x  = 4 => 5 = x + 1 thay vào ta có:

x^19 - (x+1).x^18+....+(x+1)x + 1886

= x^ 19 - x^19 +x^18 +...+x^2 + x +1886 = x +1886 = 4 + 1886 = 1890 

Ấn đúng hộ tơ nhe

\(a,\frac{2}{5}:\frac{6}{5}+\frac{3}{4}.\frac{12}{5}\)

=\(\frac{2}{5}.\frac{5}{6}+\frac{9}{5}\)

=\(\frac{1}{3}+\frac{9}{5}\)

=\(\frac{32}{5}\)

b)  \(\frac{17}{5}.\frac{3}{5}.\frac{17}{5}.\frac{2}{5}\)

=\(\frac{17}{5}.\left(\frac{3}{5}.\frac{2}{5}\right)\)

=\(\frac{17}{5}.\frac{6}{25}\)

=\(\frac{102}{125}\)

c)\(\frac{1}{4}+\frac{3}{4}.\frac{2}{3}-\frac{1}{2}\)

=\(\frac{1}{4}+\frac{1}{2}-\frac{1}{2}\)

=\(\frac{1}{4}\)

d)\(\frac{6}{7}+\frac{5}{8}:5\)

=\(\frac{6}{7}+\frac{5}{8}.\frac{1}{5}\)

=\(\frac{6}{7}+\frac{1}{8}\)

=\(\frac{48}{56}+\frac{7}{56}\)

=\(\frac{55}{56}\)

tk nhé bn!

a: =-29x100=-2900

b: \(=\left(215-5\cdot80+5\cdot50+60\right):53=\dfrac{125}{53}\)

a: =-29x(165-65)=-29x100=-2900

b: \(=\left[215-5\cdot30-60\right]:53=0\)

Bài 2:

\(a,\Leftrightarrow x^5-x^3+5x+a=\left(x+1\right)\cdot a\left(x\right)\)

Thay \(x=-1\Leftrightarrow-1+1-5+a=0\Leftrightarrow a=5\)

\(b,\Leftrightarrow x^4+x^3+ax-2=\left(x-2\right)\cdot b\left(x\right)\)

Thay \(x=2\Leftrightarrow16+8+2a-2=0\Leftrightarrow2a=-22\Leftrightarrow a=-11\)

Bài 1:

\(x^{19}-x-3=\left(x+1\right)\cdot a\left(x\right)+R\) với R là hằng số (do x+1 bậc 1)

Thay \(x=-1\Leftrightarrow-1+1-3=R\Leftrightarrow R=-3\)

Vậy phép chia dư -3

\(a,=15x^4-12x^3+9x^2\\ b,=-15x^3y^2+25x^2y^2-5xy^3\\ c,=5x^3-19x^2+12x\\ d,=3x^3+xy^2+5x^2y-9x^2y-3y^3-15xy^2\\ =3x^3-3y^3-14xy^2-4x^2y\)

Chọn B.

Ta có: