(2x + 3)\(_{ }^{^2}\)=25
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
Toán lớp 6Tìm x
Trả lời Câu hỏi tương tự
Chưa có ai trả lời câu hỏi này,bạn hãy là người đâu tiên giúp nguyenvanhoang giải bài toán này !
1, (2x-5)62=x(2x-5)
2, x^2- 25=x(2x-5)
3, 25(x-2)^2=16(3x+1)^2
tìm x
17x – ( -16x – 37) = 2x +
-2x –3. (x – 17) = 34 – 2(-x + 25
17x + 3. ( -16x – 37) = 2x + 43 - 4x
103 -57: [-2. (2x – 1)2 – (-9)0] = -106
3x – 32 > -5x + 1
15 + 4x < 2x – 145
-3. (2x + 5) -16 < -4. (3 – 2x)
-2x + 15 < 3x – 7 < 19 – x
x + (x+1) + (x+2) + (x+3) + .... + 13 + 14 = 14
25 + 24 + 23 +...+ x + (x - 2) + (x – 3) = 25
17x + 3. ( -16x – 37) = 2x + 43 - 4x
<=>17x-48x-111=-2x+43
<=>-29x=154
<=> \(x=-\frac{154}{29}\)
-3. (2x + 5) -16 < -4. (3 – 2x)
\(\Leftrightarrow-6x-31< -12+8x.\)
\(\Leftrightarrow-14x< 19\Rightarrow x< -\frac{19}{14}\)
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Tìm x biết 2(x+3)-x^2-3x=0
x^3+27+(x+3)(x-9)=0
4x^2-25-(2x-5)(2x+7)=0
8x^3-50x=0
(2x-1)^2-25=0
Bài 3 (2 điểm): Tìm x
a) 25 – 3.(6 – x) = 22
b) [(2x – 11):3 + 1].5 = 20
c) (25 - 2x) mũ 3 : 5 - 3 mũ 2 = 4 mũ 2
d) 2.3x = 10.3 mũ12 + 8.27 mũ4
3/2X+10+3/X-5-2X/X^2-25
\(\dfrac{3}{2x+10}+\dfrac{3}{x-5}-\dfrac{2x}{x^2-25}\)
\(=\dfrac{3\left(x-5\right)}{2\left(x+5\right)\left(x-5\right)}+\dfrac{6\left(x+5\right)}{2\left(x+5\right)\left(x-5\right)}-\dfrac{4x}{2\left(x+5\right)\left(x-5\right)}\)
\(=\dfrac{3x-15+6x+30-4x}{2\left(x+5\right)\left(x-5\right)}\)
\(=\dfrac{5x+15}{2\left(x+5\right)\left(x-5\right)}\)
tìm số nguyên x
-2x-(x-17)=34-(-x+25)
17x-(16x-37)=2x+43
-2x-3(x+17)=34-2(-x+25)
17x+3(16x-37)=2x+43-14x
-2x+15<3x-7<19-x
25+24+23+.....+x+(x-2)+(x-3)
nhanh lên nha
\(-2x-\left(x-17\right)=34-\left(-x+25\right)\)
\(-2x-x+17=34+x-25\)
\(-2x-x-x=34-25-17\)
\(-4x=-8\Leftrightarrow x=2\)
\(17x-\left(16x-37\right)=2x+43\)
\(17x-16x+37=2x+43\)
\(17x-16x-2x=-37+43\)
\(-x=6\Leftrightarrow x=6\)
\(-2x-3\left(x+17\right)=34-2\left(-x+25\right)\)
\(-2x-3x-51=34+2x-50\)
\(-2x-3x-2x=34-50+51\)
\(-7x=35\Leftrightarrow x=-5\)
a) x(2x - 1) - (x - 2)(2x + 3) = 5
b) (x - 3)2 - 25 = 0
c) (x - 1) (2 - x) + (x + 3)2 = 4 - 2x
a) x(2x - 1) - (x - 2)(2x + 3) = 5
2x2 - x - 2x2 - 3x + 4x + 6 = 5
0x = -1 (vô lý)
Vậy không tìm được x
b) (x - 3)2 - 25 = 0
(x - 3)2 - 52 = 0
(x - 3 - 5)(x - 3 + 5) = 0
(x - 8)(x + 2) = 0
\(\Rightarrow\) x - 8 = 0 hoặc x + 2 = 0
*) x - 8 = 0
x = 0 + 8
x = 8
*) x + 2 = 0
x = 0 - 2
x = -2
Vậy x = 8; x = -2
c) (x - 1)(2 - x) + (x + 3)2 = 4 - 2x
2x - x2 - 2 + x + x2 + 6x + 9 = 4 - 2x
9x + 7 = 4 - 2x
9x + 2x = 4 - 7
11x = -3
x = \(\dfrac{-3}{11}\)
Vậy x = \(\dfrac{-3}{11}\)
-2x – (x – 17) = 34 – (-x + 25)
17x – ( -16x – 37) = 2x + 43
-2x –3. (x – 17) = 34 – 2(-x + 25)
17x + 3. ( -16x – 37) = 2x + 43 - 4x
{ -3x + 2.[ 45- x -3( 3x+ 7 -2x ] +4x } = 55
103 -57: [-2. (2x – 1 ) ^ 2 – (-9) ^ 0 ] = -106
1)-2x – (x – 17) = 34 – (-x + 25)
-2x-x-_17
Bài 3: Giải các phương trình sau:
a, 2x3 - 50x = 0
b, 2x (3x - 5) - (5 - 3x)
c, 9(3x - 2) = x(2 - 3x)
d, (2x - 1)2 - 25 = 0
e, 25x2 - 2 = 0
f, x2 - 25 = 6x - 9
g, 5x(x - 3) - 2x + 6 = 0
h, 3x(x - 7) - 2(x - 7) = 0
i, 7x2 - 28 = 0
j, (2x + 1) + x(2x + 1) = 0
k, (x + 2)2 - (x - 2)(x + 2) = 0
l, x3 + 5x2 - 4x - 20 = 0
m, x2 - 25 + 2(x + 5) = 0
n, x3 - 3x + 2 = 0
o, x2 - 6x + 8 = 0
p, x2 - 5x - 14 = 0
q, (x - 2)2 - (x - 3)(x + 3) = 6
r, (2x - 1)2 - (2x + 5)(2x - 5) = 18