( x - 3 ) 126 = 4 50 . 8 8 . 2 2
Bài 1: Tính nhanh
A, 13 x 126 + 37 x 126 - 49 x 126
B, ( 1 + 2 + 4 + 8+.....+ 512 ) x ( 101 x 102 - 101 x 101 - 50 - 51 )
Bài 1: Tính nhanh
A, 13 x 126 + 37 x 126 - 49 x 126
= 126 x ( 13 + 49 - 49 )
= 126 x 1
= 126
B, ( 1 + 2 + 4 + 8+.....+ 512 ) x ( 101 x 102 - 101 x 101 - 50 - 51 )
= ( 1 + 2 + 4 + 8+.....+ 512 ) x ( 101 x ( 102 - 101 - 1))
= ( 1 + 2 + 4 + 8+.....+ 512 ) x ( 101 x 0)
= ( 1 + 2 + 4 + 8+.....+ 512 ) x 0
= 0
Bài 8. Tìm số nguyên x
1) x – 12 = (-8) + (-17) 2) (7 – x) – 5 = - 13 3) 7 – 3x = 28 4) 2(x + 1) + 18 = - 4 | 5) 37 – x = 12 6) x + 5 = -18 7) 27 – (x + 1) = 2. (52 – 24) 8) (x – 3)(x + 3) = 0
|
1) x-12=(-8)+(-17)
x-12=(-25)
x = (-25)+12
x = (-13)
(2 điểm) Tính nhanh
a. 4 x 126 x 25
b. (9 x 8 – 12 – 5 x 12) x ( 1 + 2 + 3 + 4 + 5)
a. 4 x 126 x 25
= (4 x 25) x 126
= 100 x 126
= 12600
b. (9 x 8 – 12 – 5 x 12) x ( 1 + 2 + 3 + 4 + 5)
= (72 – 12 – 60) x ( 1 + 2 + 3 + 4 + 5)
= 0 x ( 1 + 2 + 3 + 4 + 5)
= 0
Tính nhanh:
a) 4 x 126 x 25
b) ( 9 x 8 – 12 – 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5)
a, x-1/4=5/8 . 2/3
b, x/126= -5/4 .4/7
câu a x =2/3
câu b x=-90
a, x-1/4=5/8 . 2/3
\(x-\frac{1}{4}=\frac{5}{12}\)
x = \(\frac{5}{12}+\frac{1}{4}\)
x = \(\frac{2}{3}\)
b, x/126= -5/4 .4/7
\(\frac{x}{126}=\frac{-5}{7}\)
=> x .7 = (-5) . 126
=> x . 7 = -630
=> x = (-630) :7
=> x = -90
Học tốt
\(x-\frac{1}{4}=\frac{5}{8}.\frac{2}{3}\)
\(x-\frac{1}{4}=\frac{5}{12}\)
\(x=\frac{5}{12}+\frac{1}{4}\)
\(x=\frac{2}{3}\)
\(\frac{x}{126}=\frac{-5}{4}.\frac{4}{7}\)
\(\frac{x}{126}=\frac{-5}{7}\)
\(\Rightarrow7x=-630\)
\(x=-630:7\)
\(x=-90\)
Giải pt sau với \(\alpha\)là tham số ; x là ẩn
\(\alpha\frac{9x^8+84x^6+126x^4+36x^2+1}{x^8+36x^6+126x^4+84x^2+9}+x\frac{9\alpha^8+84\alpha^6+126\alpha^4+36\alpha^2+1}{\alpha^8+36\alpha^6+126\alpha^4+84\alpha^2+9}=0\)
\(\Leftrightarrow\frac{\left(x+a\right)\left(3a^2x^2+a^2+8ax+x^2+3\right)\left(3a^6x^6+27a^6x^4+33a^6x2+a^6+72a^5x^5+24a^5x^3+72a^{5x}+27a^4x^6+459a^4x^4+441a^4x^2+33a^4+240a^3x^5+800a^3x^3+240a^3x+33a^2x^6+441a^2x^4+459x^2a^2+27a^2+75ax^5+240ax^3+72ax+x^6+33x^4+27x^2+3\right)}{\left(a^2+3\right)\left(a^6+33a^4+27a^{2+3}\right)\left(x^{2+3}\right)\left(x^6+33x^4+27x^2+3\right)}=0\)
mấy nhân tử sau ko cần chú ý đâu :)) chỉ cần chú ý đến x+a=0 <=>x=-a thôi :))
bài này đúng 100% nhé chỉ sợ gõ sai thôi, ko tin có thể dùng máy tính kiểm tra
Tìm x, biết:
a) x-1/4=5/8*2/3
b) x/126=-5/9*4/7
a, => x- 1/4 = 5/12
=> x = 5/12 + 1/4
=> x = 2/3
b, => x/126 = -20/ 63
=> x/126 = -40/126
=> x = -40
Tính nhanh.
a) (-4).(-8).(-17).(-25).125
b) (236 – 362) – (638 + 463)
c) (- 325 – 147) – ( - 625 + 853) – (-96)
d) 69.(- 47) – 31. (- 47)
e) 98. (- 37) + (- 49).126
f) – 35. (49 – 125) – 125 .(35 – 49)
g) 2 + 4 – 6 – 8 + 10 + 12 – 14 – 16 + …+ 90 + 92 – 94 – 96
h) 1 + 3 + 3 2 + 3 3 + ….+ 3 50
4 x 125 x 25 x 8
2 x 8 x 50 x 25 x 125
2 x 3 x 4 x 5 x 50 x 25
25 x 20 x 125 x 8 - 8 x 20 x 5 x 125