\(\frac{4}{7}x\frac{5}{6}+\frac{5}{7}x\frac{5}{6}\)

\(=\frac{5}{6}x\left(\frac{4}{7}+\frac{5}{7}\right)=\frac{5}{6}x\frac{9}{7}=\frac{45}{42}=\frac{15}{14}\)

\(\frac{1}{2}:3x\frac{1}{2}=\frac{1}{6}x\frac{1}{2}=\frac{1}{12}\)

2 - 5/6= 7/6

7/8+3/4=`13/8

2/5+3/4=23/20

7/12 - 2/7 + 1/12=8/21

12/17 - 5/17 - 4/17=3/17

a)=7/6

b)=13/8

c)=8/21

d)=3/17

                  HẾT

\(2-\frac{5}{6}=1\frac{1}{6}\)

\(\frac{7}{8}+\frac{3}{4}=1\frac{5}{8}\)

\(\frac{2}{5}+\frac{3}{4}=\frac{23}{20}\)

\(\frac{7}{12}-\frac{2}{7}+\frac{1}{12}=\frac{8}{7}\)

\(\frac{12}{17}-\frac{5}{17}-\frac{4}{17}=\frac{3}{17}\)

\(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3+2+1}{6}=\frac{6}{6}=1\)

\(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=\frac{3}{6}+\frac{2}{6}+\frac{1}{6}=\frac{6}{6}=1\)

\(\frac{1}{2}\)+\(\frac{1}{3}\)+\(\frac{1}{6}\)=\(\frac{3}{6}\)+\(\frac{2}{6}\)+\(\frac{1}{6}\)=\(\frac{5}{6}\)+\(\frac{1}{6}\)=\(\frac{6}{6}\)=1

C1: 2/3 x (4/5 x 5/6) = 2/3 x 2/3 = 4/9

C2: (2/3 x 4/5) x 5/6 = 8/15 x 5/6 = 4/9

\(\frac{2}{3}x\frac{4}{5}x\frac{5}{6}\)

\(=\frac{8}{15}x\frac{5}{6}\)

\(=\frac{4}{9}\)

Đố ai tìm được.