tính
\(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
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CHỨNG MINH:
\(\frac{10^2+5.10^2+5^3}{6^3+3.6^2+3^3}=\frac{125}{27}\)
(10^2 + 5.10^2 + 5^3):(6^3 + 3. 6^2 + 3^3) = (100 + 500 + 125):(216 + 108 + 27) = 725 : 351 = ... chet cha lon de :D
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Rút gọn biểu thức:
1) \(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^2}\)
2) \(\frac{5^3+5.5^2}{-8}\)
Giúp mik nhé!!!
1) Sửa đề :
\(\frac{10^3+5\cdot10^2+5^3}{6^3+3\cdot6^2+3^3}=\frac{10^3+5\cdot5^2\cdot2^2+5^3}{6^3+3\cdot2^2\cdot3^2+3^3}=\frac{5^3\cdot\left(2^3+2^2+1\right)}{3^3\cdot\left(2^3+2^2+1\right)}=\frac{5^3}{3^3}\)
2) Sửa đề :
\(\frac{5^3+3\cdot5^2}{-8}=\frac{5^2\cdot\left(5+3\right)}{-8}=\frac{-5^2\cdot8}{8}=-5^2=-25\)
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B1: Tính
a) (1/4)44. (1/2)12
b) \(\frac{3^{17}.81^{11}}{27^{10}.9^{15}}
\)
c)\(\frac{14^{16}.21^{32}.35^{48}}{10^{16}.15^{32}.7^{96}}\)
d)\(\frac{\left(5^4-5^3\right)^3}{125^4}\)
e)\(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
10 mũ 3 + 5.10 mũ 2+5 mũ 3 trên
6 mũ 3+3.6 mũ 2 +3 mũ 3
1) Tính dfrac{7^4.3-7^3}{7^4.6-7^3.2} ; dfrac{10^3+5.10^2+5}{6^3+3.6^2+3^2} ; E1+dfrac{1}{3}+dfrac{1}{3^2}+...+dfrac{1}{3^{100}} 2) Tìm x biếtdfrac{1}{1.2}+dfrac{1}{2.3}+dfrac{1}{3.4}+...+dfrac{1}{x.left(x+1right)} ; 3^{x+1}+3^{x+3}810 MN ƠI ! GIÚP MIK VS .
Đọc tiếp
1) Tính
\(\dfrac{7^4.3-7^3}{7^4.6-7^3.2}\) ; \(\dfrac{10^3+5.10^2+5}{6^3+3.6^2+3^2}\) ; \(E=1+\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{100}}\)
2) Tìm x biết
\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{x.\left(x+1\right)}\) ; \(3^{x+1}+3^{x+3}=810\)
MN ƠI ! GIÚP MIK VS > . <
Bài 1:
a) Ta có: \(\dfrac{7^4\cdot3-7^3}{7^4\cdot6-7^3\cdot2}\)
\(=\dfrac{7^3\cdot\left(7\cdot3-1\right)}{7^3\cdot2\left(7\cdot3-1\right)}\)
\(=\dfrac{1}{2}\)
c) Ta có: \(E=1+\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{100}}\)
\(\Leftrightarrow\dfrac{1}{3}\cdot E=\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{101}}\)
\(\Leftrightarrow E-\dfrac{1}{3}\cdot E=1+\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{100}}-\left(\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{101}}\right)\)
\(\Leftrightarrow E\cdot\dfrac{2}{3}=1-\dfrac{1}{3^{101}}\)
\(\Leftrightarrow E=\dfrac{3-\dfrac{3}{3^{101}}}{2}=\dfrac{1-\dfrac{1}{3^{100}}}{2}\)
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Thuc hien phep tinh;a/ frac{5}{15}+frac{14}{15}-frac{12}{9}+frac{2}{7}+frac{11}{25}b/ 4.frac{-1^3}{2}+frac{1}{2}c/ frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}d/ frac{2^8.9^2}{6^4.8^2}e/(9frac{3}{4}:5,2+3,4.2frac{7}{34}):(-1frac{9}{16})f/frac{frac{2^3}{3}.frac{-3^2}{4}.left(-1right)^5}{frac{2^2}{5}.frac{-5^3}{6}}
Đọc tiếp
Thuc hien phep tinh;
a/ \(\frac{5}{15}+\frac{14}{15}-\frac{12}{9}+\frac{2}{7}+\frac{11}{25}\)
b/ \(4.\frac{-1^3}{2}+\frac{1}{2}\)
c/ \(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
d/ \(\frac{2^8.9^2}{6^4.8^2}\)
e/(\(9\frac{3}{4}:5,2+3,4.2\frac{7}{34}\)):(-1\(\frac{9}{16}\))
f/\(\frac{\frac{2^3}{3}.\frac{-3^2}{4}.\left(-1\right)^5}{\frac{2^2}{5}.\frac{-5^3}{6}}\)
Tính\(\frac{10^3+5.10+5^3}{6^33.6+3^3}\)
Bài 1: Tính
\(\left(-\frac{10}{3}\right)^3\cdot\left(-\frac{6}{5}\right)^4\)
Bài 2: Rút gọn
a) \(2:\left(\frac{1}{2}-\frac{2}{3}\right)^3\)
b) \(\frac{6^3+3.6^2+3^3}{-13}\)
(-10 phần 3 )3.(-6 phần 5)4
=-1000 phần 27.-1296 phần 625
=1296000 phần 16875 bạn tự giuts gọn nhé
2:(1 phần 2 - 2 phần 3)3
=2:(3 phần 6 - 4 phần 6 )3
=2:(-1 phần 6)3
2:-1 phần 216
=2.-216
=-432
63+3.62+33 phần -13
=216+3 . 36+27 phần -13
216+108+27 phần -13
=351 phần -13
=-27
=
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1.thực hiện phép tính:
a, 24-{12-[(-10)-(-2)]}
b,2/3+1/3.(-2/3+5/6):2/3
2.tính nhanh:
a,\(-\frac{2}{5}+\left(-\frac{5}{9}+\frac{2}{5}\right)\)
b, 17/13-(4/13 - 11)
c,3/5.18/17+3/5.9/17-3/5.10/17
GIÚP IK GIÚP TUI VỚI! PLEASE
1/
a, 24 - {12 -[(-10)-(-2)]}
=24-{12-(-8)}
=24-20
=4
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b,\(\frac{2}{3}\)+\(\frac{1}{3}\).(\(\frac{-2}{3}\)+\(\frac{5}{6}\)):\(\frac{2}{3}\)
=\(\frac{2}{3}\)+\(\frac{1}{3}\).(\(\frac{-4}{6}\)+\(\frac{5}{6}\)):\(\frac{2}{3}\)
=\(\frac{2}{3}\)+\(\frac{1}{3}\).\(\frac{1}{6}\).\(\frac{3}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{18}\).\(\frac{3}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{6}\).\(\frac{1}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{12}\)
=\(\frac{8}{12}\)+\(\frac{1}{12}\)
=\(\frac{9}{12}\)=\(\frac{3}{4}\)
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2/
a,\(\frac{-2}{5}\)+(\(\frac{-5}{9}\)+\(\frac{2}{5}\))
=\(\frac{-2}{5}\)+\(\frac{-5}{9}\)+\(\frac{2}{5}\)
=(\(\frac{-2}{5}\)+\(\frac{2}{5}\))+\(\frac{-5}{9}\)
= 0+\(\frac{-5}{9}\)
= \(\frac{-5}{9}\)
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