3^x-1+5.3^x-1=162
3x-1+5.3x-1=162
3^x-1 +5.3^x-1=162
6. 3^x-1=162
3^x-1=27
x-1=3
x=4
\(3^{x-1}\)+5.\(3^{x-1}\)=162
\(\Leftrightarrow\)\(3^{x-1}\)(1+5)=162
\(\Leftrightarrow\)\(3^{x-1}\)=27
\(\Leftrightarrow\)\(3^{x-1}\)=33
\(\Leftrightarrow\)x-1=3
\(\Leftrightarrow\)x=4
Vậy x=4
Ta có : 3x - 1 + 5 . 3x - 1 = 162
\(\Leftrightarrow\)3x - 1 . ( 1 + 5 ) = 162
\(\Leftrightarrow\)3x - 1 . 6 = 162
\(\Leftrightarrow\)3x - 1 = 162 ÷ 6 = 27
\(\Leftrightarrow\)3x - 1 = 33
\(\Leftrightarrow\)x - 1 = 3
\(\Leftrightarrow\)x = 4
Vậy : x = 4
3x-1+5.3x-1=162
Mình ko viết lại đầu bài nhé!
=> 3^x-1. (1+5) = 162
=>3^ x-1 . 6 = 162
=>3^x-1 =27
=>3^x-1 = 3^3
=>x-1 =3
=>x = 4
Vậy x=4
3^x-1.(1+5)=162
=>3^x-1=162:6
=>3^x-1=27=3^3
=>x-1=3
=>x=4
vậy x=4 nhé!
bài này dễ woa
bài này để qua kết quả bảng 4 chứ mấy nữa
3x-1+5.3x-1=162
3x-1+5.3x-1=162
3x-1 .(5 + 1)=162
3x-1 . 6 =162
3x-1 =162:6
3x-1 =27
3x-1 =3\(^3\)
x - 1 = 3
x = 3 + 1
x = 4
3x-1+5.3x-1=162
3x-1.1+5.3x-1=162
3x-1.(1+5)=162.Suy ra:3x-1=162:6=27
3x:3=27.Suy ra:3x=3.27=81=34(81=34)
Vậy x=4
CHÚC BẠN HỌC TỐT
\(3^{x-1}+5\cdot3^{x-1}=162\)
\(3^{x-1}\cdot1+5\cdot3^{x-1}=162\)
\(3^{x-1}\cdot\left(1+5\right)=162\)
\(3^{x-1}\cdot6=162\)
\(3^{x-1}=162:6\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
=> x-1=3
x=1+3
x=4
k co ah nha
\(3^{x-1}+5.3^{x-1}=162\)
3^x-1 + 5.3^x-1 = 162
3^x-1. (1+5) = 162
3^x-1 =27
3^x-1 = 3^3
x-1 =3
x = 4
Vậy x=4
\(3^{x-1}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}.\left(1+5\right)=162\)
\(\Rightarrow3^{x-1}.6=162\)
\(\Rightarrow3^{x-1}=162:6=27=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=3+1=4\)
giúp mình\(3^{-1}.3^x+5.3^{x-1}=162\)
\(3^{-1}.3^x+5.3^{x-1}=162\)
=> \(\frac{1}{3}.3^x+5.3^x:3=162\)
=> \(\left(\frac{1}{3}+\frac{5}{3}\right).3^x=162\)
=> 2 . 3x = 162
=> 3x = 162 : 2
=> 3x = 81
=> 3x = 34
=> x = 4
Vậy ...
\(3^{-1}.3^x+5.3^{x-1}=162\)
\(\Rightarrow3^{-1+x}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}.\left(1+5\right)=162\)
\(\Rightarrow3^{x-1}.6=162\)
\(\Rightarrow3^{x-1}=162:6=27=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Vậy x = 4
Tìm x
3^x-1 + 5.3^x-1 = 162
5^x + 5^x+2 = 650
3x-1+5.3x-1=162
=>3x-1.(1+5)=162
=>3x-1.6=162=>3x-1=162:6=27=33
=>x-1=3=>x=4
5x+5x+2=650
=>5x+5x.52=650
=>5x.(1+25)=650
=>5x.26=650=>5x=650:26=25=52
=>x=2
3x/3+5.3x-1=162
Tìm x
\(3^{x-1}+5.3^{x-1}=162\)
3x−1+5.3x−1=162
=>3x−1(1+5)=162
=>3x−1.6=162
=>3x−1=162:6
=>3x-1=27
=>3x-1=33
=>x-1=3
=>x=4
\(a,\)\(3^x^{-1}+5.3^{x-1}=162\)
\(b,\)\(x-2+3x=10\)
câu b là 2 trường hợp nhé
b: Ta có: \(x+3x-2=10\)
\(\Leftrightarrow4x=12\)
hay x=3