tính :
\(256+x^4\)
huhu help mk vs
help e vs
tính : \(a,\left(x+y-1\right)_{^{ }}^2\)
b , \(256-x^4\)
tính :
help e vs <3
\(256-x^4\)
\(16^2\)- \(x^{2^2}\)
=>(16-\(x^2\))(16+\(x^2\))
2^10.13+2^10.65/2^8.104
huhu ai jup mk vs
mk bt là k ai tl mà huhu
you help me !!!!!!!!!!!
= 2^10 . ( 13 + 65 ) / 2^8 . 104
= 2^10 . 78 / 2^8 . 104
= 2 . 2 . 2^8 . 78 / 2^8 . 104
= 2^8 . 312 / 104
= 3
help mk vs huhu
tìm x biết
\(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)\left(x+1\right)=27\)
\(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)\left(x+1\right)=27\)
\(\Leftrightarrow x^3+27-x\left(x^2-1\right)=27\)
\(\Leftrightarrow x^3-x^3+x=0\)
\(\Leftrightarrow x=0\)
Vậy x = 0
the rooms in this hotel aren't so comfortable as the rooms in that hotel
the rooms in that hotel .......
help mk vs huhu
*the rooms in this hotel aren't so comfortable as the rooms in that hotel
-the rooms in that hotel are more comfortable than the rooms in this hotel.
help bài 7 vs huhu
sau 3 giờ vòi chảy dc : \(\dfrac{1}{5}+\dfrac{2}{7}+\dfrac{11}{35}=\dfrac{7}{35}+\dfrac{10}{35}+\dfrac{11}{35}=\dfrac{7+10+11}{35}=\dfrac{28}{35}\left(b\text{ể}\right)\)
Vậy sau 3 giờ , vòi vẫn chưa đầy bể
Tìm x và y biết : (x+4)4+ /y-4/ =0
*Chú ý: Dấu / là dấu giá trị tuyệt đối đó nha mn
Gíup mk vs nhoa...huhu mai mk pải nộp rồi...làm đúng r mình tick cho
1+2+4+8+......+256+512
Giải giúp mk vs nha!
1+2+4+8+......+256+512
Phân tích :
1+1 = 2
2+2 =4
4+4=8
...
256+256 = 512
( Lấy 1 số cộng vs chính nó ! )
Học tốt !
Bài làm
1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512
= ( 2 + 8 ) + ( 4 + 16 ) + ( 128 + 32 ) + ( 64 + 256 ) + ( 512 + 1 )
= 10 + 20 + 160 + 320 + 513
= 1023
512 + 512=1024
tim x:
x-9/5=2.x
lam giup mk vs huhu
x - \(\frac{9}{5}\)= 2.x
x + \(\frac{-9}{5}\)= 2.x
x - x + \(\frac{-9}{5}\)= 2.x - x
\(\frac{-9}{5}\)= x
Bài làm
\(x-\frac{9}{5}=2x\Leftrightarrow-x=\frac{9}{5}\Leftrightarrow x=-\frac{9}{5}\)
@Hoc tot@