a) => (12x-4)+(6x+15)=16

=>12x-48+6x+15=16

=>(12x+6x)-(15-48)=16

=>18x-(-33)=16

=>18x=16+(-33)

=>18x=-17

=>x=-17/18

KL

b) =>(-20x+(-40))-(12-30x)=48

=>-20x+(-40)-12+30x=48

=>(-20x+30x)+(-40-12)=48

=>10x+(-52)=48

=>10x=48-(-52)

=>10x=4

=>x=4/10

KL

a) 12( x - 4 ) + 3( 2x + 5 ) = 16

<=> 12x - 48 + 6x + 15 = 16

<=> 18x - 33 = 16

<=> 18x = 49

<=> x = 49/18

b) -10( 2x + 4 ) - 2( 6 - 15x ) = 48

<=> -20x - 40 - 12 + 30x = 48

<=> 10x - 52 = 48

<=> 10x = 100

<=> x = 10

\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)\)\(:16\frac{2}{3}=0\)

\(\Rightarrow\)\(2-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)=0\)

\(\Rightarrow\)\(5\frac{3}{8}+x-7\frac{5}{24}=2\)

\(\Rightarrow5\frac{3}{8}+x=9\frac{5}{24}\)

\(\Rightarrow x=3\frac{5}{6}\)

( Cách làm thì đúng rồi nhưng đáp án tớ ko chắc chắn )

=48/5

Trả lời

16/5:2/3.2

=24/5.2

=48/5

Hok tốt !

\(\frac{16}{5}:\frac{2}{3}.2=\frac{16}{5}.\frac{3}{2}.2=\frac{24}{5}.2=\frac{48}{5}\)

a) \(-\frac{3}{4}x+\frac{1}{6}x=1-2\frac{5}{9}\)
    \(\left(-\frac{3}{4}+\frac{1}{6}\right).x=1-\frac{23}{9}\)
                     \(-\frac{7}{12}.x=-\frac{14}{9}\)
                                  \(x=-\frac{14}{9}:\left(-\frac{7}{12}\right)\)
                                  \(x=\frac{8}{3}\)
Vậy x = ...
b) \(\left|2x-\frac{3}{8}\right|+2\frac{3}{4}=3\frac{1}{16}\)
     \(\left|2x-\frac{3}{8}\right|+\frac{11}{4}=\frac{49}{16}\)
                    \(\left|2x-\frac{3}{8}\right|=\frac{49}{16}-\frac{11}{4}\)      
                    \(\left|2x-\frac{3}{8}\right|=\frac{5}{16}\)
 \(\Rightarrow\left|2x-\frac{3}{8}\right|\in\text{{}\frac{5}{16};-\frac{5}{16}\)}
Nếu, \(2x-\frac{3}{8}=\frac{5}{16}\)
                     \(2x=\frac{11}{16}\)
                        \(x=\frac{11}{32}\)
Nếu, \(2x-\frac{3}{8}=-\frac{5}{16}\)
                     \(2x=\frac{1}{16}\)
                        \(x=\frac{1}{32}\)
Vậy \(x\in\text{{}\frac{1}{32};\frac{11}{32}\)}
                     

a) \(\sqrt{16}+\sqrt{225}.\sqrt{9}=4+15.3=4+45=49\)

b) \(\sqrt{\dfrac{10000}{400}}+\sqrt{\left(-3\right)^2}.\sqrt{6^4}=\dfrac{100}{20}+\sqrt{9}.\sqrt{36^2}=5+3.36=5+108=113\)

b. \(\sqrt{\dfrac{10000}{400}}+\sqrt{\left(-3\right)^2}.\sqrt{6^4}=\dfrac{100}{20}+3.6^2=5+3.36=5+108=113\)

Đề bài yêu cầu gì?

x+27=26-14 x+27= 12 x=12-27 x=-15 x-16=79+12 x-16=91 x= 91+16 x=107

1+1:2=1