2+4+6+8+...+2016+2018
\frac{x-10}{2010}+\frac{x-8}{2012}+\frac{x-6}{2014}+\frac{x-4}{2016}+\frac{x-2}{2018}=\frac{x-2018}{2}+\frac{x-2016}{4}+\frac{x-2014}{6}+\frac{x-2012}{8}+\frac{x-2010}{10}
2+4+6+8+...+2016+2018
Tổng trên có: \(\frac{2018-2}{2}+1=1009\)(số hạng)
\(\Rightarrow2+4+6+8+...+2016+2018=\)\(\frac{2018+2}{2}\times1009=1019090\)
Học tốt nha
số số hạng là :
(2018 - 2) : 2 + 1 = 1009
tổng :
(2018 + 2) x 1009 : 2 = 1 019 090
số số hạng của dãy là:
(2018-2):2+1=1009(số)
tổng dãy số là:\(2018+2)x1009:2=1019090
2 + (- 4) + 6 + (-8) + 10 + ( -12) +......+2014 + ( - 2016) + 2018
B =2-4-6+8+10-12-14+.... -2014+2016+2018-2020
Ta có: \(B=2-4-6+8+10-12-14+...-2014+2016+2018-2020\)
\(=\left(2-4-6+8\right)+\left(10-12-14+16\right)+...+\left(2010-2012-2014+2016\right)+\left(2018-2020\right)\)
\(=2018-2020=-2\)
tính nhanh:
a) (2016*2017+2018*2+2015):[(2018*2017-2017*2015)+2016]
b)2018*20182017-2017*20182018
c)1+2-3-4+5+6-7-8+...+298-299-300+301+302
2-4+6-8+...-2016+2018
2-4+6-8+...-2016+2018
=(2-4)+(6-8)+...+(2014-2016)+2018
có 504 cặp
=-2+-2+...+-2+2018
=-2x504+2018
=-1008+2018
=1010
2-4+6-8+...-2016+2018
= (2+6+...+2018)- (4+8+....+2016)
=510050 - 509040
= 1010
Tính nhanh
a) S1= 1+(-2)+3+(-4)+.......+2016+(-2017)
b) S2 = 2-4+6-8+..........+2016-2018
Bài 1:
a, C = 1 + 5^2 + 5^4 + 5^6 +...+ 5^2018
b, D = 2 x 4 + 4 x 6 + 6 x 8 + 8 x 10 + ... + 2016 x 2018