ta có A= 2000.(2004+3)=2000.2004+2000.3

B= 2004.2003= 2004.(2000+3)=2004.2000+2004.3

Vì 2004.2000=2000.2004 nhưng 2004.3 > 2000.3

=> B> A

Ticks cho mình nhé bạn

\(B=2020.2021.2022=\left(2021-1\right).2021.\left(2021+1\right)=\left[\left(2021-1\right)\left(2021+1\right)\right].2021=\left(2021^2-2021+2021-1\right).2021=\left(2021^2-1\right).2021=2021^3-2021< 2021^3=A\)

vậy B<A

\(B=2020.2021.2022\\ B=\left(2021-1\right).2021.\left(2021+1\right)\\ B=\left(2021^2-1\right).2021\\ B=2021^3-2021\\ \Rightarrow A>B\)

B=2020.2021.2022B=(2021−1).2021.(2021+1)B=(20212−1).2021B=20213−2021⇒A>B

Vậy a>b

Tham khảo:https://hoc24.vn/cau-hoi/cho-a-20213-va-b-202020212022-khong-tinh-cu-the-cac-gia-tri-cua-a-va-b-hay-so-sanh-a-va-b-ai-lam-giup-mik-voi.3007463332171

có sai ko bạn 

lúc mình làm xiong thấy sai

a>b, mik chắc luôn nhưng ko bt giải thích

A<B

A<B nhé

A < B 

A = B

vì

a = 5002 . 5002 = 5000.5000(2+2)= 5000 . 5000(4)

B= 5000 x 5004 = 5000 . 5000 (4)

=> a = b

tick nhé

a = 2011.2013

a = 2011.(2012+1)

a = 2011.2012 + 2011

b = 2012.2012

b = (2011+1).2012

b = 2011.2012 + 2012

Vì 2011 < 2012

=> 2011.2012 + 2011 < 2011.2012 + 2012

=> a < b

B = 2020.2021.2022

B = (2021 - 1).(2021 + 1).2021

B = (2021.2021 + 2021 - 2021 - 1).2021

B = (2021²⁰²¹-1).2021

B = 2021³ - 2021

Vậy A > B