278+x:5-28=500

278+x:5=500+28

278+x:5=528

x:5=528-278

x:5=250

x=250x5

x=1250

ai qua đòng ý với mình thì k nhé

278 + \(\frac{x}{5}\) -28 = 500

          \(\frac{x}{5}\)       = 500 - (278-28)

          \(\frac{x}{5}\)       = 250

           x         = 250 x 5 =1250

1250

cua minh dung  Nguyễn Huyền Trang

278-4.[x+3]=178

274.[x+3]=178

x+3=274:178

x+3=1,5

x=1,5-3

x=-1,5

278-4.[x+3]=178

4.[x+3]=100

[x+3]=25

x=22

278+x:5-28=500

250+x:5=500

x:5=500-250

x:5=250

x=250*5

x=1250

ai k mh mh k lại

k cho mh nha NGUYỄN HUYỀN TRANG

\(\left(x+184-278\right)-\left(184-278\right)=4\\\left(x+184-278\right)-\left(-94\right)=4\\ \left(x+184-278\right)+94= 4\\ \left(x+184-278\right)= 4-94\\ \left(x+184-278\right)=-90\\ x+184=-90+278\\ x+184=188\\ x=188-184\\ 4.\)

( x + 184 - 278 ) - ( 184 - 278 ) = 4

x + 184 - 278 - 184 + 278 = 4

x + 0 = 4

x = 4

a) x >278 vì x phải lớn hơn 278 để x trừ được cho 278.

b) x <278 vì x phải nhỏ hơn 278 để 278 trừ được cho x.

a, ( 45 + y ) = 278 - 118

    ( 45 + y ) = 160

         y       = 160 - 45

         y       = 115

b, \(2,3y+\frac{1}{2}y-y=9\)

      \(y\left(\frac{2}{3}+\frac{1}{2}-1\right)=9\) ( Đến đây bn tự quy đồng nha )

       \(y.\frac{1}{6}=9\)

     \(y=9:\frac{1}{6}=9.6=54\)

@@ Bài kia bó tay 

\(12\left(x+5\right)+2x=130\\\Leftrightarrow 12x+60+2x=130\\ \Leftrightarrow14x=70\\ \Leftrightarrow x=5\\ ----\\ 23\left(x-5\right)-12x=138\\ \Leftrightarrow23x-115-12x=138\\ \Leftrightarrow23x-12x=138+115\\ \Leftrightarrow11x=253\\ \Leftrightarrow x=\dfrac{253}{11}=23\\ ----\\ 360-12x+23\left(x-5\right)=278\\ \Leftrightarrow360-12x+23x-115=278\\ \Leftrightarrow-12x+23x=278+115-360\\ \Leftrightarrow11x=33\\ \Leftrightarrow x=\dfrac{33}{11}=3\)

\(6\left(x+3\right)+3\left(x-5\right)=278\\ \Leftrightarrow6x+18-3x-15=278\\ \Leftrightarrow6x-3x=278+15-18\\ \Leftrightarrow3x=275\\ \Leftrightarrow x=\dfrac{275}{3}\\ ---\\ \left(7-x\right)\left(3x-90\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}7-x=0\\3x-90=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=30\end{matrix}\right.\)

\(\left(x-2\right)\left(4x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-2=0\\4x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\4x=2\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{1}{2}\end{matrix}\right.\\ ---\\ \left(2x-18\right)\left(3x-9\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-18=0\\3x-9=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=18\\3x=9\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=9\\x=3\end{matrix}\right.\)

...

\(\Leftrightarrow\left(x+1\right)\left(3x-5\right)=0\)

hay \(x\in\left\{-1;\dfrac{5}{3}\right\}\)