[0,(32).1,(5)-0,2(5)]. 11/83
H = \(\left[0,\left(32\right)1,\left(5\right)-0,\left(25\right)\right]\times\dfrac{11}{83}\)
Thực hiện phép tính
[0,(32).1,(5)-0,(25)].\(\frac{11}{83}\)
=223/6723
ket qua chuan luon do ban k cho minh nha
\(\left[0,\left(32\right)\times1,\left(5\right)-0,\left(25\right)\right]\times\dfrac{11}{83}\)
\(\left[0,\left(32\right).1,\left(5\right)-0,\left(25\right)\right].\dfrac{11}{83}\)
\(=\left[\dfrac{32}{99}.\left(1+\dfrac{5}{9}\right)-\dfrac{25}{99}\right].\dfrac{11}{83}\)
\(=\left[\dfrac{32}{99}.\dfrac{14}{9}-\dfrac{25}{99}\right].\dfrac{11}{83}\)
\(=\left[\dfrac{448}{891}-\dfrac{25}{99}\right].\dfrac{11}{83}\)
\(=\dfrac{223}{891}.\dfrac{11}{83}\)
\(=\dfrac{223}{6723}\)
M=0,(32)+1,(5)-0,(25)]x11/83
bài 1: Tính giá trị biểu thức:
1) H= [0,(32) . 1,(5) - 0,(25)] . \(\dfrac{11}{83}\)
2) A= \(\dfrac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
\(H=\left[0,\left(32\right).1,\left(5\right)-0,\left(25\right)\right].\dfrac{11}{83}\)
\(\Leftrightarrow H=\left(\dfrac{32}{99}.\dfrac{14}{9}-\dfrac{25}{99}\right).\dfrac{11}{83}\)
\(\Leftrightarrow H=\left(\dfrac{448}{891}-\dfrac{25}{99}\right).\dfrac{11}{83}\)
\(\Leftrightarrow H=\left(\dfrac{448}{891}-\dfrac{225}{891}\right).\dfrac{11}{83}\)
\(\Leftrightarrow H=\dfrac{448-225}{891}.\dfrac{11}{83}\)
\(\Leftrightarrow H=\dfrac{223}{891}.\dfrac{11}{83}\)
\(\Leftrightarrow H=\dfrac{2453}{73953}\)
\(\Leftrightarrow H=\dfrac{223}{6723}\)
2) \(A=\dfrac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
\(\Leftrightarrow A=\dfrac{\dfrac{3}{6}+\dfrac{2}{6}-\dfrac{1}{6}}{\dfrac{15}{6}+\dfrac{10}{6}-\dfrac{5}{6}}\)
\(\Leftrightarrow A=\dfrac{\dfrac{3+2-1}{6}}{\dfrac{15+10-5}{6}}\)
\(\Leftrightarrow A=\dfrac{\dfrac{4}{6}}{\dfrac{20}{6}}\)
\(\Leftrightarrow A=\dfrac{4}{6}.\dfrac{6}{20}\)
\(\Leftrightarrow A=\dfrac{24}{120}\)
\(\Leftrightarrow A=\dfrac{1}{5}\)
ai kiếm tick nè: làm rõ mới dc tick nha
\(H=\left[0,\left(32\right)\cdot1,\left(5\right)-0,\left(25\right)\right]\cdot\frac{11}{83}\)
nhanh 3 tik luôn
l
H = [0,(32) . 1,(5) - 0,(25)] . \(\frac{11}{83}\)
H = \(\left(\frac{32}{99}.\frac{15}{9}-\frac{25}{99}\right).\frac{11}{83}\)
H = \(\left(\frac{160}{297}-\frac{75}{297}\right).\frac{11}{83}\)
H = \(\frac{85}{297}.\frac{11}{83}\)
H = \(\frac{85}{2241}\)
H = ( 0 . 5 . 0).11 phần 83 (mk ko bt ghi phân số)
H = 0 . 11
H = 0
Study good
Tính giá trị biểu thức :
0,5 +0,(3) - 0,1(6)
G=----------------------
2,5 +1,(6) - 0,8(3)
H= [0,(32) x 1,(5) -0,(25)] x \(\frac{11}{83}\)
LƯU Ý: ------------------------: phân số
x: dấu nhân
GIÚP MINK NHA MẤY BẠN.MINK ĐANG CẦN GẤP
Bài 2: Thực hiện phép tính:
a) 23. 5 – 10 b) 150 + 50 : 5 - 32 c) 80 – [ 83 – (12 - 32)]
a) 23 x 5 - 10
= ( 23 x 10 ) - 5
= 225
b) 150 + 50 : 5 - 32
= ( 150 + 50 ) : 5 - 32
= 200 : 5 - 32
= 40 - 32
= 8
c) 80 - ( 83 - ( 12 - 32 )
= 83 - 12 - 80 - 32
= 71 - 48
= 23
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23.5-10= 13.5
150+ 50: 5 - 32= 150+10-32
= 160-32
=128
80-[ 83 -(12 -32)]
=80 - 39
=41
[0,(32).1,(5)-0,(25)].11/43