<=> 2x^2-x-(x^2-4x+4)=7

<=> x^2+3x-11=0

<=> 4x^2+12x=44

<=> (2x+3)^2=53

<=> 2x+3 = căn 53 hoặc - căn 53

<=> x=(căn 53-3)/2 hoặc x=(-căn 53-3)/2.

a) 27 : x -\(\frac{1}{2}=\frac{15}{7}:5\)

27 : x -\(\frac{1}{2}\)= \(\frac{3}{7}\)

27 : x = \(\frac{3}{7}+\frac{1}{2}\)

27 : x =\(\frac{6}{14}+\frac{7}{14}\)

27 : x = \(\frac{13}{14}\) 

x = 27 : \(\frac{13}{14}\)

x = 27 . \(\frac{14}{13}\)

x = \(\frac{378}{13}\)

b) 2 . x - \(\frac{3}{4}\)= \(\frac{15}{9}.\frac{3}{5}\)

2 . x - \(\frac{3}{4}\)= 1

2 . x  = 1 + \(\frac{3}{4}\)

2 . x = \(\frac{7}{4}\)

x = \(\frac{7}{4}:2\)

x = \(\frac{7}{8}\)

cho mình đúng nha

Bạn giỏi lắm Thảo Anh

*4/7x=9/8.0,125 

4/7x=9/8.1/8

4/7x=9/64

x    =9/64:4/7

x    =9/64.7/4

x    =63/256

*x-25%=1/2

x-1/4.x  =1/2

x(1-1/4) =1/2

3/4.x     =1/2

x           =1/2:3/4

x           =1/2.4/3

x           =2/3

\(\left(x-2\right)^{2018}=\left(x-2\right)^{2016}\)

=> \(\left(x-2\right)^{2018}-\left(x-2\right)^{2016}=0\)

=> \(\left(x-2\right)^{2016}\left(\left(x-2\right)^2-1\right)=0\)

=> \(\orbr{\begin{cases}\left(x-2\right)^{2016}=0\\\left(\left(x-2\right)^2-1\right)=0\end{cases}}\)

=> x = 2 

và (x - 2)² = 1 => x - 2 = 1 ; -1

=> x = 3 ; x = 1

=> x = 1 ; 2 ; 3

Ta có :

Số số hạng của tổng trên là :

\(\frac{2x-2}{2}+1=x-1+1=x\)

Tổng trên bằng :

\(\frac{\left(2x+2\right).x}{2}=\frac{2.\left(x+1\right).x}{2}=x.\left(x+1\right)=110=10.11\)

\(\Rightarrow x=10.\)

Vậy x = 10 .

Ai đó giúp mình đi mai phải nộp rồi giải sớm giùm nha

Mọi người ơi

   9 x 987 698 x 98 769

= 8 889 282 x 98 769

= 877 985 493 858

877985493858

ok bạn nhé

= 877985493858

Ta có : \(\left(3x-2\right)\left(4x+3\right)=\left(2-3x\right)\left(x-1\right)\)

\(\Leftrightarrow12x^2-8x+9x-6=2x-3x^2-2+3x\)

\(\Leftrightarrow12x^2-8x+9x-6-2x+3x^2+2-3x=0\)

\(\Leftrightarrow15x^2-4x-4=0\)​

\(\Leftrightarrow15x^2-10x+6x-4=0\)

Lỗi :vvvv

\(\Leftrightarrow10x\left(\dfrac{3}{2}x-1\right)+4\left(\dfrac{3}{2}x-1\right)=0\)

\(\Leftrightarrow\left(10x+4\right)\left(\dfrac{3}{2}x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2}{5}\\x=\dfrac{2}{3}\end{matrix}\right.\)

Vậy ...

(3x-2)(4x+3)=(2-3x)(x-1)

=(3x-2)(4x+3)-(2-3x)(x-1)

=(3x-2)(4x+3)+(3x-2)(x-1)

=(3x-2)(4x+3+x-1)

=(3x-2)(5x+2)

=15x²-10x-4+6x=15x²-4x-4

\(x.y+2y+x=6\)

\(\Rightarrow y.\left(x+2\right)+\left(x+2\right)-2=6\)

\(\Rightarrow y.\left(x+2\right)+\left(x+2\right)=8\)

\(\Rightarrow\left(x+2\right).\left(y+1\right)=8\)                  

\(\Rightarrow\left(x+2\right).\left(y+1\right)\inƯ\left(8\right)=\left\{1;2;4;8\right\}\) mà : \(x+2\ge2\)

\(\Rightarrow\) \(x+2=2\Rightarrow x=0\)

         \(y+1=4\Rightarrow y=3\)

\(\Rightarrow x=0;y=3\)