xy(x+y)+yz(y+z)+xz(x+z)+2xyz 

= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz 

= xy(x + y) + yz(y + z + x) + xz(x + z + y) 

= xy(x + y) + z(x + y + z)(y + x) 

= (x + y)(xy + zx + zy + z²) 

= (x + y)[x(y + z) + z(y + z)] 

= (x + y)(y + z)(z + x)

 xy(x+y)+yz(y+z)+xz(x+z)+2xyz 

= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz 

= xy(x + y) + yz(y + z + x) + xz(x + z + y) 

= xy(x + y) + z(x + y + z)(y + x) 

= (x + y)(xy + zx + zy + z²) 

= (x + y)[x(y + z) + z(y + z)] 

= (x + y)(y + z)(z + x)

.

.

.

 xy(x+y)+yz(y+z)+xz(x+z)+2xyz 

= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz 

= xy(x + y) + yz(y + z + x) + xz(x + z + y) 

= xy(x + y) + z(x + y + z)(y + x) 

= (x + y)(xy + zx + zy + z²) 

= (x + y)[x(y + z) + z(y + z)] 

= (x + y)(y + z)(z + x)

\(xy\left(x-y\right)+yz\left(y-z\right)+xz\left(z-x\right)\)

\(=xy\left(x-y\right)+yz\left[\left(y-x\right)-\left(z-x\right)\right]+xz\left(z-x\right)\)

\(=xy\left(x-y\right)-yz\left(x-y\right)-yz\left(z-x\right)+xz\left(z-x\right)\)

\(=\left(x-y\right)\left(xy-yz\right)-\left(z-x\right)\left(yz-xz\right)\)

\(=\left(x-y\right)\left(xy-yz\right)+\left(z-x\right)\left(xz-yz\right)\)

\(=\left(xy-yz\right)\left(x-y+z-x\right)\)

\(=\left(xy-yz\right)\left(-y+z\right)\)

mơn bn nha ^^

nh sáng nay lên lp thầy chữa bài thì kq nó k như z, cả cách lm nx :v

kq là: ( z - y )( x - z)( y - x )

[ вơ đắйǥ ] вé เςë ⁀ᶜᵘᵗᵉ

Ukm cảm ơn nhé quên mất đoạn cuối vẫn phân tích đc nữa

xy(x-y)+yz(y-z)+xz(x-z)

=y.[x.(x-y)+z.(y-z)]+xz(x-z)

=y.(x²-xy+zy-z²)+xz.(x-z)

=y.[(x²-z²)+(-xy+zy)]+xz.(x-z)

=y.[(x-z)(x+z)-y.(x-z)]+xz.(x-z)

=y.(x-z)(x+z-y)+xz.(x-z)

=(x-z)[y.(x+z-y)+xz]

=(x-z)(xy+yz-y²+xz)

xy(x+y)+yz(y+z)+xz(x+z)+2xyz 
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz 
= xy(x + y) + yz(y + z + x) + xz(x + z + y) 
= xy(x + y) + z(x + y + z)(y + x) 
= (x + y)(xy + zx + zy + z²) 
= (x + y)[x(y + z) + z(y + z)] 
= (x + y)(y + z)(z + x)

xy(x+y)+yz(y+z)+xz(x+z)+2xyz 
= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz 

= xy(x + y) + yz(y + z + x) + xz(x + z + y) 

= xy(x + y) + z(x + y + z)(y + x) 

= (x + y)(xy + zx + zy + z²) 

= (x + y)[x(y + z) + z(y + z)] 

= (x + y)(y + z)(z + x)

nhu the nay:

   ( xy( x + y )+ xyz )+( yz( y + z )+ xyz )+( xz( a +c )+ xyz)

= xy( x+y+z )+ yz( x + y + z )+ xz( x + y + z )

= ( x + y + z)( xy + yz +zx )

xong rui do dung thi ****.

xy(x+y)+yz(y+z)+xz(x+z)+2xyz 

= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz 

= xy(x + y) + yz(y + z + x) + xz(x + z + y) 

= xy(x + y) + z(x + y + z)(y + x) 

= (x + y)(xy + zx + zy + z²) 

= (x + y)[x(y + z) + z(y + z)] 

= (x + y)(y + z)(z + x)

xy(x+y)+yz(y+z)+xz(x+z)+2xyz 

= xy(x + y) + yz(y + z) + xyz + xz(x + z) + xyz 

= xy(x + y) + yz(y + z + x) + xz(x + z + y) 

= xy(x + y) + z(x + y + z)(y + x) 

= (x + y)(xy + zx + zy + z²) 

= (x + y)[x(y + z) + z(y + z)] 

= (x + y)(y + z)(z + x)

Cách 1 :  

Ta có : yz(y + z) + xz(z - x) - xy(x + y)

= yz(y + z) + xz² - x²z - x²y - xy²

= yz(y + z) - x(y + z)(y - z) - x²(y + z)

= (y + z)(yz - xy + xz - x²)

= (y + z)[y(z - x) + x(z - x)] 

= (y + z) (z - x) (y + x)