mk sắp phải đi học rồi các bạn giúp mình với có đc ko mk nhớ sẽ đền đáp công ơn của bạn 

a) (5 - x) +12 = -25

<-> 5 - x + 12 = -25

<-> 17 - x = - 25

<-> x = 42

b) 12 - 4(x - 2) = -4

<-> 12 - 4x + 8 = -4

<-> 20 - 4x = -4

<-> 4x = 24

<-> x = 6

a) (5 - x) + 12 = -25

<=> -x = -25 - 12 - 5

<=> -x = -42

<=> x = 42

b) 12 - 4(x - 2) = -4

<=> 12 - 4x + 8 = -4

<=> -4x = -4 - 8 - 12

<=> -4x = -24

<=> x = 6

c) -15 - |3 - x| = -19

<=> -|3 - x| = -4

<=> 3 - x = 4 hoặc 3 - x = -4

<=> x = -1 hoặc x = 7

\(\frac{4\sqrt{7}-5}{20}\)

\(\left(x+\frac{1}{4}\right)^2+\frac{11}{25}=\frac{18}{25}\)

\(\Rightarrow\left(x+\frac{1}{4}\right)^2=\frac{7}{25}\)

\(\Rightarrow x+\frac{1}{4}=\hept{\begin{cases}\sqrt{\frac{7}{25}}\\-\sqrt{\frac{7}{25}}\end{cases}}\)

\(\Rightarrow x=\hept{\begin{cases}\sqrt{\frac{7}{25}}-\frac{1}{4}\\-\sqrt{\frac{7}{25}}-\frac{1}{4}\end{cases}}\)

\(\frac{x+3}{97}+\frac{x+5}{95}+\frac{x+4}{96}+\frac{x+1}{99}=-4\)

\(\left(\frac{x+3}{97}+1\right)+\left(\frac{x+5}{95}+1\right)+\left(\frac{x+4}{96}+1\right)+\left(\frac{x+1}{99}+1\right)=-4+4\)

\(\frac{x+100}{97}+\frac{x+100}{95}+\frac{x+100}{96}+\frac{x+100}{99}=0\)

\(\left(x+100\right).\left(\frac{1}{97}+\frac{1}{95}+\frac{1}{96}+\frac{1}{99}\right)=0\)

=> \(\orbr{\begin{cases}x+100=0\\\frac{1}{97}+\frac{1}{95}+\frac{1}{96}+\frac{1}{99}=0\end{cases}}\)

Mà \(\frac{1}{97}+\frac{1}{95}+\frac{1}{96}+\frac{1}{99}\ne0\)

=> x + 100 = 0

=> x = -100

Vậy x = -100

Câu b trừ mỗi số đi 1 tức là trừ cả cụm đó cho 3 rùi lm tương tự câu a

a) \(\frac{5+x}{4-x}=\frac{1}{2}\)

10 + 2x = 4 - x

10 - 4 = -x - 2x

6 = -3x

=> x = 6/-3 = -2

b) \(\frac{25}{14}=\frac{x+7}{x-4}\)

25x - 100 = 14x + 98

25x - 14x = 98 + 100

11x = 198

=> x = 198/11 = 18

a,

x.2/7.3/4=5/21

x.3/14=5/21

x=5/21:3/14

x=10/9

b, 

x.1/2=1/3

x=1/3:1/2

x=2/3

c,

x:4/5=25/8:5/4

x:4/5=5/2

x=5/2.4/5=2

A, x= 5/25 : 3/4 : 2/7 = 14/15

B, x=1/3 : 1/2 = 2/3

C, x=(25/8 : 5/4)x4/5 = 5/2 x 4/5 = 2