phân tích thành nhân tử
5+√5
√33 +√32
3+√3
√14+√7
√15-√6
7-√7
10-2√10
4-4√5
5-2√5
Những câu hỏi liên quan
phân tích thành nhân tử
5+√5
√33 +√32
3+√3
√14+√7
√15-√6
7-√7
10-2√10
4-4√5
5-2√5
\(5+\sqrt{5}=\sqrt{5}\left(\sqrt{5}+1\right)\)
\(3+\sqrt{3}=\sqrt{3}\left(\sqrt{3}+1\right)\)
\(\sqrt{14}+\sqrt{7}=\sqrt{7}\left(\sqrt{2}+1\right)\)
\(\sqrt{15}-\sqrt{6}=\sqrt{3}\left(\sqrt{5}-\sqrt{2}\right)\)
\(7-\sqrt{7}=\sqrt{7}\left(\sqrt{7}-1\right)\)
\(10-2\sqrt{10}=\sqrt{10}\left(\sqrt{10}-2\right)=\sqrt{20}\left(\sqrt{5}-\sqrt{2}\right)\)
\(4-4\sqrt{5}=4\left(1-\sqrt{5}\right)\)
\(5-2\sqrt{5}=\sqrt{5}.\left(\sqrt{5}-2\right)\)
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phân tích đa thức thành nhân tử
1) 5+√5, √33+√22, 3+√3, √14-√7, √15-√6, √15-√12, 7-√7,10+2√10, 4-4√5, 5-2√5, 3-2√3
Bài 1: Phân tích đa thức sau thành nhân tử1) 2) 3) 4) 5) 6) 7)8) 9) 10) 11) 12)13) 14)15)16)
Đọc tiếp
Bài 1: Phân tích đa thức sau thành nhân tử
1) 
2) 
3) 
4) 
5) 
6) 
7)
8)
9)
10)
11)
12)
13)
14)
15)
16)
câu trả lời cho câu hỏi của Huong Le Thị Lan: 1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32.
=(1+32)+(2+31)+(3+30)+(4+29)+(5+28)+(6+27)+(7+26)+(8+25)+(9+24)+(10+23)+(11+22)+(12+21)+(13+20)+(14+19)+(15+18)+(16+17)
=33+33+33+33+33+33+33+33+33+33+33+33+33+33+33+33. =33.16 (dấu chấm là dấu nhân)=528
wow! mù mắt. Ido tính toán có khác!
C2:(32+1)x32:2=528
bạn tính thử xem đúng đấy.
Xem thêm câu trả lời
18 tháng 3 2022 lúc 14:25
Nối 2 phép tính có cùng với kết quả: 5/4:3/8 7/5 nhân 10/3 7/12:7/8 6/7 nhân 14/15 7/3:1/2 1/3:1/2 5/4 nhân 8/3 1/7:5/28
Gợi ý: Nó trong VBT Toán Nâng Cao
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ai giúp em câu này đi
a,6/1*3*7+6/3*7*9+6/7*9*13+6/9*13*15+6/13*15*19
b,1/1*3*7+1/3*7*9+1/7*9*13+1/9*13*15+1/13*15*19
c,1/2*4*6+1/4*6*8+1/6*8*10+1/8*10*12*14+...+1/96*98*100
d,5/1*5*8+5/5*8*12+5/8*12*15+...+5/33*36*40
* là dấu nhân / là phần nha
1.3.77−1+3.7.99−3+7.9.1313−7+9.13.1515−9+\frac{19-13}{13.15.19}+13.15.1919−13
=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}=1.31−3.71+3.71−7.91+7.91−9.131+9.131−13.151+13.151−15.191
=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}=1.31−15.191=28595−2851=28594
b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)b,=61.(1.3.76+3.7.96+7.9.136+9.13.156+13.15.196)
làm giống như trên
c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)c,=81.(1.2.31+2.3.41+3.4.51+...+48.49.501)
=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)=161.(1.2.32+2.3.42+3.4.52+...+48.49.502)
=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)=161.(1.2.33−1+2.3.44−2+3.4.55−3+...+48.49.5050−48)
=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)=161.(1.21−2.31+2.31−3.41+3.41−4.51+...+48.491−49.501)
=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}=161.(21−24501)=161.(24501225−24501)=4900153
d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)d,=75.(1.5.87+5.8.127+8.12.157+...+33.36.407)
=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)=75.(1.5.88−1+5.8.1212−5+8.12.1515−8+...+33.36.4040−33)
=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)=75.(1.51−5.81+5.81−8.121+8.121−12.151+...+33.361−36.401)
=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}=75.(51−14401)=75.(1440288−14401)=28841
P/S: . là nhân nha
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1/ -7(5-x)-2(x-10)=15
2/ 4(x-5)-3(x+7)= -19
3/ 4(2-x)+3(x-5)=14
4/ 7(x-9)-5(6-x)=-6+11x
5/ -7(3x-5)+2(7x-14)=28
6/ 5(4-x)-7(-x+2)=4-9+3
7/ 4x-5(-3+x)=7
8/ 5(x-7)+10(3-x)=20
9/ 7(5-x)+5(x-2)=15
1/ Suy ra: -35 + 7x - 2x + 20 = 15
5x - 15 = 15
5x = 30
x = 6
2/ Suy ra: 4x - 20 - 3x - 21 = -19
x - 41 = -19
x = 22
3/ Suy ra: 8 - 4x + 3x - 15 = 14
-7 -x = 14
x = -7 -14
x = -21
4/ Suy ra: 7x - 63 - 30 + 5x = -6 + 11x
7x + 5x - 11x = -6 +63 + 30
x = 87
5/ Suy ra: -21x +35 + 14x - 28 = 28
-21x + 14x = 28 +28 - 35
-7x = 21
x= -3
6/ Suy ra: 20 - 5x + 7x - 14 = -2
2x = -8
x = -4
7/ Suy ra: 4x +15 -5x = 7
-x = -8
x = 8
8/ Suy ra: 5x - 35 +30 -10x = 20
-5x - 5 = 20
-5x = 25
x = -5
9/ Suy ra: 35 - 7x + 5x - 10 = 15
-7x + 5x = 15 +10 - 35
-2x = -10
x = 5
Tính:
a) -5/7(14/5 - 7/10) : |-2/3| - 3/4(8/9 + 16/3) + 10/3(1/3 + 1/5)
b) 17/-26(1/6 - 5/3) : 17/13 - 20/3(2/5 - 1/4) + 2/3(6/5 - 9/2)
c) -8/9(9/8 - 3/2) + 5/4 : (5/2 - 15/4) - 3/4(10/9 - 8/3) : (-1/3)
d) 21/10 : (12/5 - 9/10) . (-4/7) - 3/2(1/6 - 7/12) + 1/5(3/2 - 1/4)
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
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Các bn giúp mk nha
Tính giá trị biểu thức sau
a) A=2*5^22-9*5^51/25^10 : 5*(3*7^15-19*7^14)/7^16+3/7^15
b) 8^5*16^3/4^13 - 3^33*4^15/6^32
c) C= 1994^(256-1^2)^(256-2^2)^....^(256-50^2)
So sánh các lũy thừa sau
A=(-2017)^2019 và B = ( - 2018)^2020