cho A=7mu1+7mu2+7mu3+7mu4+7mu5+7mu6+7mu7+7mu8 la chan hay le
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chung minh rang
a, 5mu5 - 5mu4 + 5mu3 chia het cho 7
b, 7mu6 + 7mu5 - 7mu4 chia het cho 11
c, 24mu54 . 54mu24 .2mu10 chia het cho 72mu 63
So du cua E =7+7mu2+7mu3+...+7mu36 khi chia cho 8 la
\(E=7+7^2+7^3+...+7^{36}\)
\(E=\left(7+7^2\right)+\left(7^3+7^4\right)+....+\left(7^{35}=7^{36}\right)\)
\(E=7+\left(1+7\right)+7^3\left(1+7\right)+....+7^{35}\left(1+7\right)\)
\(E=7.8+7^3.8+....+7^{35}.8\)
\(E=7+7^3+.......+7^{35}\)chia hết cho 8
Vậy \(E=7+7^2+7^3+...+7^{36}\)chia cho 8 thì dư 0
A= 7+7mu3+7mu5+ ....... +7mu199 chung to A chia het cho 35
ai giai mau co loi gia dung minh se tich cho
so du cua E=7+7mu2+7mu3+......+7mu36 khi chia cho8
\(E=\left(7+7^2\right)+\left(7^3+7^4\right)+....+\left(7^{35}+7^{36}\right)\)
= 7.8 + 7^3.8 + .... + 7^35 . 8
= 8.(7+7^3+...+7^35)
Chia 8 dư 0
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a)Neu tong cua 2 so tu nhien la 1 so le, thi tich cua chung co the la 1 so le va mot so chan duoc ko?
b) neu tich cua 2 so tu nhien la 1 so le,cthi tong cua chung co the la 1 so le va mot so chan duoc ko ?
c) Cho hai so tu nhien bat ki. Neu tong cua hai so do la so chan thi hieu cua chung la chan hay le?
tinh tong cua 2 so nguyen a,b. cho biet tong vua tinh duoc la so chan hay so le. mn chi minh voi minh can gap
#include <bits/stdc++.h>
using namespace std;
long long a,b,t;
int main()
{
cin>>a>>b;
t=a+b;
cout<<"Tong la:"<<t<<endl;
if (t%2==0) cout<<"Tong la so chan";
else cout<<"Tong la so le";
return 0;
}
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2 4 6 8 la cac so chan vay thi 1 3 5 7 9 la cac so le khi cong tung so lai ta se duoc 45 so chan la 20 so le la 25 khi chia tong cua cac chu so le
cho tong cua cac chu so chan ta duoc bao nhieu (khong du) de sao cho so do bang tong cua cac chu so le va chu so chan
Voi n thuoc Z, cac so sau la chan hay le?
A =(n-4) (n-15),B =n2-n-1
Voi n thuoc Z<cac so sau la chan hay le ?
A = (n-4) (n-15), B = n2-n-1