}{5}\times\frac{10}{11}\times\frac{57}{11}}\)

\(=\frac{\frac{6}{1}\times\frac{5}{3}-1}{\frac{210}{55}+\frac{57}{11}}\)

\(=\frac{\frac{30}{3}-1}{\frac{42}{11}+\frac{57}{11}}\)

\(=\frac{10-1}{\frac{99}{11}}\)

\(=\frac{9}{9}\)

\(=1\)

\(6:\frac{3}{5}-1\frac{1}{6}\)X \(\frac{6}{7}\)                                                     \(4\frac{1}{5}\)X \(\frac{10}{11}+5\frac{2}{11}\)

\(=\frac{33}{5}-\frac{7}{6}\)X \(\frac{6}{7}\)                                             \(=\)      \(\frac{21}{5}\)X  \(\frac{10}{11}+\frac{57}{11}\) 

\(=\frac{33}{5}-1\)                                                              \(=\frac{42}{11}+\frac{57}{11}\)

\(=\frac{28}{5}\)                                                                       \(=\frac{99}{11}=9\)

\(A=\frac{10-1\frac{1}{6}.\frac{6}{7}}{21:\frac{11}{2}+5\frac{2}{11}}=\frac{10-\frac{7}{6}.\frac{6}{7}}{\frac{21.2}{11}+\frac{57}{11}}=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}=\frac{9}{9}=1\)

\(9\frac{2}{9}+\frac{2}{3}+7\frac{7}{9}\)

\(=9+\frac{2}{9}+\frac{2}{3}+7+\frac{7}{9}\)

\(=\left(9+7\right)+\left(\frac{2}{9}+\frac{7}{9}\right)+\frac{2}{3}\)

\(=16+1+\frac{2}{3}\)

\(=17+\frac{2}{3}\)

\(=\frac{51}{3}+\frac{2}{3}\)

\(=\frac{53}{3}\)

\(\frac{5}{9}.\frac{10}{11}+\frac{5}{9}.\frac{14}{11}-\frac{5}{9}.\frac{15}{11}\)

\(=\frac{5}{9}\left(\frac{10}{11}+\frac{14}{11}-\frac{15}{11}\right)\)

\(=\frac{5}{9}.\frac{9}{11}\)

\(=\frac{5}{11}\)

\(\frac{1}{6}\div\left(0,75+\frac{1}{6}\right)-50\%-1^2\)

\(=\frac{1}{6}\div\left(\frac{9}{12}+\frac{2}{12}\right)-\frac{1}{2}-1\)

\(=\frac{1}{6}\div\frac{11}{12}-\frac{1}{2}-\frac{2}{2}\)

\(=\frac{1}{6}.\frac{12}{11}-\frac{3}{2}\)

\(=\frac{2}{11}-\frac{3}{2}\)

\(=\frac{4}{22}-\frac{33}{22}\)

\(=\frac{-29}{22}\)