8^3-2.(x-1)=4096

512.2.(x-1)=4096

       2.(x-1)=4096:512

       2.(x-1)=8

           x-1=8:2

           x-1=4

           x    =4+1

           x     =5

\(\left(325-317\right)^3-2\left(x-1\right)=2^{18}:8^2.\)

\(\left(325-317\right)^3-2\left(x-1\right)=2^{18}:\left(2^3\right)^2\)

\(\left(325-317\right)^3-2\left(x-1\right)=2^{18}:2^6\)

\(\left(325-317\right)^3-2\left(x-1\right)=2^{12}\)

\(8^3-2\left(x-1\right)=2^{12}\)

\(\left(2^3\right)^3-2\left(x-1\right)=2^{12}\)

\(2^9-2\left(x-1\right)=2^{12}\)

\(2\left(x-1\right)=2^9-2^{12}\)

\(2\left(x-1\right)=-3584\)

\(\left(x-1\right)=-2584:2\)

\(x-1=-1792\)

\(x=-1792+1\)

\(x=-1791\)

ket qua ban nào là đúng

(325 - 317)³-2 . (x - 1)=4096

=8³-2.(x - 1) =4096

sorry bn .mk cứ tưởng                  ^ _ ^

a)437+541+463-341

=(437+463)+(541-341)

=900+200

=1100

\(325-5\left[4^3-\left(27-5^2\right)\cdot1^{18}\right]\\ =325-5\left[64-\left(27-25\right)\cdot1\right]\\ =325-5\left(64-2\right)=325-5\cdot62=325-310=15\)

\(325-5\left[4^3-\left(27-5^2\right).1^{18}\right]\)

\(=325-5\left[64-\left(27-25\right).1\right]\)

\(=325-5\left[64-2.1\right]\)

\(=325-5.62\)

\(=325-124\)

\(=201\)

Tìm x

\(\text{a.-(-3-x+8)-(-3+5)=|5-8| }\)

\(3+x-8+3-5=\)\(\left|-3\right|\)

\(3+x-8+3-5=\)\(3\)

\(x=\)\(\text{3+5-3+8-3}\)

\(\text{x=10}\)

B.\(\text{43+(9-21)=317-(x+317)}\)

\(43+9-21\)\(=317-x-317\)

\(50-21=\left(317-317\right)\)\(-x\)

\(29=0-x\)

\(29=-x\)

\(\Rightarrow x=-29\)

c,3(x-2)-2(x-4)=-12-2

3x -6 -2x -8= -12

(3x-2x) - (6+8) =-14

x-14=-14

x=-14+14

x=0

Bạn tính SLS của tổng S rồi chia 2 nhân với 325+1 là ra

nhóm 4 số vào rồi tính,tiếp tục là tính GTLN của S

_{5458775553535}658

Bài 2: 

a: \(\left(6x-39\right):7=3\)

\(\Leftrightarrow6x-39=21\)

hay x=10

a) 2x-12=18                   x=3

2x - 12 = 18................................

2x = 30 ........................................

x = 15.....................................

2x - 12 = 18................................

2x = 30 ........................................

x = 15.....................................