\(2.32\ge2^n>8\\ \Rightarrow2^6\ge2^n>2^3\\ \Rightarrow n\in\left\{4;5;6\right\}\)

\(2.32=2.2^5=2^6\ge2^n>8=2^3\)

Do \(n\in N\)

\(\Rightarrow n\in\left\{6;5;4\right\}\)

2.32_>2ⁿ >8

=>2.2⁵_>2ⁿ>2³

=>2⁶_>2ⁿ>2³

=>n{6;5;4}

HT~

TL :

\(2.32>2^n\)\(>8\)

\(4^3\)> 2ⁿ > 8

3 < n < 8

n E = { 3 ; 4 ; 5 ; 6 ; 7 }

TL

=> 2.2⁵_>2ⁿ>2³

=>2⁶_>2ⁿ>2³

=> n = {4;5;6 }

Hok tốt

\(2\times2^4\ge2^n>4\)

\(2^5\ge2^n>2^2\)

\(\Rightarrow5\ge n>2\)

vậy x = 3 ; 4 ; 5

bn lm giống mk

2.32_>2ⁿ >8

=>2.2⁵_>2ⁿ>2³

=>2⁶_>2ⁿ>2³

=>n{6;5;4}

8<n^n<2.32

a,  3 x - 2 3 = 2 . 32

3 x - 2 3 = 64

3 x - 2 3 = 4 3

3 x - 2 = 4 ⇔ x = 2

b,  5 x + 1 - 5 x = 500

5 x . 5 - 5 x = 500

5 x . ( 5 - 1 ) = 500

5 x . 4 = 500

5 x = 125 = 5 3

x = 3

a, \(2.16\ge2^n>4\Rightarrow2^5\ge2^n>2^2\Rightarrow5\ge n>2\Rightarrow n\in\left\{3;4;5\right\}\)

b,\(9.27\le3^n\le243\Rightarrow3^5\le3^n\le3^5\Rightarrow n=5\)

\(2.16\ge2^n\ge4\)

\(\Rightarrow32\ge2^n>4\)

\(\Rightarrow2^5\ge2^n>2^2\)

\(\Rightarrow n\le\left\{3;4;5\right\}\)

\(2.16\ge2^n\ge4\Rightarrow2.2^4\ge2^n\ge2^2\Rightarrow2^5\ge2^n\ge2^2\Rightarrow5\ge n\ge2\Rightarrow n=\left(5;4;3;2\right)\)