\(x-\frac{25x}{100}=60-x+\frac{25x}{100}\)
TÌM X:
\(x-\left(\frac{50x}{100}+\frac{25x}{100}\right)=11\frac{1}{4}\)
\(x-\left(\frac{50x}{100}+\frac{25x}{100}\right)=\frac{45}{4}\)
\(x-\left(\frac{50x+25x}{100}\right)=\frac{45}{4}\)
\(x-\frac{75x}{100}=\frac{45}{4}\)
\(x-x\times\frac{3}{4}=\frac{45}{4}\)
\(x\times\left(1-\frac{3}{4}\right)=\frac{45}{4}\)
\(x\times\frac{1}{4}=\frac{45}{4}\)
\(x=\frac{45}{4}\div\frac{1}{4}\)
\(x=45\)
\(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=\frac{45}{4}\)
\(x-\left(\frac{100x}{200}+\frac{25x}{200}\right)=\frac{45}{4}\)
\(x-\left(\frac{100x+25x}{200}\right)=\frac{45}{4}\)
\(x-\frac{125x}{200}=\frac{45}{4}\)
\(x-x\frac{5}{8}=\frac{45}{4}\)
\(x\left(1-\frac{5}{8}\right)=\frac{45}{4}\)
\(x.\frac{3}{8}=\frac{45}{4}\)
\(x\)=\(\frac{45}{4}:\frac{3}{8}\)
\(x\)=\(30\)
tìm x
x - \(\dfrac{25x}{100}\)= 60 -x+\(\dfrac{25x}{100}\)
x-(60-x)=25x/100+25x/100
x-60+x=25x+25x/100
x-60+x=x(25+25)/100
x-60+x=x.50/100
x-60+x=x.50/50.2
x-60+x=x/2
.....
tới đây thui, mình ko biết làm nữa
ko biết là đúng hay sai đâu nhoa
tìm x biết rằng :
a) x - \(\left(\frac{50x}{100}+\frac{25x}{200}\right)=11\frac{1}{4}\) c) ( x - 5 ) . \(\frac{30}{100}=\frac{20x}{100}+5\)
a) x-\(\left(\frac{50x}{100}+\frac{25x}{200}\right)\)=\(11\frac{1}{4}\)
<=>x - \(\frac{1}{2}x-\frac{1}{8}x\)=\(\frac{11.4+1}{4}\)
<=>\(\frac{3}{8}x=\frac{45}{4}\)
<=>x=\(\frac{45}{4}:\frac{3}{8}\)
<=>x=30
Vậy x=30
c) (x-5).\(\frac{30}{100}\)=\(\frac{20x}{100}+5\)
<=>(x-5).\(\frac{3}{10}\)=\(\frac{x}{5}\)+5
<=>\(\frac{3x}{10}-\frac{15}{10}=\frac{x}{5}+5\)
<=>\(\frac{3x}{10}-\frac{x}{5}=5+\frac{15}{10}\)
<=>\(\frac{x}{10}=\frac{13}{2}\)
<=>x=\(\frac{13.10}{2}\)
<=>x=65
Vậy: x=65
Tìm x:
a) x - (\(\frac{50x}{100}\) + \(\frac{25x}{100}\)) = \(11\frac{1}{4}\)
b) (x-5) . \(\frac{30}{100}\) = \(\frac{200x}{100}\) + 5
- Help me!.
Tìm x:
a) \(x-\left(\frac{50x}{160}+\frac{25x}{200}\right)=11\frac{1}{4}\)
b)\(\left(x-5\right)\cdot\frac{30}{100}=\frac{200x}{100}+5\)
Giúp mình nhanh với, cảm ơn các bạn rất nhiều!
Tìm x:
a) x - (\(\frac{50x}{100}+\frac{25x}{200}\)) = \(11\frac{1}{4}\)
b) (x - 5) . \(\frac{30}{100}\) = \(\frac{200x}{100}\) + 5
Tính M=x100-25x99+25x98-25x97+25x96-................-25x3+25x2-25x+25 tại x = 24
x=24
=> x+1=25
=> M=x100-(x+1)x99+(x+1)x98-(x+1)x97+(x+1)x96-...-(x+1)x3+(x+1)x2-(x+1)x+25
=x100-x100-x99+x99+x98-x98-x97+x97+x96-...-x4-x3+x3+x2-x2-x+25
=-x+25
=-24+25
=1
Vậy M=1.
Tìm x:
x-(\(\frac{50x}{100}\)+ \(\frac{25x}{200}\))=\(\frac{45}{4}\)
giải lun nha
x-(4x/8+1x/8)=45/4
x-5x/8=45/4
-4x=45/4.8
-4x=90
x=90/(-4)
x=22,5
nếu đúng thì cho mk **** nha mk đang cần
Bài 1:
\(a,\dfrac{62}{7}.x=\dfrac{29}{9}:\dfrac{3}{56}\)
\(b,\dfrac{1}{5}:x=\dfrac{1}{5}-\dfrac{1}{7}\)
\(c,x-\left(\dfrac{50x}{100}+\dfrac{25x}{200}\right)=11\dfrac{1}{4}\)(11 và 1/4 là hỗn số chứ ko phải là 11.1/4 các bn nhé)
\(d,x-\dfrac{25x}{100}=60-x+\dfrac{25x}{100}\)
\(b,\dfrac{1}{5}:x=\dfrac{1}{5}-\dfrac{1}{7}\)
\(\dfrac{1}{5}:x=\dfrac{7}{35}-\dfrac{5}{35}\)
\(\dfrac{1}{5}:x=\dfrac{2}{35}\)
\(x=\dfrac{1}{5}:\dfrac{2}{35}\)
\(x=\dfrac{1}{5}.\dfrac{35}{2}\)
\(x=\dfrac{7}{2}\)