`A =2/15 +2/35 +2/63 +... +2/339`

`= 2/(3.5) +2/(5.7) + 2/(7.9) + ...+2/(19.21)`

`= 1/3 -1/5 +1/5 -1/7 +1/7 -1/9 +... 1/19 -1/21`

`= 1/3 -1/21 = 7/21 -1/21`

`=6/21 = 2/7`

$A=2/15+2/35+2/63+...+2/339$

$=2/(3.5)+2/(5.7)+2/(7.9)+...+2/(19.21)$

$=1/3-1/5+1/5-1/7+1/7-1/9+...1/19-1/21$

$=1/3-1/21=7/21-1/21$

$=6/21=2/7$

sai rồi,2/7 mới đúng,bài này không cần nhân 2

Giải:

\(\dfrac{2}{3}+\dfrac{2}{15}+\dfrac{2}{35}+\dfrac{2}{63}+\dfrac{2}{99}+\dfrac{2}{143}\) 

\(=\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}\) 

\(=\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}\) 

\(=\dfrac{1}{1}-\dfrac{1}{13}\) 

\(=\dfrac{12}{13}\) 

Chúc em học tốt!

2/3+2/15+2/35+2/63+2/99+2/143

=2(1/1x3+1/3x5+1/5x7+1/7x9+1/9x11+1/11x13)

=2(1-1/3+1/3-1/5+1/5-....+1/13)

=2(1-1/13)

=2.12/13=24/13

  ( \(\dfrac{2}{15}\) + \(\dfrac{2}{35}\) + \(\dfrac{2}{63}\)) : \(x\) = \(\dfrac{1}{18}\)

  ( \(\dfrac{2\times7}{15\times7}\) + \(\dfrac{2\times3}{35\times3}\) + \(\dfrac{2}{63}\)) : \(x\) = \(\dfrac{1}{18}\)

   (\(\dfrac{14}{105}\) + \(\dfrac{6}{105}\) + \(\dfrac{2}{63}\)) : \(x\) = \(\dfrac{1}{18}\)

    (\(\dfrac{20}{105}\) + \(\dfrac{2}{63}\)) : \(x\)  = \(\dfrac{1}{18}\)

     ( \(\dfrac{4}{21}\) + \(\dfrac{2}{63}\)) : \(x\) = \(\dfrac{1}{18}\)

       (\(\dfrac{12}{63}\) + \(\dfrac{2}{63}\)) : \(x\) = \(\dfrac{1}{18}\)

         \(\dfrac{2}{9}\) : \(x\) = \(\dfrac{1}{18}\)

               \(x\) = \(\dfrac{2}{9}\) : \(\dfrac{1}{18}\)

               \(x\) = 4

x = 4 nhé

 ( 215152​ + 235352​ + 263632​) : �x = 118181​

  ( 2×715×715×72×7​ + 2×335×335×32×3​ + 263632​) : �x = 118181​

   (1410510514​ + 61051056​ + 263632​) : �x = 118181​

    (2010510520​ + 263632​) : �x  = 118181​

     ( 421214​ + 263632​) : �x = 118181​

       (12636312​ + 263632​) : �x = 118181​

         2992​ : �x = 118181​

               �x = 2992​ : 118181​

               �x = 4

Đề không đầy đủ. Bạn xem lại

A = \(\dfrac{2}{35}\) + \(\dfrac{4}{77}\) + \(\dfrac{2}{143}\) + \(\dfrac{4}{221}\) + \(\dfrac{2}{323}\) + \(\dfrac{4}{437}\) + \(\dfrac{2}{575}\)

A =  \(\dfrac{2}{5\times7}\)+\(\dfrac{4}{7\times11}\)+\(\dfrac{2}{11\times13}\)+\(\dfrac{4}{13\times17}\)+\(\dfrac{2}{17\times19}\)+\(\dfrac{4}{19\times23}\)+\(\dfrac{2}{23\times25}\)

A = \(\dfrac{1}{5}\)-\(\dfrac{1}{7}\)+ \(\dfrac{1}{7}\) - \(\dfrac{1}{11}\)+\(\dfrac{1}{11}\)-\(\dfrac{1}{13}\)+\(\dfrac{1}{13}\)-\(\dfrac{1}{17}\)+\(\dfrac{1}{17}\)-\(\dfrac{1}{19}\)+\(\dfrac{1}{19}\)-\(\dfrac{1}{23}\)+\(\dfrac{1}{23}\)-\(\dfrac{1}{25}\)

A = \(\dfrac{1}{5}\) - \(\dfrac{1}{25}\)

A = \(\dfrac{4}{25}\)

Cầu cứu mọi người hãy giúp đỡ mình

=>x(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9)+99/x=-3/7

=>8/9x+99/x=-3/7

\(\Leftrightarrow\dfrac{8x}{9}+\dfrac{99}{x}=\dfrac{-3}{7}\)

\(\Leftrightarrow\dfrac{8x^2+99\cdot9}{9x}=\dfrac{-3}{7}\)

\(\Leftrightarrow-56x^2-6237=27x\)

hay \(x\in\varnothing\)

Có: \(x=\dfrac{1}{9}+\dfrac{8}{116}=\dfrac{1}{9}+\dfrac{2}{29}=\dfrac{47}{261}\)

\(x-\left(\dfrac{2+2+2+2}{3+15+35+63}\right)=\dfrac{1}{9}\)

\(\Leftrightarrow x=\dfrac{1}{9}+\dfrac{2}{29}=\dfrac{47}{261}\)