100-(3.52-2.33)
a)3.52 + 15.22 – 26:2
b)53.2 – 100 : 4 + 23.5
c)29 – [16 + 3.(51 – 49)]
d)10 – [(82 – 48).5 + (23.10 + 8)] : 28
hãy giúp tui ik
A = 75 +60-13=122.B = 250-25+40=265.C=29-[16+3.2] ➙29-22=7 D= 10-[16.5+88]:28➙ 10-168:28➙10-6=4
2.33 +4.32
\(2.3^3+4.3^2\\ =2.3^2\left(3+4\right)\\ =2.9.7\\ =125.\)
Sửa lại:
\(2.3^3+4.3^2\\ =2.3^2\left(3+4\right)\\ =2.9.7\\ =126.\)
Tính: (-8)2.33
Bài 1:Thựchiệnphéptính:
a) 3.52 + 15.22 – 26:2 b)53.2 – 100 : 4 + 23.5 c)62 : 9 + 50.2 – 33.3
d)32.5 + 23.10 – 81:3 e)513 : 510 – 25.22g)20 : 22 + 59 : 58
h)100 : 52 + 7.32 h)84 : 4 + 39 : 37 + 50 i)29 – [16 + 3.(51 – 49)]
mk cần gấp
\(a,=75+60-13=122\\ b,=250-25+40=265\\ c,=4+100-9=95\\ d,=45+80-27=98\\ e,=5^3-100=125-100=25\\ g,=5+5=10\)
a)
=\(3.5.5+3.5.2-13=3.5\left(5+2\right)-13=15.7-13=105-13=92\)
b)
\(=5^3.2-25+2^3.5=5.25-5.5+8.5=5\left(25-5+8\right)=5.28=140\)
c)
\(6^2:9+50.2-3^3.3=36:9+100-3^4\)
=\(4+100-81\)=23
a: \(3\cdot5^2+15\cdot2^2-26:2\)
\(=75+60-13\)
=122
b: \(5^3\cdot2-100:4+2^3\cdot5\)
\(=250-25+40\)
=265
c: \(6^2:9+50\cdot2-3^3\cdot3\)
\(=4+100-9\)
=95
a) 3.52 + 15.22 – 26:2 b) 53.2 – 100 : 4 + 23.5
c) 62 : 9 + 50.2 – 33.3 d) 32.5 + 23.10 – 81:3
e) 2345 – 1000 : [19 – 2(21 – 18)2] f) 128 – [68 + 8(37 – 35)2] : 4
g) 568 – {5[143 – (4 – 1)2] + 10} : 10 h) 107 – {38 + [7.32 – 24 : 6+(9
\(a.3.52+15.22-26:2\\ 156+330-13\\ =486-13\\ =473\)
\(b.53.2-100:4+23.5\\ =106-25+115\\ =81+115\\ =196\)
9.83 + (-2.33) - (-3.75) + 9.25 - 12.5
9.83 + (-2.33) - (-3.75) + 9.25 - 12.5
= 7,5 - (-3.75) + 9.25 - 12.5
= 11,25 + 9,25 - 12,5
= 20,5 - 12,5
= 8
=7,5+3,75+9,25-12,5
=20,5-12,5
=8
9.83 + (-2.33) - (-3.75) + 9.25 - 12.5
= 7,5 - (-3.75) + 9.25 - 12.5
= 11,25 + 9,25 - 12,5
= 20,5 - 12,5
= 8
d,321-21. [(2.33 + 44 : 32) - 52] giúp mik
= 300 . [(54 + 256 : 32) - 52
= 300 . [(54 + 8) - 52 ]
= 300 . (62 - 52)
= 300 . 10
= 3000
nhớ ôn lại kiến thức đi e ơi :)))
Bài 1: Thực hiện phép tính:
a) 3.52 + 15.22 – 26:2
b) 53.2 – 100 : 4 + 23.5
c) 62 : 9 + 50.2 – 33.3
d) 2345 – 1000 : [19 – 2(21 – 18)2]
e) 128 – [68 + 8(37 – 35)2] : 4
f) 568 – {5[143 – (4 – 1)2] + 10} : 10
e: \(=128-\left[68+8\cdot4\right]:4=128-25=103\)
\(a.3.5^2+15.2^2-26:2\) \(b.5^3.2-100:4+2^3.5\)
\(=75+60-13\) \(=250-25+40\)
\(=135+13=148\) \(=265\)
\(c.6^2:9+50.2-3^3.3\) \(d.2345-1000:\left[19-2.\left(21-18\right)^2\right]\)
\(=4+100-81\) \(=2345-1000:\left[19-2.3^2\right]\)
\(=23\) \(=2345-1000:\left[19-18\right]\)
\(=2345-1000:1\)
\(=2345-1000=1345\)
\(e.128-\left[68+8.\left(37-35\right)^2\right]:4\)
\(=128-\left[68+8.2^2\right]:4\)
\(=128-\left[68+32\right]:4\)
\(=128-100:4\)
\(=128-25=103\)
\(f.568-\left\{5.\left[143-\left(4-1\right)^2\right]+10\right\}:10\)
\(=568-\left\{5.\left[143-3^2\right]+10\right\}:10\)
\(=568-\left\{5.134+10\right\}:10\)
\(=568-\left\{670+10\right\}:10\)
\(=568-680:10\)
\(=568-68=500\)
151-2 mũ 91:2 mũ 88+ 1 mũ 2.33
ƯCLN của 2.33 và 3.5
A. 2 . 33 . 5
B. 2.3.5
C. 2.3
D. 3