Tính E= 2.2+ 4.3+ 6.4+.....+38. 20
\(\frac{7}{4}-\left(\frac{1}{2.2}+\frac{1}{4.3}+\frac{1}{6.4}+\frac{1}{8.5}+\frac{1}{10.6}+\frac{1}{12.7}+\frac{1}{14.8}\right):x=0\)
\(\frac{7}{4}-\left(\frac{1}{2.2}+\frac{1}{4.3}+\frac{1}{6.4}+\frac{1}{8.5}+\frac{1}{10.6}+\frac{1}{12.7}+\frac{1}{14.8}\right)\div x=0\)
\((\frac{1}{2.2}+\frac{1}{4.3}+\frac{1}{6.4}+\frac{1}{8.5}+\frac{1}{10.6}+\frac{1}{12.7}+\frac{1}{14.8})\div x=\frac{7}{4}\)
\((\frac{1}{4}+\frac{1}{12}+\frac{1}{24}+\frac{1}{40}+\frac{1}{60}+\frac{1}{84}+\frac{1}{112})\div x=\frac{7}{4}\)
\(\left[\frac{1}{2}\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\right)\right]\div x=\frac{7}{4}\)
\(\left[\frac{1}{2}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\right)\right]\div x=\frac{7}{4}\)
\(\left[\frac{1}{2}\left(1-\frac{1}{8}\right)\right]\div x=\frac{7}{4}\)
\(\left(\frac{1}{2}.\frac{7}{8}\right)\div x=\frac{7}{4}\)
\(\frac{7}{16}\div x=\frac{7}{4}\)
\(x=\frac{7}{16}\div\frac{7}{4}\)
\(x=\frac{7}{16}\times\frac{4}{7}\)
\(x=\frac{1}{4}\)
\(\frac{7}{4}-\left(\frac{1}{2\cdot2}+\frac{1}{4\cdot3}+\frac{1}{6\cdot4}+\frac{1}{8\cdot5}+\frac{1}{10\cdot6}+\frac{1}{12\cdot7}+\frac{1}{14\cdot8}\right)\)
\(=\frac{7}{4}-\left(\frac{1}{4}+\frac{1}{12}+\frac{1}{24}+\frac{1}{40}+\frac{1}{60}+\frac{1}{84}+\frac{1}{112}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\left(1-\frac{1}{8}\right)\)
\(=\frac{7}{4}-\frac{1}{2}\cdot\frac{7}{8}\)
\(=\frac{7}{4}-\frac{7}{16}=\frac{28}{16}-\frac{7}{16}=\frac{21}{16}\)
\(\frac{1}{4.3}+\frac{1}{6.4}+\frac{1}{8.5}+\frac{1}{10.6}+.....+\frac{1}{98.56}\) = ?
Tính: S= 1+2.2+3.3+4.........38+39.39+40
TÍNH KẾT QUẢ RỒI PHÂN TÍCH RA THỪA SỐ NGUYÊN TỐ
\(6^2:4.3+2.2^5\)
(3 mũ 7: 3 mũ 3+4.3 mũ 2).3-2 mũ 2.2 mũ 3
\(\left(3^7:3^3+4\cdot3^2\right)\cdot3-2^2\cdot2^3\)
\(=\left(3^4+4\cdot9\right)\cdot3-2^5\)
\(=117\cdot3-32\)
\(=351-32=319\)
\(=\left(3^4+4.3^2\right).3-2^2.2^3\\ =\left(81+4.9\right).3-2^2.2^3\\ =117.3-2^5\\ =351-2^5=319\)
Tìm giá trị của B:
B=\(\frac{15.4^{12}.9^7-4.3^{15}.8^8}{19.2^{24}.3^{14}-6.4^{12}.27^5}\)
\(B=\frac{15.4^{12}.9^7-4.3^{15}.8^8}{19.2^{24}.3^{14}-6.4^{12}.27^5}=\frac{3}{1}=3\)
a, A = 110- (-761)+296+1454-(-813+1077)
b , B = 15.4^12.9^7-4.3^15.8^8/19.2^24.3^14-6.4^12.47^5
c , C = 2^50-2^49-2^48-2^47-...-2^2-2
a) A = 110 - (-761) + 296 + 1454 - (-813 + 1077)
= 110 + 761 + 296 + 1454 - 264
= 871 + 1750 - 264
= 2631 - 264
= 2357
\(\frac{15.4^{12}.9^7-4.3^{15}.8^8}{19.2^{24}.3^{14}-6.4^{12}.27^5}\)
dấu "." là dấu nhân
giải đầy đủ hộ mình nhé
\(=\frac{3.5.\left(2^2\right)^{12}.\left(3^2\right)^7-2^2.3^{15}.\left(2^3\right)^8}{19.2^{24}.3^{14}-2.3.\left(2^2\right)^{12}.\left(3^3\right)^5}\)
\(=\frac{3.5.2^{24}.3^{14}-2^2.3^{15}.2^{24}}{19.2^{24}.3^{14}-2.3.2^{24}.3^{15}}\)
\(=\frac{5.2^{24}.3^{15}-3^{15}.2^{26}}{19.2^{24}.3^{14}-2^{25}.3^{16}}\)
\(=\frac{2^{24}.3^{15}.\left(5-2^2\right)}{2^{24}.3^{14}.\left(19-3^2\right)}\)
\(=\frac{3.1}{10}\)
\(=\frac{3}{10}\)
không thực hiện phép tính. Xét tổng (hiệu) nào dưới đây chia hết cho 5?
A.\(136.2^{10}+420.3^{17}\)
B.\(621.4^{20}-450\)
C.\(1.2.3.4.5+42.3^{35}\)
D.\(1.2.3.4.5.6-5^{100}\)
E.\(60.3^{12}+43\)
F.\(21.4^{20}-41.5^2\)
G.\(1.2.3.4.5.7+4.3^{115}\)
H.\(5.6-3^{100}\)