a) ^{_{\(\dfrac{7}{15}+\dfrac{8}{15}+\dfrac{9}{16}+\dfrac{7}{16}\)}}

^{_{\(=\left(\dfrac{7}{15}+\dfrac{8}{15}\right)+\left(\dfrac{9}{16}+\dfrac{7}{16}\right)\)}}

^_\(=1+1\)

^_\(=2\)

b) ^{_{\(\dfrac{4}{7}\times\dfrac{5}{6}+\dfrac{4}{7}\times\dfrac{1}{6}\)}}

^{_{\(=\dfrac{4}{7}\times\left(\dfrac{5}{6}+\dfrac{1}{6}\right)\)}}

^{_{\(=\dfrac{4}{7}\times1\)}}

^{_{\(=\dfrac{4}{7}\)}}

(7/15 + 8 / 15 ) + ( 9/16 +7/16)

1 + 1

2

4/7 . ( 5/6+1/6)

4/7 . 1

4/7

a) \(=1+1=2\)

b) \(=\dfrac{4}{7}\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\)

1: \(=-145\cdot13+145\cdot57+57\cdot10-57\cdot145=-1315\)

2: \(=17\cdot15-17\cdot16+16\cdot17-16\cdot20=255-320=-65\)

3: \(=-38\cdot25+38\cdot4-25\cdot4+25\cdot38=13\cdot4=52\)

4: \(=23\cdot145-23\cdot17-145\cdot23+145\cdot6=479\)

5: \(=24\cdot15-24\cdot4+4\cdot24-4\cdot15=360-60=300\)

6: \(=199\left(15-17+17-5\right)=199\cdot10=1990\)

7: \(=-39\cdot5+39\cdot99+99\cdot10-99\cdot39=795\)

1: 

2: 

3: 

4: 

5: 

6: 

7: 

mik đang cần gấp

giúp mik với ☹

del

ko có cái nào cả

Không có cái nào cả?

Nếu muốn đúng thì giải thích nè:

Ta quy đồng:

\(\dfrac{4}{5}=\dfrac{4x4}{5x4}=\dfrac{16}{20}\)

Đó, hoặc cái lớn hơn nha!!!

\(\dfrac{4}{3.5}+\dfrac{8}{5.9}+\dfrac{12}{9.15}+...+\dfrac{32}{x\left(x+16\right)}=\dfrac{16}{15}\)

\(2.\left(\dfrac{2}{3.5}+\dfrac{4}{5.9}+\dfrac{6}{9.15}+..+\dfrac{16}{X.\left(X+16\right)}\right)=\dfrac{16}{15}\)

\(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{15}+...+\dfrac{1}{X}-\dfrac{1}{X+16}=\dfrac{8}{15}\)

\(\dfrac{1}{X+16}=\dfrac{1}{3}-\dfrac{8}{15}\)

\(\dfrac{1}{X+16}=\dfrac{-1}{5}\)

\(X+16=-5\)

\(X=-21\)

bài2 \(x\times\dfrac{15}{16}-x\times\dfrac{4}{16}=2\) 

     \(x\times\dfrac{11}{16}=2\) 

     \(x=2:\dfrac{11}{16}\) 

    \(x=\dfrac{32}{11}\)

Bài 1 : 

 \(\dfrac{x}{16}\times\left(2017-1\right)=2\)

          \(\dfrac{x}{16}\times2016=2\)

                      \(\dfrac{x}{16}=\dfrac{2}{2016}\)

                         \(x=\dfrac{2}{2016}\times16\)

                         \(x=\dfrac{1}{63}\)

1- (5\(\dfrac{4}{9}\) +x+7\(\dfrac{7}{18}\)) : 15\(\dfrac{3}{4}\) = 0 

1- (\(\dfrac{49}{9}+x+\dfrac{133}{18}\)) : \(\dfrac{63}{4}=0\) 

 (\(\dfrac{49}{9}+\dfrac{133}{18}\)+\(x\) ) : \(\dfrac{63}{4}\) = 1 - 0 

       (\(\dfrac{77}{6}\) + \(x\) ) : \(\dfrac{63}{4}\) = 1

         \(\dfrac{77}{6}+x\)         = 1 x \(\dfrac{63}{4}\) 

          \(\dfrac{77}{6}\) + \(x\)          = \(\dfrac{63}{4}\)

                  \(x\)            = \(\dfrac{63}{4}\) - \(\dfrac{77}{6}\)

                  \(x=\) \(\dfrac{35}{12}\)

B

b

B