Tìm tất cả các nguyên tố P và Q thõa mãn
\(\dfrac{46}{P}\) + \(\dfrac{46}{Q}\) = \(\dfrac{46}{P}\) . \(\dfrac{46}{Q}\)
Tìm tất cả các nguyên tố O và Q thõa mãn
\(\frac{46}{P}\)+\(\frac{46}{Q}\)=\(\frac{46}{P}\)*\(\frac{46}{Q}\)
tìm hai số nguyên tố p và q sao cho \(\dfrac{46}{p}+\dfrac{46}{q}=\dfrac{46}{p}.\dfrac{46}{q}\)
\(\dfrac{46p}{p}+\dfrac{46q}{q}=\dfrac{46p}{p}.\dfrac{46q}{q}\)
\(=\dfrac{46p+46q}{p.q}=\dfrac{46.46}{p.q}=46.\left[q+p\right]=46.46\)\(=p+q=46\)
vậy các cặp số nguyên tố thỏa mãn là:
[23,23];[3,43];[5,41];[17,29]
Tìm tất cả các số nguyên tố p,q thảo mãn đẳng thúc 46/p+46/q=46/p.46/q
Tìm tất cả các nguyên tố P và Q thỏa mãn
\(\frac{46}{P}\)+\(\frac{46}{Q}\)=\(\frac{46}{P}\)*\(\frac{46}{Q}\)
BT2: Tính nhanh:
5) \(\dfrac{15}{7}\left(\dfrac{1}{5}-\dfrac{46}{45}\right)+\dfrac{46}{45}\left(\dfrac{15}{7}-\dfrac{45}{46}\right)\)
6) \(\dfrac{43}{47}\left(\dfrac{18}{37}+\dfrac{47}{43}\right)-\dfrac{18}{37}\left(\dfrac{43}{47}+\dfrac{37}{36}\right)\)
1/Ta co :
\(\dfrac{15}{7}.\left(\dfrac{1}{5}-\dfrac{46}{45}\right)+\dfrac{46}{45}.\left(\dfrac{15}{7}-\dfrac{45}{46}\right)\)
=\(\dfrac{15}{7}.\dfrac{1}{5}-\dfrac{15}{7}.\dfrac{46}{45}+\dfrac{46}{45}.\dfrac{15}{7}-\dfrac{46}{45}.\dfrac{45}{46}\)
=\(\dfrac{15}{7}.\left(\dfrac{1}{5}-\dfrac{46}{45}+\dfrac{46}{45}\right)-1\)
=\(\dfrac{15}{7}.\dfrac{1}{5}-1\)
=\(\dfrac{3}{7}-1=\dfrac{-4}{7}\)
2/Ta co
\(\dfrac{43}{47}.\left(\dfrac{18}{37}+\dfrac{47}{43}\right)-\dfrac{18}{3}.\left(\dfrac{43}{47}+\dfrac{37}{36}\right)\)
=\(\dfrac{43}{47}.\dfrac{18}{37}+\dfrac{43}{47}.\dfrac{47}{43}-\dfrac{18}{37}.\dfrac{43}{47}+\dfrac{18}{37}.\dfrac{37}{36}\)
=\(\dfrac{18}{37}.\left(\dfrac{43}{37}-\dfrac{43}{37}+\dfrac{37}{36}\right)+1\)
=\(\dfrac{18}{37}.\dfrac{37}{36}+1\)
=\(\dfrac{1}{2}+1=\dfrac{3}{2}\)
tick cho mk nha
Cho A=\(\dfrac{1}{4}\).\(\dfrac{3}{6}\).\(\dfrac{5}{8}\). ... .\(\dfrac{43}{46}\).\(\dfrac{45}{48}\)
B =\(\dfrac{2}{5}\).\(\dfrac{4}{7}\).\(\dfrac{6}{9}\). ... .\(\dfrac{44}{47}\).\(\dfrac{46}{49}\)
a, So sánh A và B
B, Chứng minh A<\(\dfrac{1}{133}\)
help me, chiều mình đi học
P=\(\dfrac{1}{1\cdot2}\)+\(\dfrac{2}{2\cdot4}\)+\(\dfrac{3}{4\cdot7}\)+...+\(\dfrac{10}{46\cdot56}\)
\(P=\dfrac{1}{1.2}+\dfrac{2}{2.4}+\dfrac{3}{4.7}+...+\dfrac{10}{46.56}\)
\(=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{46}-\dfrac{1}{56}\)
\(=1-\dfrac{1}{56}=\dfrac{55}{56}\)
3\(\dfrac{1}{11}\) * \(\dfrac{27}{46}\) * 1\(\dfrac{6}{17}\) * 2\(\dfrac{4}{9}\) =
\(=\dfrac{34}{11}\cdot\dfrac{23}{17}\cdot\dfrac{27}{46}\cdot\dfrac{22}{9}=\dfrac{34}{17}\cdot\dfrac{23}{11}\cdot\dfrac{22}{46}\cdot\dfrac{27}{9}\)
\(=2\cdot3\cdot\dfrac{1}{2}\cdot2=6\)
\(\dfrac{x-1}{2}=\dfrac{y+3}{4}=\dfrac{z-5}{3}và5x-3y-4z=46\)