Phân tích đa thức thành nhân tử : 4(x2 + 15x + 50)(x2 + 18x + 72) – 3x2
Phân tích đa thức thành nhân tử : (x2 – 5x)2 – 3x2 + 15x – 18
\(\left(x^2-5x\right)^2-3x^2+15x-18\)
\(=\left(x^2-5x\right)^2-3\left(x^2-5x\right)-18\)
\(=\left(x^2-5x-6\right)\left(x^2-5x+3\right)\)
\(=\left(x^2-5x+3\right)\left(x-6\right)\left(x+1\right)\)
\(=\left(x^2-5x\right)^2-3\left(x^2-5x\right)-18\\ =\left(x^2-5x\right)^2-6\left(x^2-5x\right)+3\left(x^2-5x\right)-18\\ =\left(x^2-5x\right)\left(x^2-5x-6\right)+3\left(x^2-5x-6\right)\\ =\left(x^2-5x+3\right)\left(x^2-5x-6\right)\\ =\left(x-6\right)\left(x+1\right)\left(x^2-5x+3\right)\)
\(=x^4-10x^3+25x^2-3x^2+15x-18=x^4-10x^3+22x^2+15x-18=x^4+x^3-11x^3-11x^2+33x^2+33x-18x-18=x^3\left(x+1\right)-11x^2\left(x+1\right)+33x\left(x+1\right)-18\left(x+1\right)=\left(x+1\right)\left(x^3-11x^2+33x-18\right)=\left(x+1\right)\left(x^3-6x^2-5x^2+30x+3x-18\right)=\left(x+1\right)\left[x^2\left(x-6\right)-5x\left(x-6\right)+3\left(x-6\right)\right]=\left(x+1\right)\left(x-6\right)\left(x^2-5x\right)=\left(x+1\right)\left(x-6\right)x\left(x-5\right)\)
Phân tích đa thức sau thành nhân tử : x2(x + 4)2 – (x + 4)2 – (x2 – 1)
\(x^2\left(x+4\right)^2-\left(x+4\right)^2-\left(x^2-1\right)\\ =\left(x+4\right)^2\left(x^2-1\right)-\left(x^2-1\right)\\ =\left(x^2-1\right)\left[\left(x+4\right)^2-1\right]\\ =\left(x-1\right)\left(x+1\right)\left(x+4-1\right)\left(x+4+1\right)\\ =\left(x-1\right)\left(x+1\right)\left(x+3\right)\left(x+5\right)\)
\(= (x+4)^2(x^2-1)-(x^2-1)=[(x+4)^2-1](x^2-1)\)
\(=(x+4-1)(x+4+1)(x-1)(x+1)\)
\(=(x+3)(x+5)(x-1)(x+1)\)
\(x^2\left(x+4\right)^2-\left(x+4\right)^2-\left(x^2-1\right)\)
\(=\left(x+4\right)^2\left(x^2-1\right)-\left(x^2-1\right)\)
\(=\left(x^2-1\right)\left[\left(x+4\right)^2-1\right]\)
\(=\left(x^2-1\right)\left(x+3\right)\left(x+5\right)\)
Phân tích đa thức thành nhân tử : (1 + x2)2 – 4x(1 – x2)
(1 + x2)2 - 4x(1 - x2)
= (1 + x2)(1 + x2) - 4x(1 - x2)
= (1 + x2 - 4x)(1 + x2 - 1 + x2)
= 2x2(x2 - 4x + 1)
Ta có: \(\left(x^2+1\right)^2+4x\left(x^2-1\right)\)
\(=x^4+2x^2+1+4x^3-4x\)
\(=x^4+2x^3+2x^3+4x^2-2x^2-4x+1\)
\(=\left(x+2\right)\left(x^3+2x^2-2x\right)+1\)
Phân tích đa thức thành nhân tử : (x2 + 6x – 5)(x2 + 6x + 3) – 20
Ta có: (x2+6x-5)(x2+6x+3)-20
= [(x2+6x-1)-4][(x2+6x-1)+4]-20
= (x2+6x-1)2-16-20
= (x2+6x-1)2-36
= (x2+6x-7)(x2+6x-5)
= (x+7)(x-1)(x2+6x-5)
\(\left(x^2+6x-5\right)\left(x^2+6x+3\right)\\ =\left(x^2+6x-1\right)^2-16-20\\ =\left(x^2+6x-1\right)^2-36\\ =\left(x^2+6x-1-6\right)\left(x^2+6x-1+6\right)\\ =\left(x^2+6x-7\right)\left(x^2+6x+5\right)\\ =\left(x-1\right)\left(x+7\right)\left(x+1\right)\left(x+5\right)\)
\(\left(x^2+6x-5\right)\left(x^2+6x+3\right)-20\)
\(=\left(x^2+6x\right)^2-2\left(x^2+6x\right)-35\)
\(=\left(x^2+6x-7\right)\left(x^2+6x+5\right)\)
\(=\left(x+7\right)\left(x-1\right)\left(x+1\right)\left(x+5\right)\)
Phân tích đa thức thành nhân tử : (x2 + 5x – 3)(x2 + 5x – 5) – 15
\(\left(x^2+5x-3\right)\left(x^2+5x-5\right)-15=\left(x^2+5x-3\right)\left(x^2+5x-3-2\right)-15=\left(x^2+5x-3\right)^2-2\left(x^2+5x-3\right)+1-16=\left(x^2+5x-3-1\right)^2-4^2=\left(x^2+5x-4\right)^2-4^2=\left(x^2+5x-8\right)\left(x^2+5x\right)=x\left(x+5\right)\left(x^2+5x-8\right)\)
\(\left(x^2+5x-3\right)\left(x^2+5x-5\right)-15\)
\(=\left(x^2+5x\right)^2-8\left(x^2+5x\right)-15\)
\(=x\left(x+5\right)\left(x^2+5x-8\right)\)
Phân tích đa thức thành nhân tử: (x2 – 2x – 6)(x2 – 2x – 11) + 6
\(\left(x^2-2x-6\right)\left(x^2-2x-11\right)+6\)
\(=\left(x^2-2x\right)^2-17\left(x^2-2x\right)+66+6\)
\(=\left(x^2-2x\right)^2-17\left(x^2-2x\right)+72\)
\(=\left(x^2-2x-8\right)\left(x^2-2x-9\right)\)
\(=\left(x-4\right)\left(x+2\right)\left(x^2-2x-9\right)\)
Phân tích đa thức thành nhân tử : x2 – 3x – 15
x2-2x-15=(x2-5x)+(3x-15)=x(x-5)+3(x-5)=(x-5)(x+3)
\(x^2-3x-15=\left(x^2-2.\dfrac{3}{2}x+\dfrac{9}{4}\right)-\dfrac{69}{4}=\left(x-\dfrac{3}{2}\right)^2-\left(\dfrac{\sqrt{69}}{2}\right)^2\)
\(=\left(x-\dfrac{3}{2}-\dfrac{\sqrt{69}}{2}\right)\left(x-\dfrac{3}{2}+\dfrac{\sqrt{69}}{2}\right)\)
\(x^2-2x-15=\left(x-5\right)\left(x+3\right)\)
Phân tích đa thức thành nhân tử : x2 - 2x - 24
\(x^2-2x-24\)
\(=x^2-6x+4x-24\)
\(=x(x-6)+4(x-6)\)
\(=(x+4)(x-6)\)
\(x^2-2x-24\\ =x^2-2x+1-25\\ =\left(x-1\right)^2-5^2\\ =\left(x-1-5\right)\left(x-1+5\right)\\ =\left(x-6\right)\left(x+4\right)\)
\(x^2-2x-24=\left(x-6\right)\left(x+4\right)\)
Phân tích đa thức thành nhân tử : –x2 – 5x + 24
-x2 - 5x + 24
= -x2 + 3x - 8x + 24
= -x(x + 3) - 8(x - 3)
= (-x - 8)(x + 3)
=(3x-x2)+(24-8x)=3x(1-x)+8(1-x)=(1-x)(3x+8)
\(-x^2-5x+24\)
\(=-x^2-8x+3x+24\)
\(=\left(x+8\right)\left(-x+3\right)\)