Cộng cả x và y với 1 ta được

x + 1 = \(\frac{-357}{352}+1=\frac{-5}{352}\)< \(\frac{-1}{352}\)

y + 1 = \(\frac{-1000}{999}+1=\frac{-1}{999}\)>\(\frac{-1}{352}\)

Như vậy x + 1 < y + 1 hay x < y

a) Ta có:

-1/10 < 0

1/1000 > 0

=> -1/10 < 1/1000

b) Ta có:

357/358 < 1

1000 / 999  > 1

=> 357/358  < 1000/999

=> -357/358  > -1000/999

c) -151515/313131 = -15/31

Vậy -15/13 = -151515/313131

Ta so sánh hai phân số \(\frac{2010}{2011}\)và \(\frac{1000}{999}\)có :

\(\frac{2010}{2011}< \frac{1000}{999}\)

\(\Rightarrow\left(\frac{-2010}{2011}\right)>\left(\frac{-1000}{999}\right)\)

Vậy ...

1 - \(\frac{999}{556}\) = \(\frac{-443}{556}\)

1 - \(\frac{1000}{557}\) = \(\frac{-443}{557}\)

Vì \(\frac{-443}{556}\) < \(\frac{-443}{557}\) nên \(\frac{999}{556}\) > \(\frac{1000}{557}\)

First we have :

\(\frac{999}{556}=\frac{999\cdot557}{556\cdot557}\)

Then : \(999\cdot557=999\cdot556+999\)

Next we have : \(1000\cdot556=999\cdot556+556\)

As you see : \(999\cdot556+556< 999\cdot556+999\)

So :\(\frac{999}{556}< \frac{1000}{557}\)

Nhầm : \(\frac{999}{556}>\frac{1000}{557}\)

Ta có :

\(C=\frac{1}{4}+\frac{1}{4^2}+.....+\frac{1}{4^{1000}}\)

\(\Rightarrow4C=1+\frac{1}{4}+.....+\frac{1}{4^{1999}}\)

\(\Rightarrow4C-C=\left(1+\frac{1}{4}+.....+\frac{1}{4^{1999}}\right)-\left(\frac{1}{4}+\frac{1}{4^2}+.....+\frac{1}{4^{1000}}\right)\)

\(\Rightarrow3C=1-\frac{1}{4^{1000}}\)

\(\Rightarrow C=\frac{1}{3}-\frac{1}{3.4^{1000}}< \frac{1}{3}\)

=> C < 1 / 3

Ta có:

\(C=\frac{1}{4}+\frac{1}{4^2}+...+\frac{1}{4^{1000}}\)

\(\Rightarrow4C=1+\frac{1}{4}+...+\frac{1}{4^{999}}\)

\(\Rightarrow4C-C=\left(1+\frac{1}{4}+\frac{1}{4^2}+...+\frac{1}{4^{999}}\right)-\left(\frac{1}{4}+\frac{1}{4^2}+...+\frac{1}{4^{999}}+\frac{1}{4^{1000}}\right)\)

\(\Rightarrow3C=1-\frac{1}{4^{1000}}\)

\(\Rightarrow C=\left(1-\frac{1}{4^{1000}}\right).\frac{1}{3}\)

\(\Rightarrow C=\frac{1}{3}-\frac{1}{4^{1000}.3}\)

Mà \(\frac{1}{3}>\frac{1}{3}-\frac{1}{4^{1000}.3}\)

\(\Rightarrow C< \frac{1}{3}\)

Vậy \(C< \frac{1}{3}\)

Dùng cách SO SÁNH PHẦN HƠN nha bạn :)

Ta có: \(\frac{999}{556}-1=\frac{143}{556}\)

\(\frac{1000}{557}-1=\frac{143}{557}\)

Vì \(\frac{143}{556}>\frac{143}{557}\)nên \(\frac{999}{556}>\frac{1000}{557}\)<=> x>y