425 −x =x14
-X x X = \(\frac{4}{25}.\frac{1}{4}\)-X = \(\frac{1}{25}\)
X = \(-\frac{1}{25}\)Cho mình sửa lại đề bài
\(\frac{4}{\frac{25}{-x}}=\frac{x}{\frac{1}{4}}\)
425 −x =x14
-X x X = \(\frac{4}{25}.\frac{1}{4}\)-X = \(\frac{1}{25}\)
X = \(-\frac{1}{25}\)Cho mình sửa lại đề bài
\(\frac{4}{\frac{25}{-x}}=\frac{x}{\frac{1}{4}}\)
tìm x biết:
\(\left(\frac{45\frac{10}{63}-44\frac{25}{84}}{\left(2\frac{1}{3}-1\frac{1}{9}\right):4-\frac{3}{4}}:31\right).x=\frac{-1}{16}\)
tìm x biết:
\(\left[\frac{45\frac{10}{63}-44\frac{25}{84}}{\left(2\frac{1}{3}-1\frac{1}{9}\right):4-\frac{3}{4}}:31\right].x=-\frac{1}{16}\)
tìm x,biết:
a)\(\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+8\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right)\left(x+14\right)}\)
b)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
c)\(\left(x+2\right)^2=\frac{38}{25}+\frac{9}{10}-\frac{11}{15}+\frac{13}{21}-\frac{15}{28}+\frac{17}{36}-...+\frac{197}{4851}-\frac{199}{4950}\)
giúp tớ với,huhu
\(\frac{59-x}{41}+\frac{57-x}{43}+\frac{55-x}{45}+\frac{53-x}{47}+\frac{51-x}{49}=-5\) tìm x
\(\frac{x-5}{1990}+\frac{x-15}{1980}+\frac{x-25}{1970}=\frac{x-1990}{5}+\frac{x-1980}{15}+\frac{x-1970}{25}\) tìm x
\(\frac{x+14}{86}+\frac{x+15}{85}+\frac{x+16}{84}+\frac{x+17}{83}+\frac{x+116}{4}=0\) tìm x
Bài 1: Tìm x thuộc Q, biết
1, \(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
2,\(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}\)
3, \(\frac{x-90}{10}+\frac{x-85}{15}=\frac{x-80}{20}+\frac{x-75}{25}\)
4,\(\frac{x+3}{7}+\frac{x+2}{8}+\frac{x+1}{9}=-3\)
CÁC BN GIÚP MK NHA AI NHANH MK TICK CHO THANKS
Tìm x:
a)\(\left(x-1\right)^2=\frac{9}{25}\)
b)\(\frac{1}{2}-\frac{1}{3}x=\frac{4}{5}\)
Tìm x;y thuộc N :
25 - y2=8(x - 2009)2
Tìm x thuộc Z biết:
a)\(2x+\frac{1}{7}=\frac{1}{y}\)
b)\(\frac{5}{x}+\frac{y}{4}=\frac{1}{8}\)
c)\(\frac{x}{8}-\frac{1}{y}=\frac{1}{4}\)
Tìm x biết
\(\frac{1}{2}\left(\frac{3}{4}x-\frac{1}{2}\right)^{2012}+\frac{2017}{2016}\frac{20x+6}{25}\)nhỏ hơn bằng 0
tìm x
a) ( 152\(\frac{2}{4}\)-148\(\frac{3}{8}\)) : 0,2 = X : 0,3
b) ( (6\(\frac{3}{5}\)-3\(\frac{3}{14}\)) -2,5 ) : ( 21-1,25) = X : 5\(\frac{5}{6}\)
c) (4-\(\frac{3}{4}\)) : ( 2\(\frac{1}{3}\)-1\(\frac{1}{9}\)) = 31. X : ( 45\(\frac{-10}{63}\)-44\(\frac{25}{84}\))
d) \(\frac{2.X+3}{5.X+2}\)=\(\frac{3.X-4}{7}\)
e) \(\frac{3.X-1}{40-5.X}\)=\(\frac{25-3.X}{5.X-34}\)