\(=\dfrac{13}{12}\cdot\dfrac{27}{5}\cdot2\cdot\dfrac{34}{9}\cdot2\cdot\dfrac{2}{17}=4\cdot\dfrac{4}{9}\cdot\dfrac{13}{5}\cdot\dfrac{9}{4}=4\cdot\dfrac{13}{5}=\dfrac{52}{5}\)

\(\left(1+\dfrac{2}{24}\right)\cdot5=\dfrac{13}{12}\cdot5=\dfrac{65}{12}=\dfrac{195}{36}\)

\(2.5\cdot2\cdot3\dfrac{7}{9}\cdot2\cdot\dfrac{2}{17}\)

\(=10\cdot\dfrac{2}{17}\cdot\dfrac{34}{9}=\dfrac{40}{9}=\dfrac{160}{36}\)

Do đó: 195/36>160/36

1) 10/2/5 hay 52/5
2) 90

a) \(\frac{3}{7}< \frac{5}{7}\)( Vì \(3< 5\))

\(\frac{4}{9}>\frac{2}{9}\)( Vì \(4>2\))

\(\frac{2}{5}=\frac{4}{10}\)( Vì \(\frac{2}{5}=\frac{4}{10}\)bằng cách ta thấy mẫu số là 10 và 5 nên ta chia rồi quy đồng với số đó )

b) \(\frac{2}{7}< \frac{2}{5}\)( Vì \(\frac{2}{7}=\frac{2\times5}{7\times5=}=\frac{10}{35};\frac{2}{5}=\frac{2\times7}{5\times7}=\frac{14}{35}\)mà \(10< 14\)nên điền dấu bé )

\(\frac{13}{24}>\frac{13}{27}\)( Vì theo tính chất so sánh hai phân số khác mẫu số , phân số nào có mẫu số bé hơn thì lớn hơn )

\(\frac{5}{9}>\frac{5}{11}\)(  Vì theo tính chất so sánh hai phân số khác mẫu số , phân số nào có mẫu số bé hơn thì lớn hơn )

c) \(\frac{4}{7}< \frac{3}{5}\)( Vì \(\frac{4}{7}=\frac{20}{35};\frac{3}{5}=\frac{21}{35}\)mà \(21>20\)nên điền dấu bé )

\(\frac{11}{18}< \frac{17}{24}\)( Vì \(\frac{11}{18}=\frac{206}{432};\frac{17}{24}=\frac{306}{432}\Rightarrow306>206\Rightarrow< \))

\(\frac{5}{36}>\frac{1}{9}\)( Vì \(\frac{1}{9}=\frac{4}{36}\Rightarrow5>4\Rightarrow>\))

khong be oi.

=1616311

d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)

\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)

hay \(x=\dfrac{25}{372}\)

Vậy: \(x=\dfrac{25}{372}\)

e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)

f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)

\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)

\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)

\(\Leftrightarrow3x=\dfrac{1}{9}\)

hay \(x=\dfrac{1}{27}\)

g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)

\(\Leftrightarrow\dfrac{4}{3}x=2\)

hay \(x=\dfrac{3}{2}\)

Vậy: \(x=\dfrac{3}{2}\)

h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)

  Vậy ...

i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)

  Vậy ...

2/2/17 x 1/1/24 x 5/2/5 x 3/7/9 x 2

36/17 x 25/24 x 27/5 x 34/9 x 2

36 x 25 x 27 x 34 x 2/17 x 24 x 5 x 9

1652400/18360=90

1/2/24x5/2/5x2x3/7/9x2x2/17