\(\frac{\frac{4}{25}}{-x}=\frac{x}{\frac{1}{4}}\) tìm x
Tìm x
a)\(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
b)\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
TÌM x:
a,(5-x)+12=-25
b,12-4.(x-2)=-4
c,-15-/3-x/=-19
d,\(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2.x\right)=-4\)
e,\(\left(x+\frac{1}{5}\right)m\text{ũ}2+\frac{17}{25}=\frac{26}{25}\)\
f,\(\frac{x}{3}+\frac{x}{7}=\frac{1}{7}+\frac{3}{14}\)
mk sắp phải đi học rồi các bạn giúp mình với có đc ko mk nhớ sẽ đền đáp công ơn của bạn
a) (5 - x) +12 = -25
<-> 5 - x + 12 = -25
<-> 17 - x = - 25
<-> x = 42
b) 12 - 4(x - 2) = -4
<-> 12 - 4x + 8 = -4
<-> 20 - 4x = -4
<-> 4x = 24
<-> x = 6
a) (5 - x) + 12 = -25
<=> -x = -25 - 12 - 5
<=> -x = -42
<=> x = 42
b) 12 - 4(x - 2) = -4
<=> 12 - 4x + 8 = -4
<=> -4x = -4 - 8 - 12
<=> -4x = -24
<=> x = 6
c) -15 - |3 - x| = -19
<=> -|3 - x| = -4
<=> 3 - x = 4 hoặc 3 - x = -4
<=> x = -1 hoặc x = 7
1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y
2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x
3) \(\frac{8.x+18}{2.x+6}\)Tìm x
Tìm x, biết : \(\left[\frac{45\frac{10}{63}-44\frac{25}{84}}{\left(2\frac{1}{3}-1\frac{1}{9}\right):4-\frac{3}{4}}:31\right].x=-\frac{1}{16}\)
\((x+\frac{1}{4})^2+\frac{11}{25}=\frac{18}{25}\)
TÌM X
\(\left(x+\frac{1}{4}\right)^2+\frac{11}{25}=\frac{18}{25}\)
\(\Rightarrow\left(x+\frac{1}{4}\right)^2=\frac{7}{25}\)
\(\Rightarrow x+\frac{1}{4}=\hept{\begin{cases}\sqrt{\frac{7}{25}}\\-\sqrt{\frac{7}{25}}\end{cases}}\)
\(\Rightarrow x=\hept{\begin{cases}\sqrt{\frac{7}{25}}-\frac{1}{4}\\-\sqrt{\frac{7}{25}}-\frac{1}{4}\end{cases}}\)
Tìm x, biết :
\(\frac{x+3}{97}+\frac{x+5}{95}+\frac{x+4}{96}+\frac{x+1}{99}=-4\)
\(\frac{x-5}{1995}+\frac{x-15}{1985}+\frac{x-25}{1975}=3\)
\(\frac{x+3}{97}+\frac{x+5}{95}+\frac{x+4}{96}+\frac{x+1}{99}=-4\)
\(\left(\frac{x+3}{97}+1\right)+\left(\frac{x+5}{95}+1\right)+\left(\frac{x+4}{96}+1\right)+\left(\frac{x+1}{99}+1\right)=-4+4\)
\(\frac{x+100}{97}+\frac{x+100}{95}+\frac{x+100}{96}+\frac{x+100}{99}=0\)
\(\left(x+100\right).\left(\frac{1}{97}+\frac{1}{95}+\frac{1}{96}+\frac{1}{99}\right)=0\)
=> \(\orbr{\begin{cases}x+100=0\\\frac{1}{97}+\frac{1}{95}+\frac{1}{96}+\frac{1}{99}=0\end{cases}}\)
Mà \(\frac{1}{97}+\frac{1}{95}+\frac{1}{96}+\frac{1}{99}\ne0\)
=> x + 100 = 0
=> x = -100
Vậy x = -100
Câu b trừ mỗi số đi 1 tức là trừ cả cụm đó cho 3 rùi lm tương tự câu a
Tìm x:
a) \(\frac{5+x}{4-x}=\frac{1}{2}\)
b) \(\frac{25}{14}=\frac{x+7}{x-4}\)
a) \(\frac{5+x}{4-x}=\frac{1}{2}\)
10 + 2x = 4 - x
10 - 4 = -x - 2x
6 = -3x
=> x = 6/-3 = -2
b) \(\frac{25}{14}=\frac{x+7}{x-4}\)
25x - 100 = 14x + 98
25x - 14x = 98 + 100
11x = 198
=> x = 198/11 = 18
Tìm X biết
a) \(x\cdot\frac{2}{7}\cdot\frac{3}{4}=\frac{5}{21}\)
b) \(x\cdot\frac{1}{2}=\frac{1}{3}\)
c) \(x:\frac{4}{5}=\frac{25}{8}:\frac{5}{4}\)
a,
x.2/7.3/4=5/21
x.3/14=5/21
x=5/21:3/14
x=10/9
b,
x.1/2=1/3
x=1/3:1/2
x=2/3
c,
x:4/5=25/8:5/4
x:4/5=5/2
x=5/2.4/5=2
A, x= 5/25 : 3/4 : 2/7 = 14/15
B, x=1/3 : 1/2 = 2/3
C, x=(25/8 : 5/4)x4/5 = 5/2 x 4/5 = 2
tìm x biết:
\(\left(\frac{45\frac{10}{63}-44\frac{25}{84}}{\left(2\frac{1}{3}-1\frac{1}{9}\right):4-\frac{3}{4}}:31\right).x=\frac{-1}{16}\)