a.2014¹⁰⁰  + 2014⁹⁹

=2014⁹⁹.(2014+1)

=2014⁹⁹.2015

=> 2014¹⁰⁰  + 2014⁹⁹ chia hết cho 2015

 b.3¹⁹⁹⁴ + 3^1993  _  3¹⁹⁹² 

=3¹⁹⁹².(3²+3-1)

=3¹⁹⁹².11

=>3¹⁹⁹⁴ + 3^1993  _  3¹⁹⁹² chia hết cho 11

c. 4^{13 _} 32^{5 _} 8⁸

=(2²)¹³-(2⁵)⁵-(2³)⁸

=2²⁶-2²⁵-2²⁴

=2²⁴.(2²-2-1)

=2²⁴.5

=> 4^{13 _} 32^{5 _} 8⁸ chia hết cho 5

a)\(2014^{100}+2014^{99}=2014^{99}.\left(2014+1\right)=2014^{99}.2015⋮2015\left(\text{Đ}PCM\right)\)

b)\(3^{1994}+3^{1993}-3^{1992}=3^{1992}.\left(3^2+3-1\right)=3^{1992}.\left(9+3-1\right)=3^{1992}.11⋮11\left(\text{Đ}PCM\right)\)

c)\(4^{13}-32^5-8^8=\left(2^2\right)^{13}-\left(2^5\right)^5-\left(2^3\right)^8=2^{26}-2^{25}-2^{24}=2^{24}.\left(2^2-2-1\right)\)

Đề sai rồi bạn 2^14 luôn tận cùng chẵn =>2^14 không chia hết cho 5

Chúc bạn học tốt

a.

\(\left(0,25\right)^3\times32\)

\(=\left(0,25\right)^3\times2^5\)

\(=\left(0,25\right)^3\times2^3\times2^2\) 

\(=\left(0,25\times2\right)^3\times4\)

\(=\left(0,5\right)^3\times4\)

\(=0,125\times4\)

\(=0,5\)

b.

\(\left(-0,125\right)^3\times80^4\)

\(=\left(-0,125\right)^3\times80^3\times80\)

\(=\left(-0,125\times80\right)^3\times80\)

\(=\left(-10\right)^3\times80\)

\(=-1000\times80\)

\(=-80000\)

c.

\(3^{1994}+3^{1993}-3^{1992}\)

\(=3^{1992}\times\left(3^2+3-1\right)\)

\(=3^{1992}\times\left(9+3-1\right)\)

\(=3^{1992}\times11\)

\(\Rightarrow3^{1994}+3^{1993}-3^{1992}⋮11\)

d.

\(4^{13}+32^5-8^8\)

\(=\left(2^2\right)^{13}+\left(2^5\right)^5-\left(2^3\right)^8\)

\(=2^{26}+2^{25}-2^{24}\)

\(=2^{24}\times\left(2^2+2-1\right)\)

\(=2^{24}\times\left(4+2-1\right)\)

\(=2^{24}\times5\)

\(\Rightarrow4^{13}+32^5-8^8⋮5\)

Chúc bạn học tốt

a)   \(2010^{100}\)+   \(2010^{99}\)

=   \(2010^{99}\)\(\left(2010+1\right)\)

=   \(2010^{99}\).   \(2011\)chia hết cho 2011

Vậy ...................................

b)   \(3^{1994}\)+   \(3^{1993}\)-   \(3^{1992}\)

=   \(3^{1992}\)\(\left(3^2+3-1\right)\)

=   \(3^{1992}\).   \(11\)

Vậy .......................

c)   \(4^{13}\)+   \(32^5\)-   \(8^8\)

=   \(\left(2^2\right)^{13}\)+   \(\left(2^5\right)^5\)-   \(\left(2^3\right)^8\)

=   \(2^{26}\)-   \(2^{25}\)-   \(2^{24}\)

=   \(2^{24}\).   \(\left(2^2+2-1\right)\)

=    \(2^{24}\). \(5\)

Vậy .......................

3 cau 3 nhe

a)

\(=2010^{99}\left(2010+1\right)\)

\(=2010^{99}.2011\) 

cung thay chia het ro nhi

b)

\(=3^{1992}\left(3^2+3-1\right)\)

\(=3^{1992}.11\)

cung thay chia het ro nhi

c)

\(=\left(2^2\right)^{13}+\left(2^5\right)^5-\left(2^3\right)^8\)

\(=2^{26}+2^{25}-2^{24}\)

\(=2^{24}\left(2^2+2-1\right)\)

\(=2^{24}.5\)

cung thay chia het ro nhi

cho 3 nhe 

câu 2 là so sánh nhé các bn các bn giúp mk nhé

Minh lam cau A) thoi duoc hong