\(2 .x + 4 .x + . . . + 18 .x = 18 + 16 + . . . + 2 \)

x=1

x=1

a) 32 : 4 : 2 = 8 : 2 = 4 

     32 : 4 : 2 = 32 : 2 = 16 

b) 18 : 2 x 3 = 18 : 6 = 3

     18 : 2 x 3 = 9 x 3 = 18

1,Tìm x:

\(\left(x+8\right)+\left(x-4\right)=x-20\)

\(\Leftrightarrow x+8+x-4=x-20\)

\(\Leftrightarrow x+x-x=-20+4-8\)

\(\Leftrightarrow x=-24\)

Vậy...

bài2 \(x\times\dfrac{15}{16}-x\times\dfrac{4}{16}=2\) 

     \(x\times\dfrac{11}{16}=2\) 

     \(x=2:\dfrac{11}{16}\) 

    \(x=\dfrac{32}{11}\)

Bài 1 : 

 \(\dfrac{x}{16}\times\left(2017-1\right)=2\)

          \(\dfrac{x}{16}\times2016=2\)

                      \(\dfrac{x}{16}=\dfrac{2}{2016}\)

                         \(x=\dfrac{2}{2016}\times16\)

                         \(x=\dfrac{1}{63}\)

1- (5\(\dfrac{4}{9}\) +x+7\(\dfrac{7}{18}\)) : 15\(\dfrac{3}{4}\) = 0 

1- (\(\dfrac{49}{9}+x+\dfrac{133}{18}\)) : \(\dfrac{63}{4}=0\) 

 (\(\dfrac{49}{9}+\dfrac{133}{18}\)+\(x\) ) : \(\dfrac{63}{4}\) = 1 - 0 

       (\(\dfrac{77}{6}\) + \(x\) ) : \(\dfrac{63}{4}\) = 1

         \(\dfrac{77}{6}+x\)         = 1 x \(\dfrac{63}{4}\) 

          \(\dfrac{77}{6}\) + \(x\)          = \(\dfrac{63}{4}\)

                  \(x\)            = \(\dfrac{63}{4}\) - \(\dfrac{77}{6}\)

                  \(x=\) \(\dfrac{35}{12}\)

mai nah

a)x=-2

b)x=-102

c)x=123

d)x=10

e)x=-48

\(x+\frac{1}{19}+x+\frac{2}{18}+x+\frac{3}{17}+x+\frac{4}{16}=4\)

\(4x+\left(\frac{1}{19}+\frac{2}{18}+\frac{3}{17}+\frac{4}{16}\right)=4\)

\(4x+\frac{6863}{11628}=4\)

\(4x=4-\frac{6863}{11628}=\frac{39649}{11628}\)

\(\Rightarrow x=\frac{39649}{11628\cdot4}=\frac{39649}{46512}\)

a: Ta có: \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)

\(\Leftrightarrow x^2+5x-10=x^2+3x-4\)

\(\Leftrightarrow2x=6\)

hay x=3