\(\dfrac{2}{1.4}x+\dfrac{2}{4.7}x+\dfrac{2}{7.10}x+...+\dfrac{2}{31.34}x=10\)

\(=>1,5.\left(\dfrac{2}{1.4}x+\dfrac{2}{4.7}x+\dfrac{2}{7.10}x+...+\dfrac{2}{31.34}x\right)=15\)

\(=>\dfrac{3}{1.4}x+\dfrac{3}{4.7}x+\dfrac{3}{7.10}x+...+\dfrac{3}{31.34}x=15\)

\(=>x\left(\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+...+\dfrac{3}{31.34}\right)=15\)

\(=>x\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+...+\dfrac{1}{31}-\dfrac{1}{34}\right)=15\)

\(=>x\left(1-\dfrac{1}{34}\right)=15\)

\(=>\dfrac{33}{34}x=15\)

\(=>x=\dfrac{170}{11}\)

Câu 1:

\(=\dfrac{21}{31}+\dfrac{1}{3}-\dfrac{44}{53}+\dfrac{10}{31}-\dfrac{9}{53}=\dfrac{1}{3}\)

Câu 2:

1: =>1,3x=-1,31

=>130x=-131

=>x=-131/130

2: =>(4,5-2x)=11/14:(-11/7)=-7/14=-1/2=-0,5

=>2x=5

=>x=5/2

Bài 1 :                                         Bài giải

\(-2\left(-3-4x\right)-3\left(3x-7\right)=31\)

\(6+8x-9x-21=31\)

\(-x-15=31\)

\(-x=31+15\)

\(-x=46\)

\(x=-46\)

b, \(10\left(x-7\right)=8\left(x-4\right)+x\)

\(10x-70=8x-32+x\)

\(10x-70=9x-32\)

\(10x-9x=-32+70\)

\(x=38\)

c, \(2\left|x-1\right|=3\cdot\left(5-1\right)\)

\(2\left|x-1\right|=15-3\)

\(2\left|x-1\right|=12\)
\(\left|x-1\right|=12\text{ : }2\)

\(\left|x-1\right|=6\)

\(\Rightarrow\orbr{\begin{cases}x-1=-6\\x-1=6\end{cases}}\Rightarrow\orbr{\begin{cases}x=-5\\x=7\end{cases}}\)

\(\Rightarrow\text{ }x\in\left\{-5\text{ ; }7\right\}\)

d, \(2\left(x+3\right)-2\left(x-3\right)=x\)

\(2\left(x+3-x-3\right)=x\)

\(2\cdot0=x\)

\(x=0\)

e, \(\left(x+3\right)\left(x-4\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+3=0\\x-4=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-3\\x=4\end{cases}}\)

\(\Rightarrow\text{ }x\in\left\{-3\text{ ; }4\right\}\)

a, \(-2\left(-3-4x\right)-3\left(3x-7\right)=31\)

\(6+8x-9x-21=31\)

\(-x-15=31\)

\(-x=31+15\)

\(-x=46\)

\(x=-46\)

b, \(10\left(x-7\right)=8\left(x-4\right)+x\)

\(10x-70=8x-32+x\)

\(10x-70=9x-32\)

\(10x-9x=-32+70\)

\(x=38\)

c, \(2\left|x-1\right|=3\cdot\left(5-1\right)\)

\(2\left|x-1\right|=15-3\)

\(2\left|x-1\right|=12\)
\(\left|x-1\right|=12\text{ : }2\)

\(\left|x-1\right|=6\)

\(\Rightarrow\orbr{\begin{cases}x-1=-6\\x-1=6\end{cases}}\Rightarrow\orbr{\begin{cases}x=-5\\x=7\end{cases}}\)

\(\Rightarrow\text{ }x\in\left\{-5\text{ ; }7\right\}\)

d, \(2\left(x+3\right)-2\left(x-3\right)=x\)

\(2\left(x+3-x-3\right)=x\)

\(2\cdot0=x\)

\(x=0\)

e, \(\left(x+3\right)\left(x-4\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+3=0\\x-4=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-3\\x=4\end{cases}}\)

\(\Rightarrow\text{ }x\in\left\{-3\text{ ; }4\right\}\)

A) x=19
B) x= hình như sai đề

a) 10 + 2x = 16.4 : 4

=> 10 + 2x = 16

2x = 16 - 10 

2x = 6

x = 6:2 = 3

b) 231 - ( x - 6 ) = 1339 : 13

=> 231 - ( x - 6 ) = 103

( x - 6 ) = 231 - 103 

x - 6 = 128

x = 128 + 6

x = 134

a)\(\frac{5}{7}:X=1-\frac{4}{7}=\frac{3}{7}\)

\(X=\frac{5}{7}:\frac{3}{7}=\frac{5}{3}\)

b)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{19}-\frac{1}{21}\right)-X=\frac{4}{3}-\frac{221}{231}=\frac{29}{77}\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)-X=\frac{29}{77}\)

\(X=\frac{10}{231}-\frac{29}{77}=-\frac{1}{3}\)

xem xong nhớ tích

A, 11/12

B, 12,6

a,

x- 7/12 = 1/3

x = 1/3 + 7/12

x = 11/12

b,

x + 31/10 = 14,5

x = 14,5 - 31/10

x = 57/5

\(a,\\ x=\dfrac{1}{3}+\dfrac{7}{12}=\dfrac{11}{12}\\ b,\\ x+\dfrac{31}{10}=\dfrac{157}{10}\\ x=\dfrac{157}{10}-\dfrac{31}{10}=\dfrac{63}{5}\)