-(315.4+275)+4.135-(10-275)

=-1535+540+265

=-730

A,= -315.4-275+4.315-10+275

=[(-315.4)+4.315]+(-275+275)-10

=-10

b,=[(-2,5.0,4).0,375]-[(-8.0,125).3,25]

=[-1.0,375]-[(-1).3,25]

=-0,375-(-3,25)

=-0,375+3,25=2,875

-64217/200

\(A=\left(37,1-4,5\right)-\left(-4,5+37,1\right)\)

   \(=37,1-4,5+4,5-37,1\)

   \(=37,1-37,1-4,5+4,5\)

   \(=0.\)

\(B=-\left(315.4+275\right)+4.315-\left(10-275\right)\)

   \(=-315.4-275+4.315-10+275\)

   \(=-315.5+4.315-275+275-10\)

   \(=0+0-10=-10.\)

\(C=-\left(\frac{3}{7}+\frac{3}{8}\right)-\left(-\frac{3}{8}+\frac{4}{7}\right)\)

    \(=-\frac{3}{7}-\frac{3}{8}+\frac{3}{8}-\frac{4}{7}\)

    \(=-\frac{3}{7}-\frac{4}{7}-\frac{3}{8}+\frac{3}{8}\)

    \(=-1+0=-1.\)

A=37,1 - 4,5 + 4,5 - 37,1

A=(37,1 - 37,10) + ( 4,5 - 4,5 )

 A = 0 + 0 = 0

B= -315.4 - 275  + 4.315 - 10 + 275

B=(-315.4 + 4.315) + ( 275-275) - 10

B= 0 + 0 - 10 = -10

C= -3/7 - 3/8 + 3/8 - 4/7

C = ( -3/7-4/7) + ( 3/8 - 3/8)

C=-7/7 + 0 = -7/7 = -1

- ( 315,4 + 275 ) + 4,135 - ( 10 - 275 )

= -315.4 - 275 + 4,135 - 10 + 275

= -( 315.4 - 4,135 ) - ( 275 - 275 ) - 10

= -311,265 - 0 -10

= -321,265

-(315x4+275)+4x315-(10-275)

= - ( 1260 + 275 ) + 1260 - (-265)

= -1535 + 1260- ( -265)

=-275 - ( -265)

= -10

-(315.4+275)+4.315-(10-275)

=-4.315-275+4.315-10+275

=(-4+4).315+(275-275)-10

=0-0-10=-10

(áp dụng quy tắc  phân phối, chuyển dấu, giao hoán)

- (315 . 4+ 275) + 4. 315- (10 - 275)

=- (1260+ 275) + 4. 315- (-265)

=-1535+ 4. 315- (-265)

=-1535+ 1260- (-265)

=-275- (-265)

=-10