Phân tich da thuc thanh nhan tu :
X^2-2xy+y^2+2x-2y
Bài 2 : rút gon
X^3+2x2y+xy^2 phần ( k viết dau gach ngang dc)x^2-y^2
phan tich da thuc thanh nhan tu
a) xy-y2+2x-2y
b) x2+2xy+y2-9
a, = (xy-y^2) + (2x-2y) = y(x-y) + 2.(x-y) = (x-y).(y+2)
b, = (x+y)^2 - 9 = (x+y-3).(x+y+3)
\(xy-y^2-2x-2y\)
=(xy-y).(2x-2y)
=y(x-y).2(x-y)
=(x-y).(y-2)
(x^2+x)^2+3(x^2+x)+2
x^2+2xy+y^2+2x+2y-15
phan tich da thuc thanh nhan tu
Phan tich da thuc x^2 + y^3 + 2x^2 -2cy + 2y^2 thanh nhan tu
Phân tich da thuc thanh nhan tu
\(^{x^2-2xy+y^2-2x+2y}\)
\(x^3-49x\)
\(x^2-y^2+6x+9\)
\(x^2-6x+5\)
a)x2-2xy+y2-2x+2y
=(x2-2xy+y2-2x+2y+1)-1
=(x-y-1)2-1
=(x-y-2)(x-y)
b)x3-49x
=x(x2-72)
=x(x+7)(x-7)
c)x2-y2+6x+9
=(x2+6x+9)-y2
=(x+3)2-y2
=(x-y+3)(x+y+3)
d)x2-6x+5
=x2-5x-x+5
=x(x-5)-(x-5)
=(x-1)(x-5)
phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
con bai 32, 33 neu ban tra loi duoc minh h them
phan tich da thuc thanh nhan tu
a) 7xy^2+5x^2y
b) x^2+2xy+y^2-11x-11y
a) 7xy^2+5x^2y
= xy(7y+5x)
b) x^2+2xy+y^2-11x-11y
= (x^2+2xy+y^2)-(11x+11y)
=(x+y)^2-11(x+y)
=(x+y)(x+y-11)
a) 7xy2 + 5x2y
= xy ( 7y + 5x )
b) x2 + 2xy + y2 - 11x - 11y
= ( x2 + 2xy + y2 ) - ( 11x + 11y )
= ( x + y )2 - 11 ( x + y )
= ( x + y )( x + y - 11 )
Phan tich da thuc thanh nhan tu:
1)P= 9(x+3)^2 - 4(x-2)^2
2) P= 25(2x-y)^2 - 16(x+2y)^2
1)P\(=9\left(x+3\right)^2-4\left(x-2\right)^2\)\(=\left(3x+9\right)^2-\left(2x-4\right)^2\)
\(=\left(3x+9+2x-4\right)\left(3x+9-2x+4\right)\)(hằng đẳng thức số 3)
\(=\left(5x+5\right)\left(x+13\right)\)
\(=5\left(x+1\right)\left(x+13\right)\)
2)P\(=25\left(2x-y\right)^2-16\left(x+2y\right)^2\)\(=\left(10x-5y\right)^2-\left(4x+8y\right)^2\)
\(=\left(14x+3y\right)\left(6x-13y\right)\)(tương tự câu 1)
Phan tich đa thuc thanh nhan tu
x^2+y^2-x^2y^2+xy-x-y
\(x^2+y^2-x^2y^2+xy-x-y\)\(=\left(xy-x\right)+\left(y^2-y\right)-\left(x^2y^2-x^2\right)\)
\(=x\left(y-1\right)+y\left(y-1\right)-x^2\left(y^2-1\right)\)\(=\left(y-1\right)\left[x+y-x^2\left(y+1\right)\right]\)
\(=\left(y-1\right)\left(x+y-x^2y-x^2\right)\)\(=\left(y-1\right)\left[x\left(1-x\right)+y\left(1-x^2\right)\right]\)
\(=\left(y-1\right)\left(1-x\right)\left[x+y\left(1+x\right)\right]=\left(y-1\right)\left(1-x\right)\left(xy+x+y\right)\)
phân tích cac da thuc sau thanh nhan tu:
a) x^3-2x^2 +2x -13
b) x^2y+xy +x +1
c) ax+by+ay+bx
d) x^2 -(a+b)x +ab
e) x^2y +xy^2 -x-y
f) ax^2 +ay-bx^2-by
bn post nhiều nên mình ghi đáp án thôi nhé phần nào sai đề mình cho qua
b)\(\left(x+1\right)\left(xy+1\right)\)
c)\(\left(a+b\right)\left(x+y\right)\)
d)\(\left(x-a\right)\left(x-b\right)\)
e)\(\left(x+y\right)\left(xy-1\right)\)
f)\(\left(a-b\right)\left(x^2+y\right)\)